1. Rakesh invested Rs 20,000 in a scheme exactly 4 years ago. The value of investment increased by 15% during the 1st year, increased by 10% during the 2nd year, decreased by 5% during the 3rd year and decreased by 10% during the 4th year. What is the value of investment today ?
A. 21,600
B. 21,631.5
C. 22,000
D. 22,600
E. None of these
Sol. 20000*1.15*1.1*0.95*0.9 = Rs 21631.5
2. Tina bought 25 tabs and phones for Rs 205000. She sold 80% of tabs and 12 phones for a profit of Rs 40,000. Each tab was marked up by 20% over cost and each phone was sold at a profit of Rs 2000. The remaining tabs and 3 phones could not be sold. What is tina's overall profit/loss ?
A. 2000
B. 1000
C. 1500
D. 2500
E. None of these
Sol. Total no. of phones = 12 + 3 = 15
Total no. of tabs = 25 - 15 = 10
Total CP = Rs 205000
Now, cost of 80% of the goods,
= 0.8*205000
= Rs 164000
Total amount recovered (or SP)
= 164000 + 40000
= Rs 204000
Loss = 205000 - 204000 = Rs 1000
3. Sum of CP's of 2 cows is Rs 13,000. Both the cows are sold at a profit of 20% and 40% respectively with their SP's being the same. What is the difference of CP's of both the cows ?
A. 1500
B. 1200
C. 1000
D. 2000
E. None of these
Sol. Lets assume the CP's of two cows will be x and y.
x + y = 13000
SP of 1st cow = 1.2x ( as 20% profit)
SP of 2nd cow = 1.4y ( as 40% profit)
As both are same,
1.2x = 1.4y
x = 7y/6
Thus,
7y/6 + y = 13000
13y/6 = 13000
y = 6000
x = 7000
Thus, difference = 7000 - 6000 = Rs 1000
4. A tank has 2 pipes. 1st pipe can fill in 45 min. and 2nd pipe can empty in 1hr. In what time will the empty tank be filled if the pipes be opened one at a time in alternate minutes ?
A. 5hr 53min
B. 4hr 42min
C. 3hr 13min
D. 4hr 43min
E. None of these
Sol. Part of tank that will empty in 2min = 1/45 - 1/60 = 1/180
Part of the tank (1 - 1/45) = 44/45 will be filled in = 44*180*2/45 = 352min.
1/45 part of the tank will be filled in 1 min.
Total time = (352+1) = 353 min = 5hr 53min
5. A person used to drawn out 20% of the honey from the full jar and replaced it with sugar solution. He has repeated the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was fiilled with sugar solution. The initial amount of honey in the jar was :
A. 1 kg
B. 1.5 kg
C. 2 kg
D. 2.5 kg
E. None of these
Sol. Let initial amount of honey be 'k' gm.
Thus, 512 = k(1-1/5)^4
512 = k(4/5)^4
k = 1250 gm
Therefore, initial amount of hney was = 1250/1000 = 1.25 kg.
6. A river is flowing at a speed of 10 km/h in a particular direction. Mr.Suresh, who can swim at a speed of 15 km/h in still water, starts swimming along the direction of flow of the river from points A and reaches another point B which is at a distance of 50 km from the starting point A. On reaching point B, he turns back and from starts swimming against the direction of flow of the river and stops after reaching point A. The total time taken by Suresh to complete his journey is ?
A. 11
B. 12
C. 9
D. 8
E. None of these
Sol. Speed of the stream = 10kmph
Downstream speed = 15 + 10 = 25kmph
Upstream speed = 15 – 10 = 5kmph
Total time taken by Suresh = (50/25 + 50/5) = 12h
7. Three persons A, B and C started a business together. They invest Rs.40000, Rs.24000 and Rs.30000 respectively in the beginning. After 4 months. B took out Rs. 4000 and C took out Rs. 10000. They get a profit of Rs. 25400 at the end of the year. B’s share in the profit is ?
A. 6500
B. 6400
C. 5600
D. 5200
E. None of these
Sol. 40000 * 12 : 24000 * 4 + 20000 * 8 : 30,000 * 4 + 20,000 * 8
60 : 32 : 35
32/127 * 25400 = 6400
8. Two cars X and Y starts at the same time from D and A respectively which is 200 km apart, If the two cars travel in opposite directions they meet after 1 hour and if they travel in same direction from D and A then the car which starts at D meets the another car after 5 hours, What is the speed of car starting from D ?
A. 120
B. 100
C. 180
D. 125
E. None of these
Sol. Relative speed = x+y
total distance travelled = 200 km
time taken = 1 hour
x + y = 200 —(1)
Relative speed of the faster car = x – y
total distance travelled = 200 km
time taken = 5 hour
200 = 5(x-y)
40 = x – y —(2)
From (1) and (2) 2x = 240
x = 120
Speed of car starting from D = 120km/hr.
9. Ramya’s present age is four times her daughter, Veena’s present age and two-thirds of her mother, Rani’s present age. The total of the present ages of all of them is 132 years. What is the difference between Ramya’s and her mother Rani’s present age ?
A. 28
B. 24
C. 20
D. 26
E. None of these
Sol. Ramya’s present age – x
x + (x / 4) + (3 / 2) x = 132
11x = 132 * 4
x = 48
Ramya’s mother age = 3/2 * 48 = 72
Difference = 72 – 48 = 24 years.
10. The circumference of a semicircle of area 1925 sq. cm is equal to the breadth of a rectangle. If the length of the rectangle is equal to the perimeter of a square of side 48 cm. What is the perimeter of the rectangle in cm ?
A. 745
B. 744
C. 732
D. 736
E. None of these
Sol. (22/7 *r *r) /2 = 1925
r* r = 1225
r = 35
Circumference of semicircle = 22/7 r + 2 r = 22/7 * 35 + 2 * 35 =180
Breadth of rectangle = 180 cm
Length of rectangle = perimeter of square = 4 * 48 = 192 cm
Perimeter of rectangle = 2 (180 + 192) = 744 cm
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