SBI PO Prelims - Day-23 (Data Interpretation)

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We have introduced  "the 45 days study plan to crack SBI PO Prelims Exam 2017". This plan is specifically dedicated to Quantitative Aptitude, English Language & Reasoning  and cover all types of questions asked in Bank PO exams. This will help you to prepare in a more efficient and systematic way. So, follow this post to keep updated with the plan.

Directions (1-5): A total of 39 thousand students appeared in an entrance examination from six cities, in which the number of boys was 12000. The following pie-charts show the distribution of the total students and of the total boys from these cities who appeared in the exam.

  

Q1. What is the total number of girls who appeared from City A?

(a) 3210 

(b) 3440 

(c) 3650 

(d) 3870 

(e) 3900

Q2. What is the difference between the total number of boys and the total number of girls who appeared in the exam from City E?

(a) 1725 

(b) 1750 

(c) 1775 

(d) 1800 

(e) 1825

Q3. The total number of girls who appeared from City C is approximately what per cent of the total number of students who appeared from City D?

(a) 45% 

(b) 49% 

(c) 54% 

(d) 57% 

(e) 60%

Q4. What is the difference between the total number of boys who appeared from City A and that from City B?

(a) 320 

(b) 330 

(c) 340

(d) 350 

(e) 360

Q5. The number of girls who appeared from City F is approximately what per cent of the total number of girls who appeared from all six cities together?

(a) 31.5% 

(b) 32.5% 

(c) 33.5% 

(d) 34.5% 

(e) 35.5%

Directions (6-10): In each of the following questions, a number series is given. After the series, below it, a number alongwith (a), (b), (c), (d) and (e) is given. You have to complete the series following the same sequence as that of the given series. Then answer the question that follows.

Q6. 2 3 10 29 172 885

1 (a) (b) (c) (d) (e)

What will come in place of (b) ?

(a) 11 

(b) 7

(c) 9 

(d) 8

(e) None of these

Q7. 5 7 10 36 136 690

2 (a) (b) (c) (d) (e)

What will come in place of (e) ?

(a) 310 

(b) 330

(c) 110 

(d) 64

(e) None of these

Q8. 8 4 6 15 52.5 236.25

4 (a) (b) (c) (d) (e)

Which of the following will come in place of (d) ?

(a) 36.25 

(b) 33.25

(c) 26.25 

(d) 32.75

(e) None of these

Q9. 2 14 18 46 82 174 338

4 (a) (b) (c) (d) (e) (i)

What will come in place of (e) ?

(a) 238 

(b) 338

(c) 218 

(d) 318

(e) None of these

Q10. 1 3 7 11 21 43 85

4 (a) (b) (c) (d) (e) (f)

What will come in place of (f) ?

(a) 275 

(b) 279

(c) 277 

(d) 273

(e) None of these

Directions (11-15): What approximate value will come in place of the question mark (?) in the following questions? (You are not expected to calculate exact value.)

(a) 780 

(b) 850

(c) 680 

(d) 820

(e) 750

Q12. 88.25% of 450 = ?% of 530

(a) 70 

(b) 68

(c) 75 

(d) 80

(e) 65

(a) 680 

(b) 720

(c) 750 

(d) 620

(e) 630

Q14. 3745 ÷ 24.05 × 17.98 = ?

(a) 2860 

(b) 2800

(c) 2760 

(d) 2720

(e) 2840

Q15. 117.95 × 8.017 × 4.98 = ?

(a) 4670 

(b) 4780

(c) 4840 

(d) 4720

(e) 4800

Solutions

S1. Ans.(d)

Sol. 

S2. Ans.(a)

Sol. Total number of students from City E

S3. Ans.(b)

Sol. 

S4. Ans.(e)

Sol. 

S5. Ans.(c)

Sol. 

S6. Ans.(d)

Sol. 

S7. Ans.(b)

Sol. The series is based on the following pattern:

5 × 1 + 2 = 7

7 × 2 - 4 = 10

10 × 3 + 6 = 36

36 × 4 - 8 = 136

136 × 5 + 10 = 690

Similarly, the new series is as follows:

2 × 1 + 2 = 4 ....(a)

4 × 2 - 4 = 4 ....(b)

4 × 3 + 6 = 18 ....(c)

18 × 4 - 8 = 64 ....(d)

64 × 5 + 10 = 330 .....(e)

Therefore, the number 330 will come in place of (e).

S8. Ans.(c)

Sol. The series is based on following pattern:

8 × 0.5 = 4

4 × 1.5 = 6

6 × 2.5 = 15

15 × 3.5 = 52.6

52.5 × 4.5 = 236.25

Therefore, the number 26.25 will come in place of (d).

S9. Ans.(a)

Sol. 

S10. Ans.(c)

Sol. 

S11. Ans.(e)

Sol. ? = (32.51 + 17.45) (32.51 - 17.45)

= 49.96 × 15.06 = 752.39 ≈ 750

S13. Ans.(a)

Sol. ? = 5000 – (30 * 12 * 12) 

? = 5000 – 4320 = 680

S14. Ans.(b)

Sol. 3745 ÷ 24. × 18 = 2808.75 ≈ 2800

S15. Ans.(d)

Sol. 118*8*5 = 4720

SBI PO Recruitment 2017-18 brings a golden opportunity for every banking aspirant for the year 2017. So, we at crackbankexam give you a well prepared 45 days study plan to crack SBI PO Prelims 2017. As the tentative date for the preliminary exam is 29th April, you should start preparing from now onwards. So its the right time to start with a reliable plan. With this study plan you can cover all important topics including the new pattern questions.

Quantitative Aptitude

For quantitative aptitude, it's practice that matters for scoring well in limited time. But if you find this section difficult, start working on it with a smart plan. With this SBI PO 45 days study plan you can cover all the important topics and types of questions which can be asked in SBI PO Prelims 2017-18. With good accuracy, you’ll surely get through this section with a decent score.

Reasoning

It is important that you practice everything from puzzles to seating arrangement, from coding-decoding to syllogism with ever decreasing escape routes in reasoning section. Step by step preparation will help you develop those skills to tackle twisted questions of reasoning ability in the examination. For scoring well in SBI PO reasoning practising what is really important and it can be your game changer.

English Language

It all started with last year’s SBI recruitment’s online test and till date, this section has gone through drastic changes, the pattern and level of English Language section have completely transformed from the conventional approach to a more challenging, practical and dynamic approach. And with this study plan you will be well versed in all the new pattern questions being asked in the SBI PO exam.


Follow our SBI PO Prelims 45 days Study Plan to better your chances at the coming SBI PO 2017 EXAM. Checkout other posts from the SBI PO Prelims 45 study plan in the given below table :

SBI PO (Quadratic Equation)	SBI PO (Simplification)	SBI PO (Percentage)
SBI PO (Data Sufficiency)	SBI PO (Ratio&Proportion)	SBI PO (Profit-Loss)
SBI PO (Time&Work)	SBI PO (Inequalities)	SBI PO (Number Series)

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Simplification / DI Quiz for SBI PO 2017

Q1. In a village, the average age of n people is 42 years. But after the verification it was found that the age of a person had been considered 20 years less than the actual age, so the new average, after the correction, increased by 1. The value of n is:  

(a) 21

(b) 20

(c) 22

(d) 23

(e) Can’t be determined 

Q2. The average age of a family of 6 members 4 year ago was 25 years. Meanwhile a child was born in this family and still the average age of the whole family is same today. The present age of the child is: 

(a) 2 years

(b) 1 1/2 years

(c) 1 year

(d) 3 years

(e) Can’t be determined 

Q3. Tap A can fill a tank in 20 hours, B in 25 hours but tap C can empty a full tank in 30 hours. Starting with A, followed by B and C each tap opens alternatively for one hour period till the tank gets filled up completely. In how many hour the tank will be filled up completely?

(a) 51 11/15

(b) 52 2/3

(c) 24 4/11

(d) 37 1/7

(e) Can’t be determined 

Q4. A group of students prepared stuffed toys as part of their group activity. They spent Rs. 100 on velvet, Rs 5 on thread and needle and Rs. 27 on miscellaneous items. They made 50 toys, 50% of which were purchased by force by some senior students causing them a loss of 50%. At what % profit should they sell the remaining toys so as to gain 50% on their total cost?

(a) 100% 

(b) 150%

(c) 75% 

(d) 125% 

(e) None of these

Q5. A shopkeeper marks up his goods by 20% and then gives a discount of 20%. Besides he cheats both his supplier and customer by 100 g, i.e., he takes 1100 g from his supplier and sells only 900 g to his customer. What is his net profit percentage? 

(a) 24.5% 

(b) 17.33%

(c) 25% 

(d) 32.5%

(e) None of these

Directions (6-10): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer 

(a) If x>y

(b) If x≥y

(c) If x<y

(d) If x ≤y

(e) If x = y or no relation can be established between x and y.

Solutions (6-10):

Directions (11-15): The following table provides the percentage of marks of 6 different students in 10th standard in 6 different subjects. Every Subject is given with their Maximum Marks. Study the table carefully and answer the following Question:

Q11. What is the ratio of total marks scored by Vivek, Arunoday and Neeraj in History to the average marks scored by Arunoday, Gaurav, Sameer and Sonam in Science?

(a) 48 : 29 

(b) 29 : 48 

(c) 29 : 42

(d) 42 : 29 

(e) None of these 

Q12. What is the percentage of overall marks scored by Sameer?

(a) 70.3%

(b) 70.2%

(c) 70.4%

(d) 70.1%

(e) None of these

Q13. Find the average marks scored by these students in Computer. 

(a) 27.4

(b) 32.2

(c) 30

(d) 28.4

(e) None of these

Q14. Find the total marks scored by Sonam in all Subject together. 

(a) 330

(b) 335

(c) 327

(d) 320

(e) None of these 

Q15. Find the difference between average percentage of marks scored by all students in Hindi and that in English. 

(a) 9.33

(b) 6.33

(c) 1.33

(d) 3.33

(e) None of these 

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Simplification / DI Quiz for SBI PO 2017

Directions (1-5): In the following questions three equations numbered I, II and III are given. You have to solve all the equations either together or separately, or two together and one separately, or by any other method and

Give answer If

(a) x < y = z

(b) x < y < z

(c) x < y > z

(d) x = y > z

(e) x = y = z or if none of the above relationship is established

Q1. I. 7x + 6y + 4z = 122

II. 4x + 5y + 3z = 88

III.9x + 2y + z = 78

Q2. I. 7x + 6y = 110

II. 4x + 3y = 59

III. x + z = 15

Q3. I.  

II. 2y + 3z = 33

III.6y + 5z = 71

Q4. I. 8x + 7y = 135

II. 5x + 6y = 99

III. 9y + 8z = 121

Q5. I. (x + y)³ = 1331

II. x - y + z = 0

III. xy = 28

Directions (6-10): Study the following pie-charts carefully and answer the questions given below.

Total population of the world = 700 crore

Number of patients = 10% of the total population

 

Percentage of all the patients in various continents

 

Percentage of patients of various diseases in the world

 

Percentage of cancer patients in various continents

Q6. The number of cancer patients in Australia is what per cent of the total number of patients of heart disease in the world?

(a) 6.81% 

(b) 7.85% 

(c) 5.49% 

(d) 6.01% 

(e) 7.98%

Q7. If the number of cancer patients in South America decreases by 25%, what is the percentage decrease in total number of cancer patients in the world?

(a) 4% 

(b) 8% 

(c) 3% 

(d) 6% 

(e) 5%

Q8. What is the ratio of the total number of patients in Africa to the total number of cancer patients in Asia and North America together?

(a) 350 : 147 

(b) 360 : 347 

(c) 350 : 334 

(d) 352 : 250 

(e) None of these

Q9. If the total number of patients increases by 10% every year in Europe then what is the difference between the total number of patients in Europe after 2 years and the total number of cancer patients in South America now?

(a) 8 lakh 

(b) 9 lakh 

(c) 6 lakh 

(d) 7 lakh 

(e) 5 lakh

Q10. If the number of hepatitis patients increases by 6% and that of heart disease ones by 22%, what will be their new ratio?

(a) 1110 : 2396 

(b) 1245 : 4925 

(c) 1113 : 4697 

(d) 1346 : 3411 

(e) 1496 : 2541

Directions (11-15): What approximate value will come in place of the question mark (?) in the given questions? (You are not expected to calculate the exact value) 

(a) 1315

(b) 1365

(c) 1215

(d) 1465

(e) 1265 

(a) 285

(b) 225

(c) 345

(d) 150

(e) 185 

Q13. 899.99 ÷ 45.012 = ? - 224.488  

(a) 185 

(b) 395 

(c) 295

(d) 245 

(e) 355 

(a) 77586

(b) 77776

(c) 79566

(d) 78356

(e) 76876 

(a) 32

(b) 16

(c) 64

(d) 256

(e) 512

Solutions

S1. Ans.(a)

Sol. 7x + 6y + 4z = 122 ... (i)

4x + 5y + 3z = 88 ... (ii)

9x + 2y + z = 78 ... (iii)

By equation (iii) × 3 - equation (ii),

23x + y = 146 ...(iv)

By equation (iii) × 4 - equation (i),

29x + 2y = 190 ...(v)

By equation (iv) × 2 - equation (v)

17x = 102

 x = 6

From equation (iv),

23 × 6 + y = 146

 y = 146 - 138 = 8

From equation (iii),

9 × 6 + 2 × 8 + z = 78

54 + 16 + z = 78

 z = 78 - 70 = 8

Clearly, x < y = z

S2. Ans.(c)

Sol. By equation II × 2 - equation (I)

x = 8

From equation (I),

7 × 8 + 6y = 110

 6y = 110 - 56 = 54

y = 9

From equation (III),

8 + z =15

z = 7

Clearly, x < y > z

S3. Ans.(e)

By equation II × 3 - equation I

4z = 28

 z = 7

From equation II,

2y + 3 × 7 = 33

2y = 33 - 21 = 12

y = 6

x = y < z

S4. Ans.(d)

Sol. By equation I × 5 - II × 8

 y = 9

From equation I,

8x + 7 × 9 = 135

 8x = 135 - 63 = 72

x = 9

From equation III,

9 × 9 + 8z = 121

8z = 121 - 81 = 40

z = 5

Clearly, x = y > z

S5. Ans.(e)

Sol. (x + y)³ = 1331

ð   x + y = 11

ð   y = 11 - x

From equation III,

x (11 - x) = 28

ð  11x - x² = 28

x² - 11x + 28 = 0

x² - 7x - 4x + 28 = 0

x (x - 7) - 4 (x - 7) = 0

(x - 7) (x - 4) = 0

x = 7, 4

From equation I

y = 4, 7

From equation II

7 - 4 + z = 0 => z = -3

or, 4 - 7 + z = 0 => z = 3

S6. Ans.(a)

Sol.

S7. Ans.(c)

Sol. 

 

S8. Ans.(a)

Sol.

 

S9. Ans.(d)

Sol.

  

S10. Ans.(c)

Sol. 

 

S12. Ans.(c)

Sol. 399.15-12×13.95+ ?=(24.02)^2 

Or 400 - 12 × 14 + ? ≈ 576 

Or 400 - 168 + ? ≈ 576 

Or ? ≈ 576 - 400 + 168 

Or ? ≈ 344 ≈ 345 

S13. Ans.(d)

Sol. Here, the given expression can be written as 

900 ÷ 45 = ? - 225 

Or 20 = ? - 225 

Or ? = 225 + 20 

Or ? = 245 

S14. Ans.(c)

Sol. Here, the given expression can be rounded off as 

13×7+(85)^2×11= ? 

Or 91 + 7225 × 11 = ? 

Or 91 + 79475 = ? 

Or ? ≈ 79566 

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