1. In a family, father’s age is twice that of son's age. Father is 10 years older than mother. Daughter is 20 years younger than his mother and 5 years younger than his brother. What is the age of the father?
A. 52 years
B. 50 years
C. 58 years
D. 55 years
E. None of these
Sol. Le the age of father be 'x'
Then age of son will be = x/2
Age of mother will be = (x-10)
Age of daughter will be = (x-10-20) = (x-30)
Also given,
x/2 - 5 = x - 30
x = 50 yrs.
2. After replacing an old member by a new member, it was found that the average age of five members of a club is same as it was 3 years ago. The difference between the ages of the replaced and the new members is:
A. 2 years
B. 4 years
C. 8 years
D. 15 years
E. None of these
Sol. Increase in ages of five members in 3 years = 3*5 = 15 yrs
Since the avg. age remains same, therefore required difference = 15 yrs.
3. The ratio of the present age of X to that of Y is 3 : 11. Y is 12 years younger than Z. Z’s age after 7 years will be 85 years. What is the present age of X’s mother, who is 25 years older than X ?
A. 43 years
B. 67 years
C. 45 years
D. 69 years
E. None of these
Sol. Present age of Z = 85 - 7 = 78
Present age of Y = 78 - 12 = 66
Present age of X = (3/11)*66 = 18
Present age of X's mother = 18 + 25 = 43 yrs.
4. At present, Tina is eight times her daughter’s age. 8 years from now, the ratio of the ages of Tina and her daughter will be 10 : 3. What is Tina’s present age?
A. 32 years
B. 40 years
C. 36 years
D. Cannot be determined
E. None of these
Sol. Given T = 8D
where T is the age of tina
And D is the age of daughter
Also, (8D+8)/(D+8)=10/3
Solving, we get D=4
Tina's present age = 8D = 8*4 = 32 yrs.
5. The age of the father is 30 years more than the son’s age. Ten years hence, the father’s age will become three times the son’s age that time. What is the son’s present age in years?
A. Eight
B. Seven
C. Five
D. Cannot be determined
E. None of these
Sol. Let the son's present age be x yrs.
Then the father's present age is (x+30) yrs.
Father's age after 10 yrs = (x+40) yrs
Son's age after 10 yrs = (x+10) yrs
According to the question:
(x+40)=3(x+10)
x = 5 yrs
Directions(6-10): Find the missing number in the given series:
6. 4, 2, 8, -4, 16, _
A. -10
B. -12
C. -14
D. -8
E. None of these
Sol. 4 - (1*2) = 2
2 + (2*3) = 8
8 - (3*4) =-4
-4 + (4*5) =16
16 - (5*6) =-14
7. 1, 6, 9, 44, 85, _
A. 146
B. 136
C. 126
D. 116
E. 156
Sol. 1 + (1^2 + 2^2) = 6
6 + (2^2 + 3^2) = 19
19 + (3^2 + 4^2) = 44
44 + (4^2 + 5^2) = 85
85 + (5^2 + 6^2) = 146
8. 36, 202, 44, 290, _
A. 52
B. 42
C. 48
D. 50
E. 56
Sol. 10^2 - 8^2 = 36
11^2 + 9^2 = 202
12^2 - 10^2 = 44
13^2 + 11^2 = 290
14^2 - 12^2 = 52
9. 9 16 44 107 ?
A. 362
B. 288
C. 282
D. 364
E. None of these
Sol. 9 + 2³ – 1 = 16
16 + 3³ + 1 = 44
44 + 4³ – 1 = 107; 107 + 5³ + 1 = 233
10. 13 17 33 97 ? 1377
A. 332
B. 353
C. 388
D. 396
E. 340
E. 233
Sol. 13 + 2² = 17; 17 + 4² = 33; 33 + 8² = 97….
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