IBPS PO MAINS 2016 - Quant Quiz-25 (Mixed)

1. 120, 227, 282, 345, 416, _

A. 500
B. 480
C. 495
D. 485
E. None of these

Sol. 120 + (8*6) - 1 = 227
     227 + (8*7) - 1 = 282
     282 + (8*8) - 1 = 345
     345 + (8*9) - 1 = 416
     416 + (8*10) - 1 = 495

2. 2, 21, 138, 705, _

A. 2836
B. 2900
C. 3000
D. 2764
E. None of these

Sol. 2*7 + 1*7 = 21
    21*6 + 2*6 = 138
   138*5 + 3*5 = 705
   705*4 + 4*4 = 2836

3. 8, 5, 6.5, 11.75, 26, _

A. 70
B. 68
C. 67
D. 66
E. None of these

Sol. 8*0.5 + 1 = 5
     5*1   + 1.5 = 6.5
   6.5*1.5 + 2 = 11.75
 11.75*2   + 2.5 = 26
    26*2.5 + 3 = 68

4. 240, 182, 132, 90, 56, _

A. 24
B. 30
C. 28
D. 32
E. None of these

Sol. 16^2 - 16 = 240
     14^2 - 14 = 182
     12^2 - 12 = 132
     10^2 - 10 = 90
      8^2 -  8 = 56
      6^2 -  6 = 30

5. 441, 441, 147, 735, 105, _

A. 950
B. 800
C. 915
D. 1000
E. None of these

Sol. 441*1 = 441
     441/3 = 147
     147*5 = 735
     735/7 = 105
     105*9 = 950

6. The largest and the second largest angles of a triangle are in the ratio of 7 : 3 respectively. The smallest angle is 20% of the sum of the largest and the second largest and the second largest angles. What is the sum of the smallest and the second largest angles ?

A. 80
B. 75
C. 90
D. 85
E. None of these

Sol. Sum of 3 angles of triangle is 180
= (7x + 3x)*20/100
= 2x
Thus, 7x + 3x + 2x = 180
x =15
Sum = 5x = 5*15 = 75

7. The angles of a quadrilateral are in the ratio of 3 : 5 : 11 : 1. The smallest angle of the quadrilateral is equal to the smallest angle of the triangle. The ratio of smallest and largest angle of triangle is 1:5. What is the second largest angle of the triangle?

A. 92
B. 72
C. 62
D. 82
E. None of these

Sol. 3x + 5x + 11x + x = 360
x = 18
Smallest angle of triangle = 18
x = 18 ; 5x = 90
Second largest angle of a triangle = 180 - (18+90) = 72.

8. Ravi purchased a bike for Rs.60000/-. He sold it at a loss of 8 percent. With that money he again purchased another bike and sold it at a profit of 10 percent. What is his overall loss/profit ?

A. Loss of Rs 650/-
B. Profit of Rs 560/-
C. Loss of Rs 740/-
D. Profit of Rs 720/-
E. None of these

Sol. CP = Rs.60000
SP = 92/100 * 60000 = 55200
SP of another bike = 110/100 * 55200 = 60720
Overall Profit = 60720 – 60000 = 720

9. X and Y are two alloys of nickel and copper prepared by mixing metals in the ratio 5:7 and 7:9 respectively. If equal quantities of alloys are melted to form a third alloy Z, find the ratio of nickel and copper in Z.

A. 45:63
B. 43:53
C. 43:61
D. 41:65
E. 41:55

Sol. Ratio of Third Alloy = (5/12 + 7/16)/(7/12 + 9/16) = 41:55

10. Ramesh has two bags, “X” and “Y” that contain black and blue balls. In the Bag ‘X’ there are 6 black and 8 blue balls and in the Bag ‘Y’ there are 6 black and 6 blue balls. One ball is drawn out from any of these two bags. What is the probability that the ball drawn is blue ?

A. 15/28
B. 13/28
C. 17/28
D. 23/28
E. None of these

Sol. Total balls in X bag = 14, Total balls in Y bag = 12
X bag = 1/2(8c1/14c1) = 2/7
Y bag = 1/2(6c1/12c1) = 1/4
Required probability = 2/7 + 1/4 =15/28.

Read More

IBPS PO MAINS 2016 - Quant Quiz-24 (Mixed)

1. 13, _, 122, 371, 1107

A. 40
B. 42
C. 46
D. 44
E. None of these

Sol. 13*3 + 3 = 42
     42*3 - 4 = 122
    122*3 + 5 = 371
    371*3 - 6 = 1107.

2. 274, 137, 68, 33, 15, _

A. 5.5 
B. 4.5 
C. 5 
D. 3.5 
E. 4

Sol. (274 - 0)/2 = 137
     (137 - 1)/2 = 68
     (68 - 2)/2 = 33
     (33 - 3)/2 = 15
     (15 - 4)/2 = 5.5

3. Excluding the stoppages, the speed of a bus is 64 km/hr and including the stoppages the speed of the bus is 48km/hr. For how many minutes does the bus stop per hour?

A. 15 min 
B. 10 min 
C. 12 min 
D. 20 min 
E. 18 min

Sol. Let distance be LCM of speeds = 192 km
Time taken by bus without stoppage = 192/64 = 3hr
Time taken by bus with stoppage = 192/48 = 4hr
Bus stops in 4 hours for 60 min
Bus stops in 1 hr for 60/4
= 15 min

4. 2, 24, 108, 320, 750, _

A. 1424
B. 1512
C. 1664
D. 1024
E. None of these

Sol. (1^3)*2 = 2
     (2^3)*3 = 24
     (3^3)*4 = 108
     (4^3)*5 = 320
     (5^3)*6 = 750
     (6^3)*7 = 1512

5. The ratio of amount for two years under CI per annum and for one year under SI is 4/3, when the rate of interest is same, Find the rate of Interest ?

A. 100/3 %
B. 25 %
C. 33/2 %
D. None of these
E. Can't be determined

Sol. SI for 1 year = CI for 1 year
P(1+r/100)2 /P(1+r/100) = 4/3
1+ r/100 = 4/3
r/100 = 4/3 -1 = 1/3
r = 100/3 =

6. The sum of ages of 4 members of a family 5 years ago was 80year. Now the daughter has been married off and replaced by a daughter-in-law, the sum of their ages is 94 years. What is the difference between the ages of daughter and daughter-in-law ?

A. 6
B. 4
C. 12
D. 13
E. None of these

Sol. Present Sum of their ages with daughter = 80+20 = 100
Present Sum of their ages with daughter-in-law = 92
Difference = 100 -94 = 6 yr

7. Three pipes A , B and C can fill a tank in 8 hours , After working it at together for 2 hours , C is closed and A and B can fill the remaining part in 8 hours . How much time will C take alone to fill the tank ?

A. 28
B. 30
C. 32
D. 20
E. None of these

Sol. In 2 hour the part filled by all the three pipes = 2 X 1/8 = 1/4
Remaining part = 1 – 1/4 = 3/4, which is filled by ( A + B ) in 8 hours.
1 hour the part filled by ( A + B ) = 3/(4 x 8) = 3/32
1 hour the part filled by C alone = 1/8 – 3/32= 4-3/32 = 1/32.

8. If a river flowing at 3kmph, a boat travels at 40km upstream and then returns downstream to the starting point. If its speed in still water is 5kmph, Find the total journey time ?

A. 18
B. 20
C. 25
D. 15
E. None of these

Sol. D = t(x2-y2)/2x
40 = t(52 – 32)/2×5
400 = 16t
T = 25

9. Three pipes A , B and C can fill a tank in 8 hours , After working it at together for 2 hours , C is closed and A and B can fill the remaining part in 8 hours . How much time will C take alone to fill the tank ?

A. 28
B. 30
C. 20
D. 32
E. None of these

Sol. In 2 hour the part filled by all the three pipes = 2 X 1/8 = 1/4
Remaining part = 1 – 1/4 = 3/4, which is filled by ( A + B ) in 8 hours.
1 hour the part filled by ( A + B ) = 3/(4 x 8) = 3/32
1 hour the part filled by C alone = 1/8 – 3/32= 4-3/32 = 1/32

10. The average weight of 32 students in a class was calculated as 27kg. It was later found that the weight of two students in a class was wrongly added. The actual weight of one boy was 30kg, but it was calculated as 28kg and the weight of another boy in the class was 21 whereas it was calculated as 25kg. Find the difference between original average weight and calculated average weight ?

A. 0.2
B. 0.1
C. 0.5
D. 0.4
E. None of these

Sol. Original Avg weight = 32*27+2-4 / 32 = 862/32 = 26.9
Given = 27kg
Difference = 27 – 26.9 = 0.1kg
   

Read More

IBPS PO MAINS 2016 - Quant Quiz-23 (Mixed)

1. 1, -1, -19, -145, _

A. -893
B. -883
C. -873
D. -863
E. None of these

Sol. 1×10 - 9 = 1
     1×9 - 10 = -1
    -1×8 - 11 = -19
    -19×7 - 12 = -145
   -145×6 - 13 = -883

2. 1, 1729, 398, 1398, 669, 1181, _

A. 838
B. 738
C. 638
D. 538
E. None of these

Sol. 1 + 12^3 = 1729
  1729 - 11^3 = 398
   398 + 10^3 = 1398
  1398 - 9^3 = 669
   669 + 8^3 = 1181
  1181 - 7^3 = 838

3. 3, 5, 13, 19, 31, 41, _

A. 58
B. 57
C. 56
D. 55
E. 53

Sol. 1×2 + 1 = 3
     2×3 - 1 = 5
     3×4 + 1 = 13
     4×5 - 1 = 19
     5×6 + 1 = 31
     6×7 - 1 = 41
     7×8 + 1 = 57

4. 9, 31, 53, 141, 241, _

A. 379
B. 732
C. 436
D. 324
E. None of these

Sol. 1^2 + 2^3 = 9
     2^2 + 3^3 = 31
     3^2 + 4^3 = 53
     4^2 + 5^3 = 141
     5^2 + 6^3 = 241
     6^2 + 7^3 = 379

5. 50, 99, 295.5, 1180, 5897.5, _

A. 35380
B. 35382
C. 35384
D. 35386
E. 35388

Sol. 50×2 - 1 = 99
     99×3 - 1.5 = 295.5
  295.5×4 - 2 = 1180
   1180×5 - 2.5 = 5897.5
 5897.5×6 - 3 = 35382

6. P can do a piece of work in 10 days, Q can do the same work in 15 days. They work together for 5 days and the rest of the work is done by R in 2 days. If they get 1350rs for the whole work, how should they divide the money ?

A. Rs 675, Rs 225 & Rs 450
B. Rs 675, Rs 450 & Rs 225
C. Rs 375, Rs 450 & Rs 555
D. Rs 555, Rs 450 & Rs 375
E. None of these

Sol. Work done by P & Q in 5 days = 5*(1/10 + 1/15) = 5/6
Work remaining = 1 - 5/6 = 1/6
So C alone can do the remaining work in 2 days , hence he can complete the total work in 12 days.
Ratio of their work = 5/10 : 5/15 : 2/12 = 3:2:1
Share of wages = Rs 675, Rs 450 & Rs 225.

7. A box contains 2 dozens of banana, 75% of which are not fresh. If 5 bananas are taken out from the box at random, what is the probability that at least 3 of them are fresh ?

A. 139/1771
B. 140/1771
C. 142/1771
D. 143/1771
E. None of these

Sol. The box contains 24 bananas, out of which 75% = 18 are not fresh but 6 are fresh.
The probability that at least 3 out of 5 are fresh is as follows:
[(6c3 * 18c2) + (6c4 * 18c1) + (6c5 * 18c0)]/24c5 = 139/1771

8. Anuj invested a certain amount in two schemes A & B in the ratio of 4:5. At the end of one year, he earned total dividend of 30% on his investment. After one year, he reinvested the amount including the dividend in the ratio of 6:7 in schemes A & B again. If the amount reinvested in scheme B was 94,500 rs. What was the original amount invested in scheme B ?


A. 71,000 Rs
B. 75,000 Rs
C. 95,000 Rs
D. 60,000 Rs
E. None of these

Sol. Let the amount in scheme B in the original amount be Rs 5x.
Profit earned at the end of first year = 9x * 30/100 = 2.7x Rs
(7*11.7x)/13 = 94500
x=1500 Rs
So amount in Scheme B in original amount = 15000*5 = 75000 Rs

9. In a school the number of boys and girls are in the ratio of 4:7. If the number of boys are increased by 25% and the number of girls are increased by 15%. What will be the new ratio of number of boys to that of girls?

A. 100:131
B. 100:151
C. 100:161
D. 100:181
E. None of these 

Sol. Boys = 4x and girls = 7x
Ratio = 4x*125/100 : 7x*115/100 = 100:161

10. The ratio of two numbers is 3:4. If 3 is subtracted from both the numbers, the ratio becomes 1:2. Find the sum of the two numbers? 

A. 9
B. 10.5
C. 11.5
D. 12
E. None of these

Sol. (3x – 3)/(4x – 3) = ½
x = 1.5
sum of the numbers = 7*1.5 = 10.5

Read More