IBPS Clerk Mains 2016-17 (Important Questions-21)

1. X borrows a sum of Rs.100,000 from a bank @ 10% p.a. compounded annually for 2 years. He then lends Rs.20,000, compounded every 8 months @ 10%, to each of his five friends for a period of two years. At the end of two years, X collects all the money from his friends and clears his debt with the bank. How much money did X make at the end of the two-year period ?

A. 12,100
B. 14,100
C. 15,100
D. 4,971
E. 13,200

Sol. The amount to be paid to bank after 2 years will be 100000 × (1.1)2 = Rs.121,000.
A 2-year period will be made up of three 8-month periods, each of which will cost each of the friends 10%.
The amount that each of the friends will pay back after 2 years will be 20000 × (1.1)3 = Rs.26620.
So, the total sum of money collected from the five friends will be 5 × 26620 = Rs.133,100.
After clearing his debt with the bank, X will have made 133100 – 121000 = Rs.12,100.


2. X lent Rs 2500 to Y for 4 years and Rs 4000 to Z for 3 years on simple interest at the same rate of interest and received Rs 4400 in all from both of them as interest. The rate of interest per annum is:

A. 25%
B. 17%
C. 22%
D. 20%
E. None of these

Sol. Let the rate of interes be R%. Then,
     (2500*R*4)/100 + (4000*R*3)/100 = 4400
     R = 4400/220 = 20%. 

3. 16 men and 12 women can complete a work in 8 days, if 20 men can complete the same work in 16 days, in how many days 16 women can complete the same piece of work ?

A. 8
B. 12
C. 10
D. 15
E. 9

Sol. Lets assume it take 'w' days for 1 women to complete the job.
Then, 16/(16*20) + 12/w = 1/8
      w = 160 days
Now for 16 women it will be, = 160/16 = 10 days.

4. If A's salary is 10,000 less than B's salary and B's salary is 15,000 less than C's salary and sum of their salaries is 65,000. Find the salary of A.

A. 15,000
B. 10,000
C. 12,000
D. 20,000
E. 5,000

Sol. Lets assume the salary of C be 'x'
Then, salary of B = x - 15,000
      salary of A = x - 25,000
Now sum of these salaries is,
x + x - 15,000 + x - 25,000 = 65,000
Solving,
x = 35,000
A's salary = 35,000 - 25,000 = 10,000.

5. The sum of the ages of P and Q is 25 yrs more than the age of R.The present age of Q is 5 yrs more than the age of R. Find the present age of P ?

A. 15
B. 20
C. 12
D. 10
E. 16

Sol. Given, P + Q = 25 + R
Also, given, Q = 5 + R
Putting the value of Q in the 1st eqn, we get,
P + 5 + R = 25 + R
P = 20 yrs.

6. In a family, father’s age is twice that of son's age. Father is 10 years older than mother. Daughter is 20 years younger than his mother and 5 years younger than his brother. What is the age of the father?  

A. 52 years 
B. 50 years 
C. 58 years 
D. 55 years 
E. None of these

Sol. Le the age of father be 'x'
Then age of son will be = x/2
Age of mother will be = (x-10)
Age of daughter will be = (x-10-20) = (x-30)
Also given,
x/2 - 5 = x - 30
x = 50 yrs.

7. After replacing an old member by a new member, it was found that the average age of five members of a club is same as it was 3 years ago. The difference between the ages of the replaced and the new members is: 

A. 2 years 
B. 4 years 
C. 8 years 
D. 15 years
E. None of these

Sol. Increase in ages of five members in 3 years = 3*5 = 15 yrs
Since the avg. age remains same, therefore required difference = 15 yrs.

8. The ratio of the present age of X to that of Y is 3 : 11. Y is 12 years younger than Z. Z’s age after 7 years will be 85 years. What is the present age of X’s mother, who is 25 years older than X ?


A. 43 years
B. 67 years 
C. 45 years 
D. 69 years 
E. None of these 

Sol. Present age of Z = 85 - 7 = 78
     Present age of Y = 78 - 12 = 66
     Present age of X = (3/11)*66 = 18
     Present age of X's mother = 18 + 25 = 43 yrs.

9. At present, Tina is eight times her daughter’s age. 8 years from now, the ratio of the ages of Tina and her daughter will be 10 : 3. What is Tina’s present age?  

A. 32 years 
B. 40 years  
C. 36 years 
D. Cannot be determined 
E. None of these

Sol. Given T = 8D
where T is the age of tina
And D is the age of daughter
Also, (8D+8)/(D+8)=10/3
Solving, we get D=4
Tina's present age = 8D = 8*4 = 32 yrs.

10. The age of the father is 30 years more than the son’s age. Ten years hence, the father’s age will become three times the son’s age that time. What is the son’s present age in years?   

A. Eight  
B. Seven 
C. Five 
D. Cannot be determined 
E. None of these 

Sol. Let the son's present age be x yrs.
Then the father's present age is (x+30) yrs.
Father's age after 10 yrs = (x+40) yrs
Son's age after 10 yrs = (x+10) yrs
According to the question:
(x+40)=3(x+10)
x = 5 yrs.


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IBPS Clerk Mains 2016-17 (Important Questions-20)

1. A bag contains 6 Black and 7 White balls. Four balls are drawn out one by one and not replaced. What is the probability that they are alternatively of different colours ?

A. 17/143
B. 21/143
C. 12/143
D. 11/143
E. None of these

Sol. Balls are picked in two manners – BWBW or WBWB
So probability = (6/13)*(7/12)*(5/11)*(6/10) + (7/13)*(6/12)*(6/11)*(5/10)
= 42/286 = 21/143.

2. A sum of Rs 4000 was lent partly at 5% and partly at 8% interest. Total interest received after 3 years was Rs 717. Find the ratio of the money lent at 5% and 8% ?

A. 16:29
B. 13:17
C. 27:13
D. 29:15
E. None of these

Sol. Suppose money lent at 5% = Rs x
Money lent at 8% = Rs (4000 – x)
Time (T) = 3 years
Interest in the first case = x*5*3/100 = 15x/100
Interest in the second case = Rs (4000 – x)*8*3/100
According to the question,
15x/100 + (3100 – x)*8*3/100 = 717
15x + 96000 – 24x = 71700
9x = 24300
x = Rs 2700
Other amount = Rs (4000 – 2700) = Rs 1300
Hence, ratio of money lent
= 2700: 1300 = 27:13.

3. A boat can travel 8.4km downstream in 14min. If the ratio of the speed of the boat in still water to the speed of the stream is 8:1. How much time will the boat take to cover 16.8km upstream ?

A. 26
B. 28
C. 38
D. 36
E. None of these

Sol. Speed = 8x:x
Downstream = 9x; upstream = 7x
Downstream speed = 8.4*60/14 = 36kmph
9x = 36
X = 4
Upstream = 7*4 = 28kmph
Time taken for 16.8km = 16.8*60/28 = 36min.

4. In a library 20% books are in Science, 50% of the remaining are in Social and the remaining 9000 are in various other subjects. What is the total number of books in Social ?

A. 6000
B. 9000
C. 4500
D. 2250
E. None of these

Sol. Let the no of books be x
Science books = 20% of x = 20/100 = x /5
Remaining = x – x /5 = 4x / 5
Social books = 50/ 100 x 4x / 5 = 2x/ 5
For other Subjects=> x – (x/5 + 2x/5) = 9000
2x / 5 = 9000
X = 22500
Social = 2*22500/5 = 9000.

5. Rahul and Murali buy two goods for Rs. 2000 and Rs. 3000 respectively. Rahul marks his goods up by x%, while Murali marks his goods up by 2x%. If the profit of Murali is Rs.12000 more than Rahul find x ?

A. 5%
B. 7%
C. 8%
D. 3%
E. None of these

Sol. SP of Rahul = 2000 + 2000*x = 2000 (1 + x)
Profit of Rahul = 2000 (1 + x) – 2000
SP of Murali = 3000 + 3000*2x = 3000 (1 + 2x)
Profit of Murali = 3000 (1 + 2x) – 3000
Diff of profit = 12000
[3000 (1 + 2x) – 3000] – [2000 (1 + x) – 2000] = 12000
4000x = 12000
X = 3.

Directions(6-10): What should come in place of (_) in the following series:

6. 11, 13, 20, 48, 111, _

A. 278
B. 268
C. 237
D. 256
E. 258

Sol. 11 + 1³ + 1 = 13
     13 + 2³ – 1 = 20
     20 + 3³ + 1 = 48
     48 + 4³ – 1 = 111

7. 5, 7, 3, 11, -5, _

A. 25
B. 18
C. 30
D. 27
E. None of these

Sol. 5 + 2^1 = 7
     7 - 2^2 = 3
     3 + 2^3 = 11
    11 - 2^4 = -5
    -5 + 2^5 = 27

8. 61, 82, 124, 187, _, 376

A. 238
B. 248
C. 288
D. 271
E. None of these

Sol. 61 + (1 * 21) = 82
82 + (2 * 21) = 124
124 + (3 * 21) = 187

9. 23, 30, 46, 80, 141, _

A. 238
B. 248
C. 288
D. 271
E. None of these

Sol. 30 – 23 = 7
46 – 30 = 16
80 – 46 = 34

16 – 7 = 9
34 – 16 = 18….

10. 39, 52, 78, 117, 169, _

A. 246
B. 148
C. 188
D. 234
E. None of these

Sol. 13 * 3 = 39
13 * 4 = 52
13 * 6 = 78
13 * 9 = 117.



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IBPS Clerk Mains 2016-17 (Important Questions-19)

1. The ratio of the number of boys and girls in a school is 2:3. If 30% of the boys and 40% of the girls are scholarship holders, the percentage of the students who are not scholarship holders is ?

A. 64%
B. 58%
C. 46%
D. 74%
E. None of these

Sol. Consider Total no of students = 100
Ratio is 2:3 i.e Boys=40 and Girls=60
30% of boys who get scholarship = 40*30/100=12%
40% of girls who get scholarship = 60*40/100 =24%
Therefore % of students who do not get scholarship =100-(12+24) = 64%.

2. Prachi lends Rs 40,000 of two of her friends. She gives Rs 20,000 to the first at 5% p.a. simple interest. She wants to make a profit of 10% on the whole. The simple interest rate at which she should lend the remaining sum of money to the second friend is ?

A. 16%
B. 15%
C. 14%
D. 13%
E. None of these

Sol. S.I. on Rs 20000
=(20000×5×1)/100 = Rs. 1000
Profit to made on Rs 40000
= 40000×10/100=Rs 4000
S.I.on Rs.20000 = 4000-1000 = Rs.3000
Rate=(S.I.* 100)/(P * T)=(3000×100)/20000
=15% per annum.

3. Two places are A and B are 150 kms from each other. A train leaves from A for B at the same time another train leaves B for A. The two trains meet at the end of 5 hours. If the train travelling from A to B travels 10km/hr faster than the other. Find the speed of the faster train ?

A. 20
B. 28
C. 25
D. 15
E. None of these

Sol. Let Speed of trains = S and S + 10 km/hr.
At some X distance from A both train will meet.
So, 5 = X/(S +10) ; 5 = (150 – P)/s
Solve both equation, we get S = 10 so faster train speed is 20 km/hr.

4. The cost price of goods with a bankrupt is Rs. 25500 and if the goods had realised in their full value, his creditiors would have received 85 paise in the rupee. But 2/5 of the goods were sold at 17% and the remainder at 22% below their cost price. How many paise in a rupee was received by the creditors? 

A. 72 paise 
B. 68 paise  
C. 55 paise 
D. 52 paise  
E. None of these

Sol. Total debt = 25500 × 100/85 = Rs.30000
Money received by selling the goods = 25500(2/5 × 83/100 + 3/5 × 78/100)
= 25500/500 (166 + 234)
= 51×400 = Rs.20400
Therefore, money received by the creditors for a rupee = Rs.(20400/30000)=Rs.0.68=68 paise
Hence, the creditor received 68 paise in a rupee.

5. Arjun can complete a work in 60 days. Also if Arjun and Bibek work together, they complete the same work in 20 days. If both start work but Bibek works for only half a day, in how many days will both complete the work ?

A. 25
B. 30
C. 35
D. 20
E. None of these

Sol. Bibek’s 1 day’s work = 1/20 – 1/60 = 1/30
Now in 1day Bibek completes 1/30 of the work, so in half day he will complete 1/2 * 1/30 = 1/60 of the work
Now Arjun’s 1 day’s work is 1/60 and B’s 1/60
So their total 1 day’s work = 1/60 + 1/60 = 1/30

Directions(6-10): What should come in place of the question mark(?) in the following number series:

6. 7, 16, 34, 61, 97, ?

A. 142
B. 154
C. 148
D. 164
E. None of these

Sol. 7 + 9*1, 16 + 9*2, 34 + 9*3, 61 + 9*4, ..

7. 8, 2, 2, 4.5, 18, ?

A. 112.5
B. 122.5
C. 134.2
D. 142.5
E. None of these

Sol. A) 112.5
* (0.5^2), * (1^2), * (1.5^2), * (2^2), * (2.5^2)

8. 7, 9, 23, 121, 839, _

A. 7650
B. 7561
C. 7542
D. 7560
E. 7652

Sol. 7*1 + 2 = 9
     9*3 - 4 = 23
    23*5 + 6 = 121
   121*7 - 8 = 839
   839*9 + 10 =7561

9. 6, 8, 16, 34, 66, _

A. 120
B. 122
C. 115
D. 116
E. 124

Sol. 6 + 2*1^2 = 8
     8 + 2*2^2 = 16
    16 + 2*3^2 = 34
    34 + 2*4^2 = 66
    66 + 2*5^2 = 116

10. 90, 89, 58, 53, 34, _

A. 22
B. 24
C. 25
D. 26
E. 21

Sol. 10^2 - 10 = 90
      9^2 + 8  = 89
      8^2 - 6  = 58
      7^2 + 4  = 53
      6^2 - 2  = 34
      5^2 + 0  = 25



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IBPS Clerk Mains 2016-17 (Important Questions-19)

Directions: (1-5): Each of the questions below consists of a question two statements numbered I and II given below it. You have to decide whether the data given in the statements are sufficient to answer the question. Read both the statements and give answer

A) If the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question
B) If the data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question
C) If the data either in statement I alone or in statement II alone are sufficient to answer the question
D) If the data given in both statements I and II together are not sufficient to answer the question
E) If the data in both statements I and II together are necessary to answer the question

1. What is the weighted average of marks obtained by Vishal?
I. Maths, Science and Social have weights 5, 4 and 3 respectively.
II. Simple Arithmetic mean of Maths and science is 140, which is twice the average of Science and Social.

A)
B)
C)
D)
E)

Sol. Ans D)
In Statement I, Only weights of subjects are given
(M+S)/2 =140 => M + S = 280
(S+SL)/2 = 2(140) => S + SL = 560 We can’t find the marks in Maths, Science and Social.

2. What is the difference between the two digits in a two-digit number?
I. The sum of the two digits is 8.
II. 1/5 of that number is 15 less than 1/2 of 44

A)
B)
C)
D)
E)

Sol. Ans B)
Statement I not sufficient
From statement II,
1/5 * x = 1/2 *44 -15
x = 35, Difference between the two digits is = 2.

3. What is the speed of boat in still water?
I. It takes 5 hours to cover the distance between M and N downstream
II. It takes 7 hours to cover the distance between M and N upstream.

A)
B)
C)
D)
E)

Sol. D)
D = 5*(b+s) and D = 7*(b-s)
So we can’t find the value of b.

4. What is the rate of interest p.c.p.a. ?
I.The amount doubles itself in 10 years.
II.The simple interest accrued in 3 years is Rs. 9,000.

Sol. A)
From Statement I,
R = X*100/x*10 = 10%.

5. For a certain bat and ball, what is the price of the ball?
I. The combined price of the bat and the ball is Rs.155
II. The price of the bat is Rs.105 more than the price of the ball.

Sol. E)
From Statement II,
Let the price of ball be x, then the price of the bat= (x+105)

From Statement I, c
Combined price bat and ball = Rs.155

x+(x+105) = 155 => 2x + 105 = 155 =>
x = 25.

Directions(6-10): What should come in place of (_) in the following series:

6. 7, 9, 23, 121, 839, _

A. 7650
B. 7561
C. 7542
D. 7560
E. 7652

Sol. 7*1 + 2 = 9
     9*3 - 4 = 23
    23*5 + 6 = 121
   121*7 - 8 = 839
   839*9 + 10 =7561

7. 6, 8, 16, 34, 66, _

A. 120
B. 122
C. 115
D. 116
E. 124

Sol. 6 + 2*1^2 = 8
     8 + 2*2^2 = 16
    16 + 2*3^2 = 34
    34 + 2*4^2 = 66
    66 + 2*5^2 = 116

8. 90, 89, 58, 53, 34, _

A. 22
B. 24
C. 25
D. 26
E. 21

Sol. 10^2 - 10 = 90
      9^2 + 8  = 89
      8^2 - 6  = 58
      7^2 + 4  = 53
      6^2 - 2  = 34
      5^2 + 0  = 25

9. 50, 26, 14, 8, 5, _

A. 4
B. 3
C. 3.5
D. 2.5
E. 4.5

Sol. 50/2 + 1 = 26
     26/2 + 1 = 14
     14/2 + 1 = 8
      8/2 + 1 = 5
      5/2 + 1 = 3.5

10. 4, 12, 60, 420, _, 41580

A. 4620
B. 3780
C. 4200
D. 5040
E. None of these

Sol. 4*3 = 12
    12*5 = 60
    60*7 = 420
   420*9 = 3780
  3780*11= 41580


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IBPS Clerk Mains 2016-17 (Important Questions-18)

Directions(1-5): Study the information given and answer the given below questions:

A group of 5 members needs to be formed from 4 doctors, 3 engineers and 5 teachers.
In how many ways the group can be formed if,

1. No teacher is included

A. 15
B. 18
C. 21
D. 24
E. None of these

Sol. Case-1 (4 doctors & 1 engineer) → 4c4 × 3c1 = 1×3 = 3
       Case-2 (3 doctors & 2 engineer) → 4c3 × 3c2 = 4×3 = 12
       Case-3 (2 doctors & 3 engineer) → 4c2 × 3c3 = 6×1 = 6

Total cases = 3+12+6 = 21.

2. Atleast 1 selected from each stream

A. 350
B. 400
C. 390
D. 380
E. None of these

Sol. Case-1 (2D , 2E & 1T) → 4C2×3C2×5C1 = 6×3×5 = 90
       Case-2 (1D , 2E & 2T) → 4C1×3C2×5C2 = 4×3×10 = 120
       Case-3 (2D , 1E & 2T) → 4C2×3C1×5C2 = 6×3×10 = 180

Total cases = 90+120+180 = 390.

3. Only teachers can be included

A. 5
B. 2
C. 3
D. 1
E. None of these

Sol. Total cases = 5c5 = 1.

4. Only engineers and teachers can be included

A. 56
B. 55
C. 54
D. 52
E. None of these

Sol. Case-1 (2 engineer & 3 teacher) → 3c2 × 5c3 = 3×10 = 30
       Case-2 (3 engineer & 2 teacher) → 3c3 × 5c2 = 1×10 = 10
       Case-3 (1 engineer & 4 teacher) → 3c1 × 5c4 = 3×5 = 15
       Case-4 (5 teacher) → 5c5 = 1

Total cases = 30+10+15+1 = 56.

5. Total ways of forming the group

A. 756
B. 792
C. 764
D. 781
E. None of these

Sol. Total ways = 12c5 = 792.

Directions(6-10): What should come in place of (_) in the following series:

6. 16, 26, 42, 136, _

A. 534
B. 524
C. 494
D. 484
E. None of these

Sol. The series is  ×1+10,  ×2-10,  ×3+10,  ×4-10

7.  5, 6, 16, 57, 244, 1245, _

A. 7500
B. 7506
C. 7502
D. 7508
E. None of these

Sol. 5*1 + 1^2 = 6
     6*2 + 2^2 = 16
    16*3 + 3^2 = 57
    57*4 + 4^2 = 244
   244*5 + 5^2 = 1245
  1245*6 + 6^2 = 7506

8. 95, 60, 36, 21, 13, _

A. 8
B. 9
C. 10
D. 11
E. 12

Sol. 95 - 60 = 35
     60 - 36 = 24
     36 - 21 = 15
     21 - 13 = 8
     13 - 10 = 3

     35 - 24 = 11
     24 - 15 = 9
     15 - 8  = 7
      8 - 3  = 5
   
Thus, C. 10

9. 25, 32, 53, 88, 137, _

A. 195
B. 200
C. 205
D. 210
E. None of these

Sol. 25 + (7*1) = 32
     32 + (7*3) = 53
     53 + (7*5) = 88
     88 + (7*7) = 137
    137 + (7*9) = 200

10. 3, 5, 13, 43, 177, _

A. 890
B. 889
C. 891
D. 892
E. None of these

Sol. 3*1 + 2 = 5
     5*2 + 3 = 13
    13*3 + 4 = 43
    43*4 + 5 = 177
   177*5 + 6 = 891.



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IBPS Clerk Mains 2016-17 (Important Questions-17)

Directions(1-5): What should come in place of question mark (?) in the following series:

1. 7415, 2271, 2171, 2107, 2071, ?

A. 2057
B. 2056
C. 2055
D. 2054
E. None of these

Sol. 7415 - 12² = 2271
     2271 - 10² = 2171
     2171 -  8²  = 2107
     2107 -  6²  = 2071
     2071 -  4²  = 2055.

2. 500, 465, 435, 410, 390, ?

A. 365
B. 375
C. 385
D. 395
E. None of these

Sol. 500 - 35 = 465
     465 - 30 = 435
     435 - 25 = 410
     410 - 20 = 390
     390 - 15 = 375.

3. 4, 8, 12, 24, 36, ?

A. 75
B. 76
C. 72
D. 70
E. None of these

Sol. 4×2 = 8
     8×1.5 = 12
    12×2 = 24
    24×1.5 = 36
    36×2 = 72.

4. 20, 114, 565, 2256, 6765, ?

A. 13528
B. 12528
C. 13875
D. 12875
E. None of these

Sol. 20×6 - 6 = 114
    114×5 - 5 = 565
    565×4 - 4 = 2256
   2256×3 - 3 = 6765
   6765×2 - 2 = 13528.        
  
5. 112, 146, 95, 163, 78, ?

A. 190
B. 185
C. 180
D. 175
E. None of these

Sol. 112 + 34 = 146
     146 - 51 = 95
      95 + 68 = 163
     163 - 85 = 78
      78 + 102= 180.

6. The ratio of water and milk in three vessels are 5 : 7, 7 : 9 and 8 : 5, respectively. If the mixture of the three vessels is mixed, then what will be the ratio of water and milk ?

A. 791 : 887
B. 857 : 719
C. 917 : 955
D. 875 : 976
E. None of these

Sol. Quantity of water in the mixture = 5/12 + 7/16 + 8/13 = 917/624
Quantity of milk in the mixture = 7/12 + 9/16 + 5/13 = 955/624
The required ratio is 917 : 955

7. A box contains 5 red balls, 4 blue balls, 3 yellow balls and 2 green balls. If four balls are picked at random, what is the probability that two are red, one is blue and one is green ?

A. 22/1001
B. 85/1001
C. 55/1001
D. 80/1001
E. 65/1001

Sol. Total balls = 14
Probability = (5c2 × 4c1 × 2c1 )/ 14c4 = 80/1001.

8. A basket contains 6 red balls and 10 green balls. Two balls are drawn at random one after one with replacement. What is the probability that first one is green and second one is red ?

A. 16/64
B. 18/64
C. 15/64
D. 14/64
E. None of these

Sol. Probability Required = (10/16)×(6/16).

9. Out of a total profit of Rs 14,000, Anish received Rs 10000 as his share. If Anish invested Rs 20000 for 6 months while Balu invested his amount for the whole year, then find the amount that Balu invested ?

A. Rs 5,000
B. Rs 3,000
C. Rs 5,500
D. Rs 4,000
E. None of these

Sol. Profit ratio = 10000 : 4000 = 5 : 2
So
20,000×6 : 12x = 5 : 2
10000/x = 5/2
x = 4,000.

10. It takes six times as long to row a distance against the stream as to row the same distance in favor of the stream. What is the ratio of the speed of the boat in still water to that of stream ?

A. 6 : 7
B. 5 : 8
C. 8 : 5
D. 7 : 5
E. 5 : 7

Sol. A = [(tu + td) / (tu – td)] × B
So
A = [(6x + x) / (6x- x)] × B
So, A/B = 7/5.

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IBPS Clerk Mains 2016-17 (Important Questions-16)

1. Rahul scored 48 marks in the maths examination and failed by 15 marks. The passing percentage is 35% for this exam. What is the maximum marks for the maths examination ?

A. 150
B. 120
C. 180
D. 200
E. None of these

Sol. Let the maximum marks be 'x'
Then, 0.35x = 48 + 15
Solving,  x = 180.

2. The ratio of the number of boys and girls in a school is 4:3. If 15% of the boys and 10% of the girls are scholarship holders, then the percentage of the students who do not get the scholarship, is 

A. 87.14%
B. 82.14%
C. 88.42%
D. 85.16%
E. None of these

Sol. Let no. of boys be 4x
And no. of girls be 3x.
Then, scholarship boys = 0.15*4x = 0.6x
Scholarship girls = 0.1*3x = 0.3x

% non-scholarship students = [(7x-0.9x)/7x]*100 = 87.14%.

3. Mahesh is 36 years old and his son is 10 years old. After how many years mahesh will be twice his son's age ?

A. 8
B. 12
C. 16
D. 20
E. None of these

Sol. Lets the years be 'x'
Then, 36 + x = 2(10 + x)
Solving, x = 16 years.

4. The ages of two persons are in the ratio of 5 : 7. Sixteen years ago, their ages were in the ratio of 3 : 5. Find the sum of their ages ?

A. 84
B. 100
C. 96
D. 72
E. None of these

Sol. Let ages be 5x and 7x.
Then, (5x-16)/(7x-16) = 3/5
Solving, x = 8
Thus, sum = 12x = 96.

5. The milk and water in two vessels A and B are in the ratio 4:3 and 2:3 respectively. In what ratio the liquids in both the vessels be mixed to obtain a new mixture in vessel c consisting half milk and half water?

A. 8:3
B. 7:5
C. 4:3
D. 2:3
E. None of these 

Sol. (1/2 - 2/5)/(4/7 - 1/2)
Required Ratio = 14/10
= 7:5.

6. 50, 26, 14, 8, 5, _

A. 4
B. 3
C. 3.5
D. 2.5
E. 4.5

Sol. 50/2 + 1 = 26
     26/2 + 1 = 14
     14/2 + 1 = 8
      8/2 + 1 = 5
      5/2 + 1 = 3.5

7. 120, 170, 224, 280, 360, _ 

A. 392
B. 442
C. 458
D. 528
E. 540

Sol. 11^2 – 1 = 120
     13^2 + 1 = 170
     15^2 – 1 = 224
     17^2 + 1 = 280
     19^2 – 1 = 360
     21^2 + 1 = 442.

8. 13, 17, 33, 97, _, 1377

A. 332
B. 353
C. 388
D. 396
E. 340
 
Sol. 13 + 4 = 17; 17 + 16 = 33; 33 + 64 = 97....

9. 5, 11, 24, 44, 71, _

A. 102
B. 105
C. 112
D. 101
E. None of these

Sol. 5 + 6 = 11
    11 + 13= 24
    24 + 20= 71
    71 + 27= 105

    13 - 6 = 7
    20 - 13= 7
    27 - 20= 7

10. 6, 4, 5, 11, 39, _

A. 170
B. 185
C. 165
D. 189
E. None of these

Sol. 6*1 - 2 = 4
     4*2 - 3 = 5
     5*3 - 4 = 11
    11*4 - 5 = 39
    39*5 - 6 = 189.

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IBPS Clerk Mains 2016-17 (Important Questions-15)

Directions(1-5): What should come in place of (_) in the following series:

1. 9, 17, 37, 71, 121, _

A. 179
B. 189
C. 199
D. 209
E. None of these

Sol. B) 189
Difference of the difference is in A.P. of 12, 14, 16, 18.

2. 5, 8, 27, 104, 525, _

A. 3125
B. 3150
C. 3144
D. 3156
E. None of these

Sol. 5*2 - 2 = 8
     8*3 + 3 = 27
    27*4 - 4 = 104
   104*5 + 5 = 525
   525*6 - 6 = 3144.

3. 1, 3, 7, 13, 21, _

A. 30
B. 31
C. 32
D. 33
E. None of these

Sol. 1 + 2*1 = 3
     3 + 2*2 = 7
     7 + 2*3 = 13
    13 + 2*4 = 21
    21 + 2*5 = 31.

4. 30, 16, 10, 8, 8, _

A. 12
B. 9
C. 6
D. 15
E. None of these

Sol. 30/2 + 1 = 16
     16/2 + 2 = 10
     10/2 + 3 = 8
      8/2 + 4 = 8
      8/2 + 5 = 9.

5. 7, 11, 19, 29, 41, _

A. 56
B. 55
C. 54
D. 53
E. None of these

Sol. 4 + 1 = 5
     9 + 2 = 11
    16 + 3 = 19
    25 + 4 = 29
    36 + 5 = 41
    49 + 6 = 55.

6. A boat whose speed 15 km/h in still water goes 30 km downstream and comes back in four and half hours. The speed of the stream is (in km/hr)  

A. 5
B. 3
C. 8
D. 9
E. None of these

Sol. Lets assue speed of the stream is 'x' km/hr.
Then,
30/(15-x) + 30/(15+x) = 9/2
Solving, x = 5 km/hr.

7. A car covers a distance of 210 km in a certain amount of time at the speed of 35 km/h. What is the average speed of a truck that travel distance of 18 km less than the car in the same time?  

A. 34 km/hr 
B. 36 km/hr 
C. 35 km/hr 
D. 32 km/hr 
E. None of these

Sol. Time = 210/35 = 6hrs.
Speed of truck = (210-18)/6 = 32 km/hr.

8. If a person walks at 14 km/h instead of 10 km/h he would have walked 20 km more. The actual distance travelled by him is- 

A. 85 km
B. 50 km
C. 80 km
D. 70 km
E. None of these

Sol. x/10 = (x+20)/14
Soling, x = 50 km.

9. A train running at a speed of 40 m/s crosses a pole in 21 seconds less than the time it required to cross a bridge 3.5 times its length at the same speed. What is the length of bridge? 

A. 1080 m 
B. 240 m 
C. 840 m 
D. 560 m 
E. None of these 

Sol. Let the lengtth of the train be 'x' meter.
Length of the bridge is 3.5x m.
Thus, (3.5x + x)/40 - x/40 = 21
Solving, x = 240m.
Thus, length of the bridge = 3.5*240 = 840m.

10. A thief is noticed by a policeman from a distance of 400 m. The thief starts running and policeman chased him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is distance between them after 12 minutes?  

A. 100 m
B. 200 m 
C. 150 m
D. 250 m 
E. None of these

Sol. Relative speed = (11-10) = 1 km/hr
Distance covered in 12 minutes,
= 12/60
= 0.2 km.
= 200 m   

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IBPS Clerk Mains 2016-17 (Important Questions-14)

IBPS Clerk Mains 2016-17 (Important Questions-14)

Directions(1-5) : What should come in place of (_) in the following series :

1. 124, 228, 436, _, 1684, 3348

A. 944
B. 852
C. 872
D. 444
E. None of these

Sol. The series is 
× 2 - 20, ×2 - 20, × 2 - 20, ….

2.  1, 1729, 398, 1398, 669, 1181, _

A. 838
B. 738
C. 638
D. 538
E. None of these

Sol. 1 + 12^3 = 1729 
  1729 - 11^3 = 398 
   398 + 10^3 = 1398 
  1398 - 9^3 = 669 
   669 + 8^3 = 1181 
  1181 - 7^3 = 838

3.  7, 7, 10, 18, 33, _

A. 52
B. 55
C. 57
D. 59
E. None of these

Sol. Difference of the difference is : 3, 5, 7, 9.
Thus, answer is 57.

4. 12, 24, 144, 2592, _

A. 138699
B. 139698
C. 139869
D. 139968
E. None of these

Sol. 12*2=24
24*6 =144…..(2*3 = 6)
144*18 = 2592….(6*3)
2592*54 = 139968….(18*3 = 54).

5. 13, 16, 22, 34, _, 106

A. 56
B. 48
C. 58
D. 62
E. None of these

Sol. 16 - 13 = 3
     22 - 16 = 6
     34 - 22 = 12
     58 - 34 = 24
    106 - 58 = 48.

6. If 2 horses are worth 3 oxen, and 5 oxen are worth 12 sheep, and 2 sheep are worth Rs. 500, the value of the horse is

A. Rs. 800
B. Rs. 600
C. Rs. 900
D. Rs. 750
E. None of these

Sol. Sol. 2 sheep = 500 Rs.
12 sheep = 500 × 6 = 5 oxen
3 oxen = 600 × 3 = 2 houses
1 horses = 900 Rs. 

7. A certain job was assigned to a group of man to do it in 20 days. But 12 men did not turn up for the job and the remaining men did the job in 32 days. The original number of men in group was 

A. 32
B. 34
C. 36
D. 40
E. None of these

Sol. Sol. (x – 12) men in 32 day.
20x = 32(x – 12) or x = 32

8. Three fourth of a tank is full of water. If 5 litre are added to it than four fifth of the tank become full. What is the capacity of tank.

A. 75 litre
B. 82 litre
C. 100 litre
D. 120 litre
E. None of these

Sol. Let the capacity be x then,
3x/4 + 5 = 4x/5
Solving, x = 100 L.

9. 8 men can complete a piece of work in 18 days, 18 women complete in 10 days while 6 children complete in 12 days. 4 children, 12 men and 20 women work for 2 days. If only children were to complete the remaining work in 1 day. How many children are required.

A. 36
B. 24
C. 18
D. Can’t determine
E. None of these

Sol. Sol. 8 M = 18 days
M = 18 × 8 = 144 days
W = 18 × 10 = 180 days
C = 6 × 12 = 72 days
Let work be 720 unit then
M = 5 unit daily
W = 4 unit daily
C = 10 unit daily
4 children, 12 men, 20 women = 40 + 60 + 80 = 180 unit × 2 = 360 unit
Rest 720 – 360 = 360 unit
So, no. of children who complete in 1 day = 360/10 = 36

10. A tank is more completely filled in 16 hours but takes four hour more to fill because of a leak in the bottom of the tank. What will the leak take to empty the completely filled tank.

A. 80
B. 60
C. 50
D. cannot be determine
E. None of these

Sol. A) 80
= (16*20)/(20-16)

= 80.

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IBPS Clerk Mains 2016-17 (Important Questions-13)

IBPS Clerk Mains 2016-17 (Important Questions-13)

1. The ratio of number of students to number of teachers is 1:2, but when 2 teachers and 2 students left, the ratio became 1:3. How many people in total were there ?

A. 16
B. 18
C. 15
D. 12
E. None of these

Sol. Lets assume the number of ladies be 'x'.
Then, numbr of students will be '2x'
According to the question,

(x-2)/(2x-2) = 1/3
Solving, we get, x = 4
Thus, total people = x + 2x = 3*4 = 12.

2. The ratio of difference, sum and product of two numbers is 1:7:24, then what is the sum of these two numbers ?

A. 8
B. 10
C. 12
D. 14
E. None of these

Sol. Lets assume the numbers to be x and y.
According to the question, (x-y)/(x+y) = 1/7
Solving, x = 4y/3 

Also given, (x+y)/xy = 7/24
Using x = 4y/3 in above equation and solving,

y = 6
Thus, x = 4*6/3 = 8
Sum = 6+8 = 14.

3. Three friends X, Y and Z earns a total of Rs 1450 and spend 60%, 45% and 70% of thir salaries respectively. If their savings are in the ratio 14:21:15. Find Y's salary ?

A. 800
B. 600
C. 1000
D. 400
E. None of these

Sol. Salary = savings amount/%value of salary
%value of savings are 40, 35 & 30.
Savings of X, Y and Z are 14x, 21x, 15x
Thus, 14x/40 + 21x/35 + 15x/30 = 1450
Solving, x = 1000
Thus, Y's salary = 21x/35 = Rs 600.

4. There is a ratio of 5 : 4 between two numbers. If 40 percent of the first number is 12, then what would be 50 percent of the second number?

A. 12
B. 24
C. 18
D. Data inadequate
E. None of these

Sol. Lets assume the numbers to be 5x, 4x
Thus, 40% of 5x = 12
Solving, x = 6
Thus, 50% of 2nd number = 50% 0f 4x
Soving, = 12.

5. The age of Anil and Sunil are in the ratio of 8 : 7, After 10 years the ratio of their ages will be 13:12. What is the difference in years between their present ages?

A. 4 years
B. 2 years
C. 6 years
D. 8 years
E. None of these

Sol. Diference of the ages will be same always.
Lets assume the ages to be 8x, 7x.
Thus, (8x + 10)/(7x+10) = 13/12
Solving, x = 2
Difference= 8x - 7x = 2 years.

Directions(6-10): What should come in place of question mark(?) in the following :

6. 49.80 % of 750.08 ÷ 11.02 = 56.09 –  ?

A.34
B.16
C.22
D.27
E.None of these

Sol. C.22
50% of 750÷11 = 56 – x
375/11 = 56 – x
34.09 = 56 – x
X = 56 – 34.09 = 21.91 = 22

7. (1064 ÷ 0.95 + 1028 × 0.50) × 11.5 = ?

A.18147
B.12345
C.16780
D.13678
E.None of these

Sol. 1064+514 = 1578
1578*11.5 = 18147.

8. 65.56 × l24 – 312 × 5 = ? % of 2208.05

A.300
B.245
C.312
D.265
E.None of these

Sol. 66*124 – 312*5 = x % of 2208
8184 – 1560 = x% 2208
6624 = x*2208/100
X = 6624*100/2208
X = 300

9. 68.55 ÷ 0.03 + 52.8 ÷ 0.8 – 170 / 0.25 = ?

A.1234
B.1567
C.1671
D.1987
E.None of these

Sol. 6855/3 = 2285
528/8 = 66
170/0.25 = 680
2285+66 – 680 = 1671.

10. (5616÷156)×23.67 = ? ÷ 16.78

A.12388
B.14336
C.18644
D.14688
E.None of these

Sol. 36*24 = 864

864*17 = 14688.

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IBPS Clerk Mains 2016-17 (Important Questions-12)

IBPS Clerk Mains 2016-17 (Important Questions-12)

1. A sum of money is to be divided among X, Y and Z in the ratio 7:12:18. If the total share of X and Y is Rs 500 more than Z's share. What is X's share ?

A. 3000

B. 3500

C. 4000

D. 4500

E. None of these

Sol. Lets assume X, Y and Z shares are 7x, 12x and 18x.

Then, 7x + 12x = 18x + 500

Solving, x = Rs 3,500

2. A person invested Rs 4400 in two parts one at 6% and the other at 10% rate of interest. If his overall gain is 9%, find the money invested at 10% interest. 

A. 4400

B. 3300

C. 5500

D. 3500

E. 6000

Sol. Ratio of money invested at 6% and 10% is (10-9)/(9-6) = 1:3

Hence, money invested at 10% interest = 3*4400/4 = 3300.

3. The average age of P and Q is 20 years. If R were to replace P, the average would be 19 and if R were to replace Q, the average would be 21. What are the age of P, Q and R?

A. 22, 18, 20

B. 20, 20, 18

C. 18, 22, 20

D. 18, 20, 22

E. None of these

Sol. Sol.  Given P + Q = 40  

 R + Q = 38    

 P + R = 42    

 Adding all the three equations we have, 

 P + Q + R = 60   

 Solving these equations, we have,

 R = 20 years, Q = 18 years and P = 22 years

4. In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for?

A. 160 

B. 175

C. 180 

D. 195

E. None of these

Sol. Suppose the man works overtime for x hours.

Now, working hours in 4 weeks = (5 x 8 x 4) = 160.

160 x 2.40 + x X 3.20 = 432

3.20x = 432 - 384 = 48

x = 15.

Hence, total hours of work = (160 + 15) = 175.

5. If the length, breadth and height of a cuboid is increased by 10%, 20%, 30% respectively. Then find the percentage increase in the volume of the cuboid?

A. 71.6%

B. 60%

C. 171.6%

D. Can’t be determined

E. None of these

Sol. Initial volume = l * b * h. Increased volume will be equal to 1.1l *1.2b *1.3h = 1.716lbh. Therefore percentage increase in volume will be given by the expression ((1.716 -  1)  *lbh)/lbh*100 = 71.6%.

Directions(6-10): What should come in place of (_) in the following series:

6. 16, 27, 44, _, 96,131

A.64

B.72

C.67

D.69

E.None of these

Sol. 16 + 11 = 27

     27 + 17 = 44

     44 + 23 = 67

     67 + 29 = 96

     96 + 35 = 131

7. 43 , 52, 34, 61, _, 70

A.29

B.20

C.22

D.25

E.None of these

Sol. 43+(9*1) = 43+9 = 52

52-(9*2) = 52-18=34

34+(9*3) = 34+27 = 61

61-(9*4) = 61-36 = 25

25+(9*5) = 25+45 = 70

8. 512, 514, _, 556, 612

A.526

B.512

C.524

D.528

E.None of these

Sol. 512 + 2 = 514

514+12 = 526    (12-2 =10+8 = 18+12 =30)

526+30 = 556    (18+8 = 26+30 = 56)

556+56 = 612

9. 213, 220, _, 697, 1761.5

A.337

B.397

C.376

D.341

E.None of these

Sol. 213*1+7 = 220

220*1.5+11 = 330+11 = 341

341*2+15 = 682+15 = 697

697*2.5+19 = 1742.5+19 = 1761.5

10. 3, 14, 23, 34, 47, _

A.63

B.64

C.67

D.62

E.None of these

Sol. 1*2+1 = 2+1 = 3

3*4+2 = 12+2 = 14

4*5+3 = 20+3 = 23

5*6+4 = 30+4 = 34

6*7+5 = 42+5 = 47

7*8+6 = 56+6 = 62. 

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