IBPS RRB 2016-17 - Quant Quiz-6

Directions (Q. 1-5): In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer if:

1. x > y
2. x >  y
3. x < y
4. x < y
5. x = y or the relationship cannot be established.


1. I. x^2 – (1296)^½ = 28
    II. y^7/3 * y^2/3 – 262 = 250

2. I. 20x^2 – 31x + 12 = 0
    II. 20y^2 – y – 12 = 0

3. I. x^2 + 12 = 7x
    II. y^2 + 30 = 11y

4. I. 30x – 49√x + 20 = 0
    II. 42y – 5√y – 25 = 0

5. I. x^2 – 14x + 48 = 0

    II. y^2 – y – 30 = 0

Directions(6-10) : Find the missing number in the given series:

6. 13, 25, 48, 92, 176, _

A. 335

B. 330

C. 315

D. 336

E. None of these

7. 28, 53, 85, 124, 170, _

A. 220

B. 213

C. 243

D. 223

E. 216

8. 40, 43, 49, 58, 70, _

A. 90

B. 85

C. 75

D. 100

E.  80

9. 113, 126, 100, 139, 87, _

A. 145

B. 150

C. 152

D. 148

E. 175

10. 300, 156, 84, 48, 30, _

A. 18

B. 16

C. 15

D. 21

E. 24

                                         ANSWERS

1. 4
    x = +8, -8
    y = +8 

2. 2
    20x^2 - 15x - 16x + 12 = 0
    5x(4x-3) -4(4x-3) = 0
    (5x-4)(4x-3) = 0
    x = 4/5 , 3/4

    20y^2 + 15y - 16y - 12 = 0
    5y(4y+3) -4(4y+3) = 0
    (5y-4)(4y+3) = 0
    y = 4/5, -3/4

3. 3
    x^2 - 3x -4x + 12 = 0
    x(x-3) -4(x-3) = 0
    (x-4)(x-3) = 0
    x = 4, 3

    y^2 - 6y -5y + 30 = 0
    y(y-6) -5(y-6) = 0
    (y-5)(y-6) = 0
    y = 5, 6

4. 2
    30 x – 25  x^0.5 – 24  x^0.5 + 20 

    (5x^0.5– 4) (6x^0.5– 5) = 0

    x = 16/25, x = 25/36

    42 y – 5y^0.5– 25 = 0

    (6 y^0.5– 5) (7y^0.5 + 5) = 0

    y = 25/36, y = 25/49

5. 2

    x^2 -6x  -8x + 48 = 0
    x(x-6) -8(x-6) = 0
    (x-8)(x-6) = 0
    x = 8, 6

    y^2 - 6y + 5y - 30 = 0
    y(y-6) +5(y-6) = 0
    (y+5)(y-6) = 0
    y = -5, 6
    

6. D

7. D

8. B

9. C

10. D

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