Quadratic Equations Quiz for IBPS PO / SBI PO 2017

Directions (1-5): In these questions two equations numbered I and II are given. You have to solve both the equations and mark answer.

(a) X > Y

(b) X ≤ Y

(c) X < Y

(d) X ≥ Y

(e) Relationship between X and Y cannot be established

(a) X ≥ Y

(b) X ≤ Y

(c) X < Y

(d) X > Y

(e) Relationship between X and Y cannot be established

(a) X ≥ Y

(b) X > Y

(c) X ≤ Y

(d) X < Y

(e) Relationship between X and Y cannot be established

(a) X ≥ Y

(b) X > Y

(c) X ≤ Y

(d) X < Y

(e) Relationship between X and Y cannot be established

(a) X ≥ Y

(b) X < Y

(c) X > Y

(d) X ≤ Y

(e) Relationship between X and Y cannot be established

Directions (6-10): In each of these questions, two equations I and II are given. You have to solve both the equations and give answer.

(a) x < y

(b) x > y

(c) x = y

(d) x ≥ y

(e) x ≤ y or no relationship can be established between x and y

Directions (11-15): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.

(a) If x > y

(b) If x ≥ y

(c) If x < y

(d) If x ≤ y

(e) x = y or relationship cannot be established

Solutions

Important Note:

To receive the fastest updates on Bank Exams like IBPS, SBI, RBI, IPPB, etc. as well as all other ongoing as well as forthcoming exams, kindly subscribe to our website. All you have to do is enter your email in the pop-up that appears on the website when you first enter it on the home page. Once you’re subscribed, you will receive all the latest updates concerning all competitive exams.

Read More

Quadratic Equations Quiz for IBPS PO / SBI PO 2017

Directions (Q. 1–4): In each of these questions, two equations numbered I and II with variables x and y are given. You have to solve both the equations to find the value of x and y. Give answer

a) if x > y 

b) if x >= y 

c) if x < y

d) if x <= y 

e) if x = y or relationship between x and y cannot be determined.

1. 

I. x^2 + x – 20 = 0

II. y^2 + 13y + 40 = 0

1. b

I. x^2 + 5x – 4x – 20 = 0

(x – 4) (x + 5) = 0

x = 4, – 5

II. y^2 + 8y + 5y + 40 = 0

(y + 8) (y + 5) = 0

y = –8, – 5

x >= y

2. 

I. x^2 – 11x + 30 = 0

II. y^2 – 13y + 40 = 0

2. e

I. x^2 – 6x – 5x + 30 = 0

(x – 5) (x – 6) = 0

x = 5, 6

II. y^2 – 8y – 5y + 40 = 0

(y – 8) (y – 5) = 0

y = 8, 5

No relationship between ‘x’ and ‘y’ exits.

3. 

I. x^2 + 10x + 25 = 0

II. 5y^2– √60 y + 3 = 0

3. c

I. (x + 5)^2 = 0

x = –5

II. (√5y – √3)^2 = 0

y = √3/√5

y>x

4. 

I. 10x^2 – 29x – 21 = 0

II. y^2 + 13y – 68 = 0

4. e

I. 10x^2 – 35x + 6x – 21 = 0

(5x + 3) (2x – 7) = 0

x = -3/5, 7/2

II. y^2 + 17y – 4y – 68 = 0

(y – 4) (y + 17) = 0

y = 4, –17

No relationship between x and y exists.

Directions (Q. 5–7): What value should come in the place of question mark (?) in the following number series?

5. 362, 452, 550, 656, ?

a) 770 

b) 772 

c) 670 

d) 870 

e) 790

5. a

 

6. 25, 28, 26, ?, 27, 30

a) 28 

b) 32 

c) 34 

d) 29 

e) 36

6. d

7. 9, 12, 30, 99, ?

a) 406 

b) 418 

c) 408 

d) 416 

e) 424

7. c

Directions (Q. 8–10): What value should come in the place of question mark (?) in the following questions?

8. 168.781 – 112.412 – 8.409 – 1.150 = ?

a) 44.81 

b) 46.81 

c) 40.81 

d) 47.81 

e) 46.61

8. b

? = 46.81

9. 2.01*8.96 + 128.12/(2.05*1.97) = ?

a) 50 

b) 11 

c) 21 

d) 44 

e) 23

9. a

2.01*8.96 + 128.12/(2.05*1.97) = ?

Or, 2*9 + 128/(2*2) = 18 + 32 = 50 (approx.)

10. 8.5% of 160 – 0.42% of 750 = ?

a) 11.45 

b) 12.45 

c) 13.45 

d) 9.45 

e) 10.45

10. e

? = 8.5/100 * 160 - 0.42/100 * 750

= 13.6 - 3.15 = 10.45

Important Note:

To receive the fastest updates on Bank Exams like IBPS, SBI, RBI, IPPB, etc. as well as all other ongoing as well as forthcoming exams, kindly subscribe to our website. All you have to do is enter your email in the pop-up that appears on the website when you first enter it on the home page. Once you’re subscribed, you will receive all the latest updates concerning all competitive exams.

Read More

IBPS Clerk Prelims 2016-17 Quant Quiz-8

1. 45, 43, 83, 245, 975, 4869, _

A. 29207
B. 29107
C. 29217
D. 29307
E. 29407

Sol. *1 - 2, *2 - 3, *3 - 4, *4 - 5, *5 - 6, *6 - 7

2. 26.5, 22.5, 36, 92, 343, 1679, _

A. 10027
B. 10025
C. 10028
D. 10026
E. None of these

Sol. *1 - 2^2, *2 - 3^2, *3 - 4^2, *4 - 5^2, *5 - 6^2, *6 - 7^2

3. 16, 24, 60, 210, 945, _

A. 5197.5
B. 5200
C. 5215.5
D. 5205.5
E. None of these

Sol. *1.5, *2.5, *3.5, *4.5, *5.5

4. 31, 34, 71, 216, 867, _

A. 4338
B. 4348
C. 4368
D. 4388
E. None of these

Sol. *1 + 3, *2 + 3, *3 + 3, *4 + 3, *5 + 3

5. 16, 16, 40, 140, 840, _

A. 8000
B. 7980
C. 7880
D. 7780
E. None of these

Sol. *1, *2.5, *3.5, 6, *9.5

6. 12, 7, 6, 10, 19, _

A. 68.5
B. 58.5
C. 38.5
D. 28.5
E. 48.5

Sol. 12 * 0.5 + 1 = 7
7 * 1 – 1 = 6
6 * 1.5 + 1 = 10
10 * 2 – 1 = 19
19 * 2.5 + 1 = 48.5

7. 18, 20, 25, 42, _ 364

A. 106
B. 136
C. 107
D. 140
E. 104

Sol. 18 + 1² + 1= 20
20 + 2² + 1= 25
25 + 4² + 1= 42
42 + 8² + 1= 107
107 + 16² + 1= 364

8. 48, 49, 96, 291, 1160, _

A. 3835
B. 4825
C. 2815
D. 7865
E. 5805

Sol. 48 * 1 + 1 = 49
49 * 2 – 2 = 96
96 * 3 + 3 = 291
291 * 4 – 4 = 1160
1160 * 5 + 5 = 5805

9. 12, 14, 21, 49, 112, _

A. 262
B. 248
C. 238
D. 264
E. 220

Sol. 12 + 1³ + 1 = 14
14 + 2³ – 1 = 21
21 + 3³ + 1 = 49
49 + 4³ – 1 = 112
112 + 5³ + 1 = 238

10. 2, 48, 392, 1572, 3146, _

A. 6134
B. 4134
C. 3146
D. 3147
E. 8134

Sol. 2*16 + 16 = 48
48*8 + 8 = 392
392*4 + 4 = 1572
1572*2 + 2 = 3146
3146*1 + 1 = 3147 

Read More

IBPS Clerk Prelims 2016-17 Quant Quiz-7

1. 5, 8, 17, 24, 37, _

A. 48
B. 50
C. 64
D. 58
E. 60

Sol. 2^2 + 1, 3^2 – 1, 4^2 + 1, 5^2 – 1, 6^2 + 1

2. 1, 4, 11, 30, 85, _

A. 385
B. 205
C. 248
D. 125
E. 141

Sol. 3^0 + 0, 3^1 + 1, 3^2 + 2, 3^3 + 3, 3^4 + 4

3. 2, 4, 7, 12, 19, _

A. 40
B. 28
C. 26
D. 30
E. 37

Sol. Prime number addition

4. 3, 5, 13, 49, 241, _

A. 1372
B. 1441
C. 761
D. 1094
E. None of these

Sol. 3*2 – 1, 5*3 – 2, 13*4 – 3, 49*5 – 4, 241*6 – 5

5. 21, 10, 9, 12, 22, _

A. 38.5
B. 50.5
C. 52.5
D. 62.5
E. 78.5

Sol. 21*0.5 – 0.5, 10*1 – 1, 9*1.5 – 1.5, 12*2 – 2

6. Mixture A contains 75% milk and mixture B contains 90% milk. A milkman takes some mixture from mixture A and mixes it with four times the amount of mixture from mixture B. What is the percentage of milk in the new mixture ?

A. 90%
B. 75%
C. 87%
D. 84%
E. 78%

Sol. Let x from A, 4x form B
So milk from A = (75/100)*x, milk from B = (90/100)*4x
So milk in new mixture is (75x/100) + (360x/100) = 4.35x
Total mixture in third is x+4x = 5x
So % of milk is (4.35x/5x)*100

7. 5 men started the work and worked for 4 days. Now they are replaced by 12 women where 1 man can do as much work as 2 women do in 1 day. If the works gets completed in a total of 10 days, in how many days 7 women can complete the entire work ?

A. 20
B. 12
C. 16
D. 22
E. 14

Sol. Given 1 m = 2w, so 12 women = 6 men
Let 1 man do work in x days, so 1 man’s 1 day work = 1/x, so 5 men 1 day’s work = (1/x)*5
And since they did work for 4 days, so there work becomes (5/x)* 4 = 20/x
Now total work completed in 10 days, this mean that 12 women or 6 men did in (10-4) = 6 days
So similarly as above, 1 man’s 1 day work = 1/x, so 6 men 1 day’s work = (1/x)*6
And since they did work for 6 days, so there work becomes (6/x)* 6 = 36/x
So (20/x) + (36/x) = 1
Solve, x = 56
1 man do work in 56 days, so 1 woman in 2*56 days, and 7 women in (2*56)/7

8. The incomes of 2 persons A and B is in the ratio 4 : 5. Their expenditures are in the ratio 2 : 3 respectively. If both save Rs 50,000, then what is B’s income ?

A. 95000
B. 100000
C. 125000
D. 145000
E. 130000

Sol. Incomes 4x and 5x
Expenditures 2y and 3y
So 4x – 2y = 50000
And 5x – 3y = 50000
Solve both equations, x = 25,000
So B’s income = 5*25000

9. The radius of sphere is 16 cm and cost of painting its surface Rs 50 per square cm. Suppose the radius of sphere and its cost are increased by 5% and 10% respectively. What will be the percentage increase in the total cost of painting per square cm ?

A. 22.3%
B. 15.23%
C. 25.25%
D. 30.40%
E. 28.45%

Sol. Surface area of square is 4ᴨr2
Radius increases by 5%, so by successive increase formula
surface area changes by 5+5+((5*5)/100) = 10.25%
Total cost of painting = Surface area of sphere * Cost
So again by successive increase formula
change in cost of painting will be = 10.25+10+((10.25*10)/100).

10. 2 pipes A and B are such that A fills the bucket in 8 hrs and B empties the bucket in 4 hrs. If pipe A is opened first and after 2 hours B is also opened, in how much total time (in hours) will the bucket get empty ?

A. 5
B. 4
C. 3
D. 2
E. None of these

Sol. In 2 hrs, bucket filled by A is 2 * 1/8 = 1/4
After 2 hrs, bucket filled by A + B in 1 hr is 1/8 -1/4 = -1/8
This means after 2 hrs, 1/4th is full, now in next 1 hr 1/8 out of 1/4th already filled gets empty, so now 1/4 – 1/8 = 1/8 bucket is filled, in next 1 hr (A+B) empties this 1/8 too
So total 2 + 1 + 1 = 4.

Read More

IBPS Clerk Prelims 2016-17 Quant Quiz-6

1. 11, 13, 20, 48, 111, _

A. 278
B. 268
C. 237
D. 256
E. 258

Sol. 11 + 1³ + 1 = 13
     13 + 2³ – 1 = 20
     20 + 3³ + 1 = 48
     48 + 4³ – 1 = 111

2. 5, 7, 3, 11, -5, _

A. 25
B. 18
C. 30
D. 27
E. None of these

Sol. 5 + 2^1 = 7
     7 - 2^2 = 3
     3 + 2^3 = 11
    11 - 2^4 = -5
    -5 + 2^5 = 27

3. 61, 82, 124, 187, _, 376

A. 238
B. 248
C. 288
D. 271
E. None of these

Sol. 61 + (1 * 21) = 82
82 + (2 * 21) = 124
124 + (3 * 21) = 187

4. 23, 30, 46, 80, 141, _

A. 238
B. 248
C. 288
D. 271
E. None of these

Sol. 30 – 23 = 7
46 – 30 = 16
80 – 46 = 34

16 – 7 = 9
34 – 16 = 18….

5. 39, 52, 78, 117, 169, _

A. 246
B. 148
C. 188
D. 234
E. None of these

Sol. 13 * 3 = 39
13 * 4 = 52
13 * 6 = 78
13 * 9 = 117.

6. A sum of Rs. 6600 is to be divided among three brothers A, B and C in such a way that simple interest on each part at 5% per annum after 1, 2 and 3 year respectively remains equal. The share of C is more than that of A by ?

A. 2200
B. 2600
C. 3300
D. 2400
E. None of these

Sol. x*5*1/100 = y*5*2/100 = z*5*3/100
x:y:z = 5:10:15 = 1:2:3
The share of C is more than that of A by = 2/6 * 6600 = 2200.

7. The area of a square is 441 sq cm whose side is half the radius of a circle. The circumference of a circle is equal to breadth of a rectangle. If perimeter of the rectangle is 800 cm. What is the length of the rectangle ?

A. 196 
B. 186
C. 180
D. 190
E. 136

Sol. Side of the square
Radius of circle = 2 × 21 = 42 cm
Circumference of the circle = breadth of rectangle = 2 * 22/7 * 42 = 264
Let the length of rectangle = x cm.
Perimeter of rectangle = 800cm
2(x + 264) = 800
x = 400 – 264 = 136cm

8. Ramesh and Suresh wants to make 25% profit on selling good. Ramesh calculating it on cost price while Suresh on the selling price, the difference in the profits earned by both being Rs. 200 and selling price being the same in both the cases. Find out the Selling Price of both goods ?

A. 3500
B. 1600
C. 2000
D. 4000
E. None of these

Sol. Profit = 25% = 1/4
Let CP of Ramesh’s article = 4x & Profit = x; SP = 4x + x = 5x
Let CP of Suresh’s article = 4y
4y = 5x —(1)[Selling price of Ramesh’s article = Cost Price of Suresh’s article]
y – x = 200—-(2)
y = 1000; x = 800
Selling price = 5x = 4y = 4000

9. Inside a square plot a circular garden is developed which exactly fits in the square plot and the diameter of the garden is equal to the side of the square plot which is 28 meter. What is the area of the space left out in the square plot after developing the garden ?

A. 98
B. 146
C. 84
D. 168
E. None of these

Sol. Radius of the circular garden = 28 / 2 = 14
The area of garden = 22/7 * 14 * 14 = 616 sq.m
The area of square field = 28 × 28 = 784 sq.m.
Required area =784 – 616 = 168 sq.m

10. Two cars start together in the same direction from the same place. The first goes with uniform speed of 30 kmph. The second goes at a speed of 20 kmph in the first hour and increases its speed by 1/2 kmph each succeeding hours. After how many hours will the second car overtake the first, if both cars go non stop ?

A. 31
B. 41
C. 51
D. 21
E. None of these

Sol. The second car overtake the first car in x hours
Distance covered by the first car in x hours = Distance covered by the second car in x hours
10x = x/2[2a + (x-1)d] ; 10x = x/2[2*8 + (x-1)1/2]; x = 40 -31 = 9.

Read More

IBPS Clerk Prelims 2016-17 Quant Quiz-5

1. It is required to get 40% marks to pass an exam. A candidate scored 200 marks and failed by 8 marks. What were the maximum marks of that exam ?

A. 530
B. 540
C. 502
D. Can't be determined
E. None of these

Sol. 200 + 8 = 40x/100 ; where 'x' is maximum marks.
40x/100 = 208
Solving, x = 520.

2. The sum of five consecutive numbers is 190. What is the sum of the largest and the smallest number ?

A. 75
B. 77
C. 73
D. 76
E. None of these

Sol. Lets assume the numbers to be x, x+1, x+2, x+3, x+4
Now, sum = x+x+1+x+2+x+3+x+4 = 190
Solving, x = 36
Smallest number = x = 36
Largest number = x+4= 40
Sum = 36 + 40 = 76.

3. The speed of a truck is 1/3 rd the speed of a train. The train covers 1230 km in 5 hours. What is the speed of the truck ?

A. 85
B. 82
C. 86
D. 80
E. None of these

Sol. Speed of train = 1230/5 = 246 km/hr
Speed of truck = (1/3)*246 = 82 km/hr

4. What is the value of three fourth of sixty per cent of 480 ?

A. 216
B. 218
C. 224
D. 226
E. None of these

Sol. Value = (3/4)*(60*480/100) = 216.

5. If a number is multiplied by three-fourth of itself, the value thus obtained is 10800. What is that number ?

A. 150
B. 140
C. 120
D. 180
E. None of these

Sol. Lets assume the number to be 'x'.
According to the question,
(3x/4)*x = 10800
x^2 = 10800*4/3
x = 120.

6. A train crossed a platform in 43 seconds. The length of the train is 170 metres. What is the speed of the train ?

A. 233 km/hr
B. 265 km/hr
C. 216 km/hr
D. Can't be determined
E. None of these

Sol. As length of the platform not given.
Therefore, can't be determined.

7. 4, 6, 15, 56, 275, _

A. 1644
B. 1500
C. 1426
D. 1826
E. None of these

Sol. 4*2 - 2 = 6    
     6*3 - 3 = 15
    15*4 - 4 = 56
    56*5 - 5 = 275
   275*6 - 6 = 1644

8. 4, 6, 10, 18, 34, _

A. 64
B. 66
C. 62
D. 68
E. None of these

Sol. 4 + 2^1 = 6
     6 + 2^2 = 10
    10 + 2^3 = 18
    18 + 2^4 = 34
    34 + 2^5 = 66

9. 5, 11, 21, 43, 85, _

A. 175
B. 171
C. 172
D. 171
E. None of these

Sol. 5*2 + 1 = 11
    11*2 - 1 = 21
    21*2 + 1 = 43
    43*2 - 1 = 85
    85*2 + 1 = 171

10. 1, 3, 9, 21, 41, _

A. 76
B. 72
C. 74
D. 78
E. None of these

Sol. 1 + 1*2 = 3
     3 + 2*3 = 9
     9 + 3*4 = 21
    21 + 4*5 = 41
    41 + 5*6 = 71

Read More

IBPS Clerk Prelims 2016-17 Quant Quiz-4

1. 3, 8, 15, 24, 35, _

A. 47
B. 48
C. 49
D. 50
E. None of these

Sol. 1*2 + 1 = 3
     2*3 + 2 = 8
     3*4 + 3 = 15
     4*5 + 4 = 24
     5*6 + 5 = 35
     6*7 + 6 = 48

2. 2, 3, 10, 15, 26, _

A. 36
B. 35
C. 34
D. 32
E. None of these

Sol. 1^2 + 1 = 2
     2^2 - 1 = 3
     3^2 + 1 = 10
     4^2 - 1 = 15
     5^2 + 1 = 26
     6^2 - 1 = 35

3. 5, 11, 19, 29, 41, _

A. 46
B. 48
C. 55
D. 57
E. None of these

Sol. 1 + 2^2 = 5
     2 + 3^2 = 11
     3 + 4^2 = 19
     4 + 5^2 = 29
     5 + 6^2 = 41
     6 + 7^2 = 55

4. 6, 12, 18, 24, 30, _

A. 34
B. 35
C. 36
D. 38
E. None of these

Sol. 5*1 + 1 = 6
     5*2 + 2 = 12
     5*3 + 3 = 18
     5*4 + 4 = 24
     5*5 + 5 = 30
     5*6 + 6 = 36

5. 6, 10, 4, 12, 2, _

A. 16
B. 15
C. 14
D. 18
E. None of these

Sol. 8 - 2*1 = 6
     6 + 2*2 = 10
    10 - 2*3 = 4
     4 + 2*4 = 12
    12 - 2*5 = 2
     2 + 2*6 = 14

6. There are 2 schemes A and B, both have 12% interest rate. A person invests in them in the ratio of 3:4. After 3 years, the difference between interest from A and interest from B is Rs 360, calculate the amount invested in scheme A ?

A. 4000
B. 3000
C. 2000
D. 1000
E. None of these

Sol. Lets assume investment by A to be '3x'.
Assume invested by B to be '4x'.

S.I. from A = (3x*3*12)/100 = 1.08x
S.I. from B = (4x*3*12)/100 = 1.44x

Difference = 1.44x - 1.08x = 0.36x
Thus, 0.36x = 360
x = Rs 1000

Investment by A = 3*1000 = Rs 3000.

7. The height of 5 boys is recorded as, 146 cm, 154 cm, 164 cm, 148 cm and 158 cm. What is the average height of all these boys ?

A. 158
B. 156
C. 154
D. 152
E. None of these

Sol. Average height = (146=154+164+148+158)/5 = 154.

8. Pravin purchased 25 kg of rice at the rate of Rs 45 per kg and 12 kg of pulses at the rate of Rs 28 per kg. What is the total amount that he paid to the shopkeeper ?

A. 1461
B. 1416
C. 1561
D. 1516
E. None of these

Sol. Total amount paid = 25*45 + 12*28 = Rs 1461.

9. The perimeter of a rectangle is 60 cm and its breadth is 12 cm. What is the area of the rectangle ?

A. 220
B. 240
C. 180
D. 216
E. None of these

Sol. Perimeter = 2(l+b)
As given, 2(l+b) = 60
Also given, b = 12
Thus, 2(l+12) = 60
l = 18
Area = 18*12 = 216.

10. If the three fourth of a number is subtracted from the number; the value so obtained is 163. What is that number ?

A. 652
B. 556
C. 672
D. 572
E. None of these

Sol. x - 3x/4 = 163
x/4 = 163
x = 652.

Read More

IBPS Clerk Prelims 2016-17 Quant Quiz-3

1. The CP of two dozen mangoes is Rs 32 , after selling 18 mangoes at 12 Rs per dozen ,the shopkeeper reduced the rate as Rs 4 per dozen. Then find the loss percentage ?

(a) 15
(b) 20
(c) 25
(d) 37.5
(e) None of these

Sol. Total CP = 32
Total SP = 12 + 6 + 2 = 20
∴ Loss percentage = (12/32)×100 = 37.5%

2. A man takes 3 hours 45 minutes to row a boat 15 km downstream of a river and 2 hours 30 minutes to cover a distance of 5 km upstream. Find the speed of the current.

(a)1kmph
(b)3kmph
(c)5kmph
(d)2kmph
(e)none of these

Sol. Sol. Let downstream speed = x
Upstream speed = y
15/x = 3 + 45/60
15/x = 15/4
x = 4
5/y = 2 + 30/60
5/y = 5/2
y = 2
Speed of current = 1 kmph.      

3. Elena’s age after 15 years will be 5 times her age 5 years back, What is the present age of Elena?

(a) 10
(b) 37
(c) 35
(d) 11
(e) none of these

Sol. Let Elena’s age = x
x + 15 = 5 (x – 5)
x = 10 years.

4. If the wheel of a bicycle makes 560 revolutions in travelling 1.1 km, what is its radius? (use π=22/7)

(a) 31.25 cm
(b) 37.75 cm
(c) 35.15 cm
(d) 11.25 cm
(e) none of these

Sol. Perimeter = 1.1×1000/560

2×22/7×r = 1.1×100/56
r = 110×7/(56×22×2) = 5/16
= 31.25 cm.

5. A cistern 6 m long and 4 m wide contains water up to a breadth of 1 m 25 cm. Find the total area of the wet surface.

(a)42 m sqaure
(b)49 m sqaure
(c)52 m sqaure
(d)64 m square
(e)none of these

Sol.Total Surface Area of wet surface
= 2 (l + B) × h + lb
= 2 (6 + 4) 1.25 + 6 × 4
= 20 × 1.25 + 24
= 25 + 24
= 49 m square

6. The milk and water in two vessels A and B are in the ratio 4:3 and 2:3 respectively. In what ratio the liquids in both the vessels be mixed to obtain a new mixture in vessel c consisting half milk and half water?

(a)8 : 3
(b)7 : 5
(c)4 : 3
(d)2 : 3
(e)none of these

Sol. (1/2−2/5)=1/10(4/7−1/2)=1/14
∴ Required Ratio = 14/10
=7 : 5

7. The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs.11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?

(a)Rs. 5, Rs.7.50
(b)Rs. 8, Rs. 12
(c)Rs. 10, Rs. 16
(d)Rs. 12, Rs. 14
(e)None of these

Sol. Sum of price of the remaining two
Books = 12 × 10 – 11.75 × 8
= 26
∴ Let cost of First book be x
∴ x + 160x/100 = 26
 260x/100 = 26
 x = 10
∴ Price of second book = 10 + 6 = 16.

8. A fort has provisions for 60 days. If after 15 days 500 men strengthen them and the food lasts 40 days longer, how many men are there in the fort?

(a)3500
(b)4000
(c)6000
(d)8000
(e)None of these

Sol. Let No. of soldiers = x
60 × x = 15x + 40 (x + 500)
60x =15x + 40x + 20000
5x = 20000
x = 4000

9. A bag contains Rs 216 in the form of 1 Rs ,50 paisa &25 paisa coins in the ratio of 2:3:4.the numbers of 50 paisa coins is?

(a) 140
(b) 175
(c) 184
(d) 160
(e) none of these

Sol. 2x + 3x/2 + 4x/4 = 216
(8x + 6x + 4x)/4 = 216
18x/4 = 216
x = 48
∴ No of 50 paise coin = 48 × 3 = 144.

10. A is twice as fast as B & B is trice as fast as C. The journey covered by C in 42 min. Will be covered by B in ?

(a) 14 min
(b) 4 min
(c) 5 min
(d) 8 min
(e) 6 min

Sol. A  B  C
       6x 3x x

Ratio of their speeds = 6 : 3 : 1
Ratio of their time = 16:13:11
= 1 : 2 : 6
∴Time taken by B = 426×2
= 14 min.  

Read More

IBPS Clerk Prelims 2016-17 Quant Quiz-2 (Previous Year Questions)

Directions(1-5): Find the missing numbers in the given series:

1. 41, 42, 45, 54, 81, _

A. 158
B. 160
C. 162
D. 164
E. None of these

Sol. 41 + 3^0 = 42
     42 + 3^1 = 45
     45 + 3^2 = 54
     54 + 3^3 = 81
     81 + 3^4 = 162

2. 5, 4, 7, 20, 79, _

A. 390
B. 398
C. 394
D. 395
E. None of these

Sol. 5*1 - 1 = 4
     4*2 - 1 = 7
     7*3 - 1 = 20
    20*4 - 1 = 79
    79*5 - 1 = 394

3. 12, _, 6, 9, 18, 45

A. 12
B. 6
C. 8
D. 15
E. None of these

Sol. 12*0.5 = 6
      6*1   = 6
      6*1.5 = 9
      9*2   = 18
     18*2.5 = 45

4. 164, 84, 44, 24, 14, _

A. 12
B. 9
C. 8
D. 15
E. None of these

Sol. 164 - 80 = 84
      84 - 40 = 44
      44 - 20 = 24
      24 - 10 = 14
      14 - 5  = 9

5. 350, 334, 366, 318, _, 302

A. 376
B. 382
C. 386
D. 390
E. None of these

Sol. 350 - 16 = 334
     334 + 32 = 366
     366 - 48 = 318
     318 + 64 = 382
     382 - 80 = 302

6. Six years from now, average of mannu's age and ninnu's age will be 29 yrs. Five years ago, ratio of ahe of mannu to ageo ninnu is 11:7. What is the age of ninnu ?

A. 19
B. 20
C. 22
D. 18
E. None of these

Sol. Lets assume age of mannu to be 'x'
And age of ninnu to be 'y'

Six years from now, mannu's age = x+6 and ninnu's age = y+6
Thus, according to the question,
(x+6+y+6)/2 = 29
x + y = 46

Five years ago, mannu's age = x-5 and ninnu's age = y-5
Thus, according to the question,
(x-5)/(y-5) = 11/7
11y - 7x = 20

Now solving these equations we get,
y = 19 years.

7. There are seven positive numbers. Average of first 4 numbers is 11 and the average of last 4 numbers is 9. What is the 4th number ?

A. 16
B. 15
C. 13
D. 12
E. None of these

Sol. Sum of 1st four no.s = 11*4 = 44
     Sum of last four no.s = 8*4 = 32

Also, Sum of all seven no.s = 9*8 = 72
Thus, Fourth number = (44 + 32) - 72 = 13.

8. Two trains travel in opposite direction from the same starting point. Speeds of the 1st train is 22m/s and speed of 2nd train is 8m/s. How long will tey take to be 378 km apart ?

A. 3hours 30min
B. 3hours 45min
C. 4hours 15min
D. 3hours 35min
E. None of these.

Sol. Relative speed = 22 + 8 = 30m/s = 30*18/5 = 108 km/hr
     Relative distance = 378 km

Thus time taken will be = 378/108 = 3hours 30minutes.

9. 2/7th of a number is two less than 1/2 of another number . If the sum of the two numbers is 15, what is their product ?

A. 14
B. 54
C. 56
D. 36   
E. None of these

Sol. Lets assume the numbers are x and y.
Then, according to the question,
2x/7 = y/2 - 2
and
x + y = 15
Solving these we get,
x = 7
y = 8
Thus the product = 8*7 = 56.

10. Sum of the two positive numbers is 630. If 75% of 1st number is equal to 60% of 2nd number, then what is the larger number among the two ?

A. 280
B. 350
C. 290
D. 340
E. None of these

Sol. Lets assume the 1st number be 'x'
And the 2nd number be 'y'

According to the question,
x + y = 630
and
75x/100 = 60y/100

Solving these two we get,
x = 350
y = 280
Thus the larger number is 350. 

Read More

IBPS Clerk Prelims 2016-17 Quant Quiz-1

1. 40% of a number when added to the square of the same number, then it is increased to 4040% of itself. What is the actual number ?

A. 120
B. 400
C. 175
D. 40
E. None of these

Sol. Let the number is x.
Then, 40x/100 + x^2 = 4040x/100
x^2 - 40x = 0
Therefore, x = 0, 40

2. A person runs 1/2th of distance at 10 km/hr, the next 2/5th of distance at 8 km/hr and the rest of the distance at 6 km/hr. Find his average speed ?

A. 9
B. 8.67
C. 8.57
D. 8
E. None of these

Sol. Lets assume total distance to be 100 km.
Required Average = 100/[50/10 + 40/8 + 10/6] = 8.57 km/hr

3. A sum was put at simple interest at certain rate for 3 years. Had it been put at 5% higher rate, it would have fetched Rs 108 more. What is the sum ?

A. 360
B. 480
C. 720
D. 960
E. None of these

Sol. Let the sum be S.
108 = S*5*3/100
S = Rs 720.

4. 6 men or 10 women can reap a field in 15 days, then the number of days that 12 men and 5 women will take to reap the same field is :

A. 5
B. 6
C. 8
D. 12
E. None of these

Sol. Number of days = 15/(12/6 + 5/10) = 6 days.

5. X and Y travel the same distance at 9 km/h and 10 km/h. If X takes 20 minutes longer than Y, the distance travelled by each is :

A. 16
B. 20
C. 30
D. 24
E. 28

Sol. Let the distance is d.
d/9 = d/10 + 20/60
Solving, we get, d = 30 km.

6. If the length of a rectangular field is doubled and its breadth is halved(i.e. reduced by 50%). What is percentage change in its area ?

A. 0%
B. 10%
C. 25%
D. 33.33%
E. None of these

Sol. Let the length is 'l' and breadth is 'b'
Area = lb
New arae = 2l*0.5b = lb
Change in area = 0%

7. A dice is thrown twice, what is the probabilty that atleast one of the two throws comes up with number 5 ?

A. 11/36
B. 5/6
C. 15/36
D. 19/37
E. None of these

Sol. No. of ways that none of the dice shows 5 = 5*5 = 25
Total ways = 6*6 = 36
Atleast one of the two throws comes up with the number 5 = 36 - 25 = 11
Required Probability = 11/36.

8. Sahil is 20% less efficient than Karan. If the Karaan can do a piece of work in 24 days. The number of days required by Sahil to complete the same work alone ?

A. 20
B. 30
C. 28.8
D. Can't be determined
E. None of these

Sol. Sahil's efficiency = 4
     Karan's efficiency = 5
Number of days required by Sahil to complete alone = 5*24/4 = 30.

9. If 8 men collected 200 kg of tobacco leaves in 10 hours. How many more(in kg) of tobacco leaves will 12 men collect in 8 hours ?

A. 24 
B. 40
C. 50
D. 100
E. None of these

Sol. Let 12 men collect W kg in 8 hours then
    8*10/200 = 12*8/W
    W = 240
Extra leaves collected by 12 men = 240 - 200 = 40 kg.

10. The average age of 10 boys in a group is 20 yrs, if a new boy is also included, then the new average age of all the students increases by 1 year. The age of new boy is:

A. 21
B. 30
C. 31
D. 32
E. None of these

Sol. Age of new student = 20 + (1+10/1)*1 = 20 + 11 = 31 years. 

Read More

IBPS PO MAINS 2016 - Quant Quiz-7 (Time and Work)

1. A can complete a piece of work in 4 days. B takes double the time taken by A, C takes double that of B, and D takes double that of C to complete the same task. They are paired in groups of two each. One pair takes two-thirds the time needed by the second pair to complete the work. Which is the first pair?

(a) A and B

(b) A and C

(c) B and C

(d) A and D

(e) C and D

Sol. Work done in one day by A, B and C are 1/4,1/8,1/16 and 1/32 respectively.

Using answer choices, we note that the pair of B and C does 3/16 of work in one day; the pair of A and D does 1/4+1/32=9/32 of work in one day

Hence, A and D take 32/9 days

B and C take 16/3=32/6 days

Hence, the first pair must comprise of A and D.

2. R finishes a work in 7 days. P finishes the same job in 8 days and Q in 6 days. They take turns to finish the work. R worked on the first day, P on the second day and Q on the third and then again R and so on. Who was working on the last day when work got finished?

(a) R

(b) P

(c) Q

(d) P and Q

(e) Cannot be determined

Sol. Three day’s work = 1/7+1/8+1/6=73/168

Six day’s work = 73/84

Seventh day work = 1/7, done by R

Since 73/84+1/7=85/84 > 1, therefore, R was working on the last day.

3. Construction of a road was entrusted to a civil engineer. He has to finish the work in 124 days for which he employed 120 workers. Two-third of the work was completed in 64 days. How many workers can be reduced now without affecting the completion of the work on time?

(a) 56

(b) 64

(c) 80

(d) 24

(e) None of these

Sol. 2/3rd of the work was completed in 64 days by 120 workers.

1/3rd of the work was completed in 32 days by 120 workers.

Also 1/3rd of the work is to be completed in 60 days by (120 – x) workers, where x is the number of men reduced in order to finish the work on schedule.

So, (120 – x) × 60 = 120 ⇒ x = 56.

4. Two workers earned Rs. 225 first worked for 10 days and the second for 9 days. How much did each of them get daily if the first worker got Rs. 15 more for working 5 days than the second worker got for working 3 days?

(a) Rs. 11.70; Rs. 12.00

(b) Rs. 10.80; Rs. 13.00

(c) Rs. 11.25; Rs. 12.50

(d) Rs. 12.60; Rs. 11.00

(e) None of these

Sol. Let A got Rs. x per day and B got Rs. y per day. So, 10x + 9y = 225 and 5x = 3y + 15 ⇒ x = 10.80, y = 13.

5. Two pipes A and B can fill a tank in 20 and 30 h respectively. Both the pipes are opened to fill the tank but when the tank is 1/3 full, a leak develops in the tank. Due to this leakage one-third of the water supplied by pipes A and B goes waste. What is the total time to fill the tank if the leak if not closed ?

(a) 12 h

(b) 16 h

(c) 18 h

(d) 20 h

(e) None of these

Sol. Let us assume total work = 180 (we are not assuming it to be LCM of 20 and 30 = 60 because in that case 1/3rd of A + B will be fractional)

Time taken to fill 1/3rd of the tank = 180/ (9 + 6) = 4 h

Due to leakage, net inflow = 2/3 (9 + 6) = 10 units

Time taken to fill remaining 120 units = 12 h

So total time taken = 12 + 4 = 16 h

6. P, Q and R can do a piece of work in 16, 24 and 30 days respectively. They started the work simultaneously but P stops the work after 4 days and Q called off the work 2 days before the completion. In what time the work is finished ?

a) 100/9 days
b) 100/11 days
c) 100/7 days
d) 100/13 days
e) None of these

Sol. 4/16 + (T -2)/24 + T/30 = 1 where T is the time taken to complete the job.

       T = 100/9 days.

7. If P can do 1/3 of the work in 5 days and Q can do 1/4 of the work in 6 days, then how much money will Q get if they were paid a total of 390 rupee?

a) 120
b) 150
c) 170
d) 190
e) None of these

Sol. P can alone complete the whole  work in 15 days and Q can complete the same work alone in 24 days. So ratio of work done by them 1/15: 1/24 i.e. 8: 5
Q get = (5/13)*390 = 150.

8. A does half as much work as B in one third of the time taken by B. If together they take 20 days to finish the work then what will be the share of A if 1000 rupees is given for the whole work?

a) 400
b) 500
c) 600
d) 700
e) None of these

Sol. Let B take x days to complete the work, then A will take  = x/3 + x/3 = 2x/3 days (as half work is completed in one third of the time)
3/2x + 1/x = 1/20
X = 50. So A will complete the work in 100/3 days and B will complete the work in 50 days.
Ratio of work done by A and B – 3/100: 1/50 = 3:2
So A share = 3/5*1000 = 600.

9. A does half as much work as B does in one sixth of the time. If together they take 20 days to complete the work, then what is the time taken by A to complete the work independently.

a) 80/3 days
b) 100/3 days
c) 60/3 days
d) 140/3 days
e) None of these

Sol. Let B complete the work in X days so in one day work done by B is 1/x
as A do half work in one-sixth of the time so A will complete work in 2*x/6 = x/3 days
One day work of A and B i.e. 3/x + 1/x = 1/20. So we get x = 80
So time taken by A alone = 80/3 days.

10. A and B can do a piece of work in 20 and 25 days respectively. They began to work together but A leaves after some days and B completed the remaining work in 12 days. Number of days after which A left the job-

a) 5.7/9 days
b) 6.7/9 days
c) 7.7/9 days
d) 11.7/9 days
e) None of these

Sol. (1/20 + 1/25)*T + 12/25 = 1
We will get T = 52/9 i.e. 5.7/9 days.

Read More