Monday, 24 October 2016




1. An aluminium wire when bent in square form encloses an area of 484 sq.cm. If the same aluminium wire is bent in circular form then what is the area it encloses ?

A. 616 sq.cm
B. 650 sq.cm
C. 673 sq.cm
D. 539 sq.cm
E. 462 sq.cm

2. The difference between compound interest and simple interest on a sum for 2 yrs at 20% per annum, when the interest is compounded annually is Rs 240. If the interest were compounded half yearly, the difference in two interests over same period would be ?

A. Rs 384.6
B. Rs 344.2
C. Rs 324.8
D. Rs 316.5
E. None of these

3. Out of 10 items having same cost price, 6 are sold at 10% profit and remaining at 20% profit. If all the 10 items were sold at a profit of 10%, then profit would be Rs. 80 less than the initial profit. What is the cost price of each camera ?

A. Rs 200
B. Rs 150
C. Rs 180
D. Rs 236
E. None of these

4. A bucket contains 2 red balls, 4 blue balls, and 6 white balls. Three balls are drawn at random. What is the probability that the draw contains exactly one blue ball ?

A. 5/11
B. 19/29
C. 28/55
D. 21/44
E. None of these

5. How many motor vehicle registration number plates can be formed with the digits 1, 2, 3, 4, 5 (no digits being repeated) if it is given that registration number can have 1 to 5 digits?

A.100
B.120
C.205
D.325
E.None of these

Directions(6-10): Study the following table and answer the questions that follows:

The table shows no. of employees in 5 departments - A, B,C,D and E in a company, the percentage of females in each department and the ratio of no. of males who are unmarried to married.

ibps-po-prelim-2016-day-23-q6

6. Approximately what percentage of females in department B are less than that in department C ?

A. 8%
B. 10%
C. 12%
D. 7%
E. 15%

7. How many males in department D are unmarried ?

A. 242
B. 248
C. 243
D. 252
E. 240

8. What is the difference between total no. of females in department A and no. of males in department B who are unmarried ?

A. 46
B. 42
C. 32
D. 36
E. 38

9. What is the total no. of males in department D and E ?

A. 615
B. 625
C. 600
D. 605
E. 675

10. What is the ratio of no. of unmarried males in department C to no. of married males in department B ?

A. 19:27
B. 26:29
C. 15:27
D. 13:27
E. None of these



1. Length of the square = (484)^0.5 = 22cm

Perimeter of the square = 4*22 = 88cm
Thus, length of the wire = 88cm

Now in circular form,
Circumference of the circle = 88cm
2*22*r/7 = 88

Thus, r = 14cm

Area of the circle = (22/7)*(14)^2 = 616 sq.cm

2. Difference for 2 yrs = P*20*20/100*100 = 240
Solving, we get,

P = 6000

So SI for 2 yrs = 6000*20*2/100 = 2400
Amount at compounded half yearly = 6000 [1 + 10/100]^4

Solving,we get,

Amount at compounded half yearly = 8784.6
So CI at compounded half yearly = 8784.6 – 6000 = 2784.6
So difference = 2784.6 – 2400 = Rs 384.6

3. Let CP of 1 is x, then of 6 is 6x
so SP = (110/100)* 6x = 66x/10
CP of 4 = 4x so SP = (120/100)*4x = 48x/10
total SP = 66x/10 + 48x/10 = 114x/10 = 11.4x
and total CP = 6x + 4x = 10x
so profit = 11.4x – 10x = 1.4x
if all 10 items at 10% profit, SP = (110/100)*10x = 11x
and CP = 10x so profit = x
now given that, 1.4x = x + 80
solve, x = 200, CP of each is x = 200.

4. Required Prob. = (4c1 * 8c2)/12c3 = 28/55.

5. If number is 1 digit number, Number of ways= 5.
If number is 2 digit number, Number of ways=5×4=20
If 3 digit number, Number of ways= 5×4×3= 60
If 4 digit number, Number of ways=5×4×3×2=120
If 5 digit number, Number of ways=5×4×3×2×1=120.
By adding these we get the sum as 325.

6. Females in department B = (40/100)*290 = 116
   In department C = (35/100)*360 = 126
   Required % = (126-116)/126 * 100 = 8%

7. (3/5)*(75/100)*540 = 243

8. Females in A = (20/100)*450 = 90
Males in B who come by bus = (1/3) * (60/100)*290 = 58
Difference = 90-58 = 32.

9. D + E
(75/100)*540 + (80/100)*250 = 405+200 = 605.

10. Unmarried males in department C = (4/9) * (65/100)*360 = 104
Married Males in department B = (2/3) * (60/100)*290 = 116
104 : 116 = 26 : 29.
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