1. Ramesh bought two cows for Rs 19,5000. He sold one at a loss of 20% and the other at a profit of 15%. If the selling price of each dog is same, then the cost prices are:
A. 11,500 and 800
B. 12,000 and 7,500
C. 10,000 and 9,500
D. 10,500 and 9,000
E. None of these
Sol. Lets assume the CP of the 1st dog to be'x'.
Then the CP of 2nd dog will be (19500-x).
The SP of 1st dog = x*(1 - 20/100)
The SP of 2nd dog = (19500-x)(1 + 15/100)
Now according to the question, both are same,
x*(1 - 20/100) = (19500-x)(1 + 15/100)
Solving we get,
x = Rs 11500
CP of 2nd dog = 19500 - 11500 = Rs 8000.
2. X started a business with a capital of Rs 1,00,000. One year later, Y joined him with a capital of Rs 2,00,000. At the end of three years from the start of business, the profit earned was Rs 84,000. The share of Y in the profit exceeded the share of X by :
A. 12,000
B. 10,000
C. 9,000
D. 8,000
E. 11,000
Sol. Ratio of profit of X : Profit of Y
= 1,00,000*3:2,00,000*3
= 3:4
Let their share be 3k and 4k.
Then according to the question,
3k + 4k = 84,000
7k = 84,000
k = 12,000
Difference in their share = 4k - 3k = k
Thus, k = Rs 12,000.
3. Suresh bought a Fridge at 15% discount on its labeled price. Had he bought it at 25% discount, he would have saved Rs. 400, At what price did he buy the Fridge ?
A. 3000
B. 4500
C. 4000
D. 3400
E. None of these
Sol. Lets assume labelled price to be 'x'
Then according to the question,
(x - 0.15x) - (x - 0.25x) = 400
x = 4,000
At 15% discount,
CP = x - 0.15x = 4000 - 600 = Rs 3400.
4. A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. After what time will they again at the starting point?
A. 26 minutes and 18 seconds
B. 42 minutes and 36 seconds
C. 45 minutes
D. 46 minutes and 12 seconds
E. None of these
Sol. L.C.M. of 252, 308 and 198 = 2772.
So, A, B and C will again meet at the starting point in 2772 sec.
i.e., 46 min. 12 sec.
5. Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
A. 10
B. 15
C. 12
D. 20
E. None of these
Sol. Speed of the first train = 120/10 = 12 m/sec.
Speed of the second train =120/15= 8 m/sec.
Relative speed = (12 + 8) = 20 m/sec.
Therefore, required time =(120 + 120)/20 = 12 sec.
6. The average of three consecutive odd numbers is 12 more than one third of the first of these numbers. What is the last of the three numbers?
A. 15
B. 17
C. 19
D. Data inadequate
E. None of these
Sol. If the smallest number be x, then
(x/3) + 12 = x + 2
x + 36 = 3x + 6
3x - x = 36-6
2x = 30
x =15
Third number = 15 + 4 = 19.
7. The cost of an apple is twice that of a banana and the cost of a banana is 25% less than that of a guava. If the cost of each type of fruit increases by 10%, then the percentage increase in the cost of 4 bananas, 2 apples and 3 guavas is :
A. 10%
B. 12%
C. 16%
D. 18%
E. None of these
Sol. Let cost of a banana = m.
Then cost of an apple = 2m
Then cost of a guava = [100/(100-25)] × m
= 1.33m.
Then cost of 4 bananas, 2 apples and 3 guavas is = 4 × m + 2 × 2m + 3 × 1.33m
= 4m + 4m + 4m
= 12m
New cost of banana = m + 10 % of m
= m + 0.1m
= 1.1m
New cost of apple = 2m + 10 % of 2m
= 2m + 0.2m
= 2.2 m
New cost of guava = 1.33m + 10 % of 1.33m
= 1.33m + 0.133m
= 1.466m
Then new cost of 4 bananas, 2 apples and 3 guavas is = 4 × 1.1m + 2 × 2.2m + 3 × 1.466m
= 4.4m + 4.4m + 4.4m
= 13.2m
Increase percentage in total cost = [(New cost - old cost)/(old cost)]×100
= [(13.2m-12m)/12m]×100
= 10 %.
8. Some toffees were bought at the rate of 11 for Rs 10 and the same number at the rate of 9 for Rs 10. If the whole lot was sold at Rs 1 per toffee, then the loss or gain in the whole transaction was :
A. Loss of 1%
B. Gain of 1%
C. No loss or gain
D. Gain of 1.5%
E. None of these
Sol. Let us say we bought 99 (which is the LCM of 9 and 11) toffees at the rate of 11 for Rs 10
Hence money spent = (10/11) × 99
= Rs 90
We also bought 99 toffees at the rate of 9 for Rs 10.
Hence money spent = (10/9) × 99
= Rs 110
Total money spent to buy 99 + 99 = 198 toffees = Rs 110 + 90
= Rs 200
SP of each toffee = Rs 1
SP of 198 toffees = Rs 198
Loss incurred = Rs 200 – Rs 198
= Rs 2
Loss% = (Loss/CP) × 100
= (2/200) × 100
= 1%
9. The list price of an article is Rs. 160 and a customer buys it for Rs. 122.40 after two successive discounts. If the first discount is 10%, then second discount is:
A. 12%
B. 10%
C. 16%
D. 15%
E. None of these
Sol. The list price of an article is Rs.160.
First discount is 10%.
Selling price after first discount = 160 – 10% of 160
= 160 – 16
= 144
A customer buys it for Rs.122.40
Final selling price = 122.40
Second discount = 144 – 122.40
= Rs.21.60
Second discount % = (21.60/144) × 100
= 15%.
10. A shopkeeper allows 23% commission on his advertised price and still makes a profit of 10%. If he gains Rs. 56 on one item, his advertised price of the item, in Rs, is :
A. 780
B. 760
C. 800
D. 820
E. None of these
Sol. Let the advertised price be Rs. X.
Given, Commission percent = 23%
Selling price=X×(1-23/100)
Or, selling price = 0.77X
Given, Gain percent = 10%
And, Gain = Rs. 56
We know that, Cost price = Selling price – Gain
Cost price = 0.77X - 56
0.77X = (0.77X-56)×(1 + 10/100)
0.77X = 0.847X – 61.6
0.077X = 61.6
X = 800
Hence the advertised price is Rs. 800.
