Quantitative Aptitude Section Strategy for IBPS RRB Scale-1 Prelims 2017

As the IBPS RRB Exam is approaching, many of you must be anxious about the Quantitative Aptitude Section. Students, worrying about things is not an option. Stay positive as once you replace negative thoughts with positive ones, you'll start having positive results. The level of every other section is only getting complex and convoluted, there is no doubt that this section too will be making your blood run cold. But one should not forget that a mix of accuracy and a good number of attempts can definitely turn the situation around in Quantitative Aptitude Section.

The total number of questions asked in this Section in IBPS RRB PO Prelims Examination will be 40. The amount of time that you need to spend on the Quantitative Aptitude Section is 25 minutes. The trick to make the grade in Quantitative Aptitude Section is pretty manageable. Choose to attempt the questions on Quadratic Equations/ Inequalities, Simplification/ Approximation and Number Series first.  The total number of questions based on these topics will be 15. If we talk about the previous year Examination of IBPS PO RRB, there were 5 questions on Number Series, 5 on Quadratic equations, 5 on Simplification. There can be questions on Appoximation and Inequality too. So, this is how questions are framed on these topics. One should try to attempt the maximum number of questions within 8 minutes of time. Attempt at least 11-12 questions because this part is the easiest. After having attempted all these questions efficiently, go for Data Interpretation. There were 3 DI's in the previous year IBPS RRB PO Examination so we can expect 15 questions on DI this year also. One should try to attempt at least 10-11 questions as 3 out of every 5 questions in a DI are doable. The time limit for DI's should be 10-12 minutes. Attempt questions based on Arithmetic in the end. There were a total number of 10 questions from miscellaneous topics in IBPS RRB PO 2016. 6 questions from Arithmetic Section too will be doable, so, try to attempt at least 5-6 questions within a time limit of 5-6 minutes. 

Students, Quantitative Aptitude is a difficult this very section that can scare you out of your wits but do not forget that it can prove to be very scoring as well. The only way to score satisfactory marks in the section is strenuous practice. Work hard and everything will come up roses in the end.

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Important Topics of Quantitative Aptitude for IBPS PO Prelims

यहां हम आपके साथ IBPS PO  Prelims 2017 परीक्षा के लिए क्वांटिटेटिव एपटीड्यूड सेक्शन से कुछ सबसे महत्वपूर्ण और आवश्यक विषयों को साझा करेंगे.IBPS PO भर्ती परीक्षा में 3 प्रमुख वर्ग/विषय है-  संख्यात्मक अभियोग्यता, रीज़निंग और अंग्रेजी भाषा.IBPS Pre परीक्षा में कुल 100 प्रश्नों में से संख्यात्मक अभियोग्यताअनुभाग में 35 प्रश्न होंगे.आपको 1 घंटे के समय का स्वयं प्रबंधन करना होगा,और इस प्रकार आपको 25 मिनट के भीतर संख्यात्मक अभियोग्यता अनुभाग को पूरा करने के लिए पर्याप्त अभ्यास करना होगा.इसके लिए, आपको  बैंक भर्ती परीक्षा के मात्रात्मक योग्यता अनुभाग में must-do 5 most frequently asked topics पर ध्यान केन्द्रित करना होगा.

2015 और 2016 में संख्यात्मक अभियोग्यता अनुभाग में कट ऑफ क्रमशः 7.75 और 8.25 थी. संख्यात्मक अभियोग्यता अनुभाग को पास करने में आपकी मदद करने वाली पहली और सबसे बुनियादी युक्ति यह है कि आपको अपनी गणना गति पर काम करना होगा.यदि आप गणित में अच्छा स्कोर करना चाहते हैं तो आपको पता होना चाहिए कि आपको तेजी से गणना करनी होगी.वास्तव में, यदि आप पर्याप्त अभ्यास कर चुके हैं, तो यह खंड सबसे अधिक स्कोरिंग है क्योंकि आप भाषा के उत्तर को सुनिश्चित नहीं कर सकते हैं और पजल को सुलझाने के दौरान आपको कठिनाई का सामना करना पड़ सकता हैं, लेकिन अंकगणित के प्रश्नों में, आप यह सुनिश्चित कर सकते हैं कि आप इसे हल कर सकते हैं, या आपका उत्तर सही है या नहीं

1. Simplification & Approximation

स्तर: आसान

अपेक्षित प्रश्नों की संख्या: 3 – 5

मानसिक गणना, मन को तेज करती है और मानसिक चपलता और बुद्धि को बढ़ाती है, जो विचारों की शुद्धता को बढ़ाता है.संख्यात्मक अभीयोग्यता में समय बचाने के लिए और अच्छे स्कोर सुनिश्चित करने के लिए, एक मिनट का समय सरलीकरण या सन्निकटन के प्रश्न को हल करने के लिए पर्याप्त हैं.ये प्रश्न आपका सरल  मार्ग हैं जो संख्यात्मक अभीयोग्यता के कठिन अनुभाग में कट ऑफ क्लियर करने में आपकी सहायता करेंगा.

Simplification 

Directio: दिए गए प्रश्नों को सरलीकृत करें और नीचे दिए गए प्रश्नों में प्रश्न चिह्न (?) के स्थान पर आने वाले मान की गणना करे?
Q. 3.5% of 40 + 3.5% of 80 = ?% of 10
(a) 49
(b) 56
(c) 64
(d) 66
(e) 42


Approximation (IBPS PO Pre 2016, SBI PO Pre 2017, IBPS PO Mains 2016)

Direction: नीचे दिए गए प्रश्नों में प्रश्न चिह्न (?) के स्थान पर क्या अनुमानित मान आना चाहिए?
Q. 23.001 × 18.999 × 7.998 = ?
(a) 4200
(b) 3000
(c) 3500
(d) 4000
(e) 2500

2. Number Series

स्तर: आसान- मध्यम

अपेक्षित प्रश्नों की संख्या: 5

भीतर संख्या श्रृंखला के प्रश्न को 30-50 सेकंड के समय में हल करने में सक्षम होने के लिए पर्याप्त अभ्यास करें.पर्याप्त अभ्यास और तेज गणना की गति के साथ आप आसानी से नंबर श्रृंखला प्रश्नों की चाल या पैटर्न की पहचान करने में सक्षम होंगे.यदि आपको श्रृंखला के पैटर्न को प्राप्त करने में बहुत अधिक समय लग रहा हैं, तो आप परीक्षा के दौरान उस प्रश्न को छोड़ सकते हैं.पहाड़े, वर्ग, घन, वर्ग मूल और घन मूल को सीखें.

Missing Number Series (SBI PO Prelims 2017, IBPS Clerk Mains 2016, IBPS PO Prelims 2016)

निर्देश:निम्नलिखित में से प्रत्येक श्रृंखला में प्रश्न चिह्न (?) के स्थान पर क्या मान होगा?
Q. 14, 8, 9, 14.5, 30, ?
(a) 75
(b) 76
(c) 60
(d) 65
(e) इनमे से कोई नहीं

Wrong Number Series (IBPS PO Mains 2016)

निर्देश:निम्नलिखित श्रृंखला में गलत शब्द का पता लगायें.
Q. 33, 39, 56, 85, 127, 185, 254
(a) 39
(b) 254
(c) 185
(d) 85
(e) 56

3. Inequality

स्तर: मध्यम

अपेक्षित प्रश्नों की संख्या: 3 - 5

एसबीआई ने पिछले वर्ष दो मात्रा के आधार पर एक नये प्रकार के असमानता के प्रश्नों की शुरुआत की थी और यह प्रश्न इस वर्ष की एसबीआई पीओ परीक्षा में भी देखे गए हैं.IBPS PO में पैटर्न में बदलावों को देखते हुए इनका आगे की परीक्षा में भी दिखाई देने की बहुत अधिक संभावना है.नए प्रकार के अलावा, आपको द्विघात समीकरण को हल करने में महारत प्राप्त करने के लिए पर्याप्त अभ्यास करना चाहिए.यह विषय अपेक्षाकृत आसान है.

New Pattern Inequality (SBI PO Mains 2017 and IBPS PO Mains 2016)

Q. एक बॉक्स में 1 से 63 तक की संख्या वाले 63 कार्ड हैं. प्रत्येक कार्ड पर केवल 1 संख्या अंकित है.
मात्रा I: उस कार्ड के चयन करने की प्रायिकता, जिनके अंक, यदि आपस में बदल दिए जाते हैं, तो प्राप्त संख्या जो मूल अंकों से 36 अधिक है.
मात्रा II: उस कार्ड को चुनने की प्रायिकता, जिस पर अंकित संख्या , 8 का एक गुणज है, लेकिन 16 का नहीं.
(a) मात्रा I > मात्रा II
(b) मात्रा I < मात्रा II
(c) मात्रा I ≥ मात्रा II
(d) मात्रा I ≤ मात्रा II
(e) मात्रा I = मात्रा II या कोई संबंध नहीं

Quadratic Equation (IBPS PO Prelims 2016)

Direction: दो समीकरण (I) और (II) दिए गए हैं. आपको दोनों समीकरणों को हल करना होगा और जवाब देना होगा:
Q. I. 3x² – 22x +7 = 0
II. y² – 15y + 56 = 0
(a) if x > y
(b) if x ≥ y
(c) if x < y
(d) if x ≤ y
(e) if x = y या x  और y के बीच कोई संबंध स्थापित नहीं किया जा सकता

4. Data Interpretation

स्तर: मध्यम-कठिन

अपेक्षित प्रश्नों की संख्या: 15-20

डेटा इंटरप्रिटेशन किसी भी बैंकिंग परीक्षा के लिए संख्यात्मक अभीयोग्यता अनुभाग का एक प्रमुख हिस्सा है.  निम्नलिखित DI के प्रकार हैं जिनका आपको IBPS परीक्षा के लिए अभ्यास करना चाहिए.

1. Pie Charts 

2. Line Graph 

3. Bar Graphs 

4. Tabular

5. Radar DI

6. Caselet DI
7. Missing DI 

जैसा कि IBPS ने SBI  का परीक्षा पैटर्न चुना है, इस वर्ष भी SBI PO  परीक्षा में हुए परिवर्तनों के बारे में अच्छी जानकारी रखना एक बेहतर निर्णय होगा. SBI PO के  संख्यात्मक अभीयोग्यता अनुभाग में एक बड़ा बदलाव आया है जहां SBI ने मुख्य परीक्षा में अंकगणित विषय आधारित डेटा इंटरप्रिटेशन के प्रश्नों का परिचय दिया.आमतौर पर, DI प्रतिशत, औसत, अनुपात की अवधारणाओं पर आधारित होती है लेकिन इस बार SBI PO Mains 2017 में DI समय और कार्य और लाभ और हानि पर आधारित थी.तो नए पैटर्न के साथ-साथ पारंपरिक पैटर्न के साथ भी तैयार रहें.

5. Arithmetic Questions (Word Problem)

स्तर: मध्यम-कठिन

अपेक्षित प्रश्नों की संख्या: 10

शब्द समस्याओं के लिए,आपको अंकगणित भाग को तैयार करने और अभ्यास करने की आवश्यकता है. इस भाग में विभिन्न अध्याय - लाभ और हानि, औसत, अनुपात और समानुपात, गति दूरी और समय, समय और कार्य, प्रायिकता, पाइप और टंकी, क्रमांतरण और संयोजन, चक्रवृद्धि ब्याज और साधारण ब्याज शामिल हैं. इनसे निपटने का सबसे अच्छा तरीका संभवत:  उन विषयों के अभ्यास और प्रयास है जिसमें आप आत्मविश्वास से भरे है और आपकी एक बेहतर पकड हैं. किसी शब्द की समस्या पर 2 मिनट से अधिक खर्च न करने की कोशिश करें. यह आपके समय को मार सकता है इसलिएआपको अपने समय प्रबंधन के साथ सख्त होना चाहिए.

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Strategy To Clear IBPS PO 2017 Prelims

The notification of IBPS PO 2017 Examination is already out and the registrations too have started. We all know how SBI PO Examination 2017 blew everyone's mind this year with new pattern questions. Well, IBPS too has introduced changes in the Mains Examination Pattern and it now looks similar to the pattern of SBI PO Mains Examination. But if we talk of the pattern of Prelims Examination, then, to your relief, the pattern is still the same.

Students, as far as the IBPS PO 2017 Prelims Examination cut off is concerned, it entirely depends on the number of vacancies declared and the complexity level of questions asked. The overall cut off for Prelims Examination of 2015 and 2016 were 37.25 and 47.50 respectively. As the difficulty level of every other examination has only been rising, there is no doubt that the level of IBPS Examination too has to rise. 

Quantitative Aptitude

Quantitative Aptitude Section has always been giving heebie-jeebies to the students, many of them are bundle of nerves while attempting this particular section. Well, this is a fact that this section can be very difficult and time-consuming. Data Interpretation and topics from arithmetic section make it hard for one to deal with the section as easily as any other section. But students, you can't ignore the fact that this very section can prove to be very scoring as well. The only way to ace the scores in the section is strenuous practice.

The trick to ace Quantitative Aptitude test is to attempt the questions on Quadratic Equations, Simplification and Approximation first and then you go for Number Series. The total number of questions on these topics will be 15. One should try to attempt at least 12 questions in not more than 8 minutes. After having attempted all these questions efficiently, go for Data Interpretation. As per the previous year pattern of IBPS PO 2016, the number of questions based on DI in 2017 Examination will be 10 i.e. 2 DI's, each holding 5 questions. In every DI 3 questions are always doable and the rest two are a bit tricky and calculative. So, one should try to attempt at least 6-7 questions out of the total 10 questions within 10 minutes. The remaining 10 questions will be based on miscellaneous topics like CI & SI, Time and Work, Pipes and Cisterns, Partnership, etc. 6 out of these 10 questions too will be doable and one should try to finish them within 7 minutes. If we observe the pattern of Quant Section of IBPS PO Prelims 2016 and SBI PO Prelims 2017, it's the same as described. So, one can be very sure that same is going to be the pattern of IBPS PO 2017 as IBPS follows the pattern of SBI only. This is how you have to wind up with the Quantitative Aptitude Section. The average time to be spent on this section should be 25 minutes. Practice continuously, it will pay big time.

The sectional cut off for Quantitative Aptitude Section in 2015 and 2016 were 7.75 and 8.25 respectively.

Reasoning Ability

This section is no doubt going to make your blood run cold with a great number of puzzles and the number can be as great as 55-60% of the total number of questions in this section. You literally need to practice quite hard if you genuinely wish to ace the grades in this particular section. 

The trick to attempt the maximum number of questions in minimum time is to attempt the difficult puzzles in the end. Start with the questions that are not in the form of puzzles, you can choose to start with questions based on inequalities, direction and distance, syllogism, coding decoding, alpha numeric series, and other random topics. Then try to start with puzzles that appear easy to be solved and proceed with moderate and difficult puzzles in a similar way. You can choose to leave an extremely difficult puzzle but do keep it in mind that it is just impossible to overlook puzzles as the expected number of total questions based on puzzles is 20-24. And yes, do read the question very carefully, you can miss a few important points while solving puzzles and mark a wrong answer too. So, this is how you have to manage to attempt this section. Make sure that the time that you spend on solving this section doesn't exceed 20 minutes.

The sectional cut off for Reasoning Ability Section in 2015 and 2016 were 11.25 and 8.50 respectively.

English Language

This topic can be easy as pie if your basics are clear. A habit of reading an English Newspaper can actually do a good turn because it helps to build up a strong vocabulary, effective knowledge of grammar, and efficient comprehension skills. Rest depends on how hard you practice.

The trick to scoring in English section can vary from one person to another depending on his/her strengths and weaknesses. If you are good at vocab and reading then attempt the reading comprehension first and proceed with Cloze Test and other miscellaneous topics like Error Detection, Para Jumbles, Phrase Replacement, Double Fillers, etc. But if you are good at grammar, attempt Reading Comprehension in the end. The Reading comprehension too should be attempted in a way that you attempt questions based on vocab and phrases first and then the questions that need a deep penetration through the paragraphs. The important topics for cloze test are subject verb agreement, preposition and verbs. These topics may help you some other questions too that will be based on grammar. So make sure that you have these topics on your finger tips when you are to attempt the examination. This section should be finished within a time limit of 15 minutes.

The sectional cut off for English Language Section in 2015 and 2016 were 7.50 and 7.00 respectively.

So students, we hope this article proves to be helpful to you all. Do bear it in mind that there is an overall cut off too. So, do not just concentrate on clearing sectional cut off of every different section, try to perform to the best of your ability in every section so that you are able to clear the overall cut off too. Put your heart, mind, and soul into even your smallest acts. This is the secret to success. 

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Quant Mix Quiz-9 IBPS PO 2016-17 (Plus the solutions)

Q1. The sum of five consecutive even numbers is equal to 170. What is the sum of the second largest number amongst them and the square of the smallest number amongst them together?
  
(a) 940
(b) 932
(c) 938
(d) 934 
(e) None of these

Sol. Let the five consecutive even numbers are 2x, 2x + 2, 2x + 4, 2x + 6, 2x + 8 respectively.
According to the question,
2x + 2x + 2 + 2x + 4 + 2x + 6 + 2x + 8 = 170
10x + 20 = 170
10x = 150
x= (150/10) = 15
Thus, the five numbers are 30, 32, 34, 36, 38 respectively.
Therefore, required sum =(30)^2+36 = 900+36 = 936

Q2. The area of a square is four times area of a rectangle. The length of the rectangle is 25 cm and its breadth is 1 cm less than one-fifth its length. What is the perimeter of the square? 

(a) 40 cm 
(b) 80 cm 
(c) 160 cm 
(d) Cannot be determined 
(e) None of these 

Sol. Length of the rectangle  = 25cm

Thus, Breadth = [(1/5)*Length] - 1 = (25/5)-1 = 4cm
Given, area of the square = 4*area of the rectangle
       (side)^2 = 4*(25*4)
        side = 20cm

Hence, perimeter of the square = 4*side = 4*20 = 80cm

Q3. Sohan got 54 marks in Hindi, 65 marks in Science, 89 marks in Maths, 69 marks in Social Science and 68 marks in English. The maximum marks of each subject are 100. How much overall percentage of marks did he get? 

(a) 74 
(b) 69
(c) 68
(d) 72
(e) None of these

Sol. Marks in all subjects = 54 + 65 + 89 + 69 + 68 = 345
Total maximum marks = 5 * 100 = 500
Thus,  required percentage =(345/500)*100=69%

Q4. 8 women cam complete a piece of work in 15 h. In how many hours will 12 women complete the same piece of work? 

(a) 12 
(b) 6
(c) 8
(d) 10
(e) None of these 

Sol. 8 women can complete a piece of work in = 15 h
1 woman can complete a piece of work in = (15 * 8) h = 120 h
Thus, 12 women can complete a piece of work in =120/12 = 10 h

Q5. The length of a rectangle is 24 cm which is 10 cm more than the diameter of a circle. What is the area of the circle? 

(a) 210 sq cm 
(b) 176 sq cm 
(c) 132 sq cm 
(d) 154 sq cm 
(e) None of these 

Sol. Diameter of a circle = 24 - 10 = 14 cm
Radius of a circle =14/2 = 7 cm
Area of a circle = (22/7)r^2 = (22/7)*7*7 = 154 sq.cm

Q6. Three substances A, B and C are mixed together. Their volumes are proportional to 4, 3 and 2 respectively and the weights of equal volumes are proportional to 5, 4 and 3 respectively. What is the weight of substance A if the weight of the mixture is 114 kg?

(a) 30 kg
(b) 40 kg
(c) 50 kg
(d) 60 kg
(e) 70 kg

Sol. Let the volumes of A, B and C be 4, 3 and 2.
And the weight of equal volumes of A, B and C be 5, 4 and 3
Ratio of weight of A, B and C = 5*4 : 3*4 : 2*3
= 20 : 12 : 6
= 10 : 6 : 3
So, Weight of A = 10/19 * 114 = 60kg

Q7. How many numbers lying between 3000 and 4000 and divisible by 5 can be made with the digits 3, 4, 5, 6, 7 and 8? (The digits are not to be repeated in any number).

(a) 10
(b) 12
(c) 14
(d) 16
(e) 18

Sol. Every number between 3000 to 4000, which is divisible by five and which can be formed by the given digits, must contain 5 at unit’s place and 3 at thousand’s place.
Thus we are left with four digits out of which we are to place two between 3 and 5, which can be done in
 4P2 = 12 ways

Q8. A student scored 20% of maximum marks and failed by 26 marks and when he scores 40% of the marks in the same paper he passes by 14 marks. Then find the maximum marks?

(a) 100
(b) 200
(c) 300
(d) Cannot say
(e) None of the above

Sol. Let the maximum marks be M, then (40 – 20) % of maximum marks will equal to 26 + 14 = 40 marks.
Therefore 20% * M = 40 or M = 200

Q9. Ram could save 20% of his income. But two years later when his income is increased by 10%, he could save the same amount only as before. By how much percent has his expenditure increased?

(a) 12.5
(b) 11.11
(c) 9.09
(d) 15
(e) None of the above

Sol. Let original income = Rs. 100. Then, saving = Rs. 20 and expenditure = Rs. 80
New income = Rs. 110, New saving = Rs. 20
New expenditure = Rs. 90
Increase in expenditure = Rs. 10.
Thus, Increase % = [10/80)*100]% = 12.5%

Q10. Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is definitely the difference between R and Q’s age?

(a) 1 year 
(b) 2 years 
(c) 25 years
(d) Data inadequate 
(e) None of these

Sol. R – Q = R – T => Q = T. Also, R + T = 50
R + Q = 50
So, (R – Q) cannot be determined.

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IBPS Quant quiz based on 23rd October shift (IBPS PO Prelims 2016)

1. A 280-m-long train takes 20 sec to cross a person who is going in the same direction with the speed of 6 km/h. After crossing that person, the train can reach next station in 45 min. How long will that person take to reach the station after being crossed by train?

(a) 7 hr 3 min
(b) 6 hr 3 min
(c) 7 hr 30 min
(d) 7 hr 50 min
(e) 6 hr 30 min


2. The number obtained by interchanging the two digits of a two-digit number is less than the original number by 36. If the sum of the two digits of the number is 8, then what is the original number?

(a) 26
(b) 53
(c) 62
(d) 35
(e) 71


3. The distance between two stations S1 and S2 is 640 km. A train J starts at 5 pm from S1 and moves towards S2 at an average speed of 80 km/h. Another train K starts from S2 at 4 : 20 pm and moves towards S1 at an average speed of 100 km/hr. How far from S1 will the two trains meet?

(a) 248.18 km
(b) 278.48 km
(c) 276.38 km
(d) 254.81 km
(e) 268.18 km

Directions (4-8): Find the missing numbers in the given series :

4. 4, 5, 22, 201, _

A. 1200
B. 1202
C. 2202
D. 3220
E. None of these

5. 22, 30, 19, 27, _

A. 14
B. 18
C. 16
D. 15
E. None of these

6. 15, 12, 18, 9, 21, _

A. 4
B. 8
C. 9
D. 6
E. None of these

7. 4, 9, 20, 43, 84, _

A. 169
B. 159
C. 149
D. 139
E. None of these

8. 69, 74, 67, 78, 65, _

A. 62
B. 74
C. 82
D. 90
E. None of these

9. Rajesh had Rs. 20,000 with him out of this money he lent some money to Mahesh for 4 years at 20% p.a. simple interest. He lent the remaining money to Suresh for an equal number of years at the rate of 24% p.a. After 4 years, Rajesh found that Mahesh had given him Rs. 864 more as interest as compared to Suresh. The amount of money which Rajesh had lent to Suresh must be.

A. 11,600
B. 9,600
C. 8,600
D. 10,600
E. None of these

10. The area of each face of the cube is 36 and the length of one side of the cube is 6. Then what is the volume of the cube?

A. 144
B. 256
C. 216
D. 196
E. None of these

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Quant Mix Quiz-8 IBPS PO 2016-17 (Plus the solutions)

1) Two men undertake to do a piece of work for Rs. 600. One alone could do it in 6 days and the other in 8 days. With the assistance of a boy they finished it in 3 days. Boy's share should be

A.  Rs. 75   B. Rs. 225   C. Rs. 300   D.    Rs. 100 Sol. 1st man ‘A’ can do in 6 days 2nd man ‘B’ can do in 8 days A, B  & Boy can do it is 3 days Let there be 24 units of work (LCM of 6, 8 and 3) ⇒ A does 4 units/day      B does 3 units/day      Boy does 1 units/day      Money is divided in the ratio of 4 : 3 : 1 .... That implies Boy gets Rs. 75/- 2) A wire of length 60 m is used to enclose a field which is in the shape of a right-angled triangle. The area of the field is 150 m2. Then the largest side of the field has a length of : A.    30 m B. 20 m C. 25 m D. 15 m Sol. Perpendicular = x         Base = y         Hypotenuse = z   x + y + z = 60 Also, x^2 + y^2 = z^2 (1/2)*x*y = 150 Solving, x=15m ,   y=20m  ,     z=25m Longest side = 25 m. 3) A cylindrical container is filled with ice cream. Its diameter is 12 cm and height is 15 cm. The whole ice cream is distributed among 10 children in equal cones having hemispherical tops. If the height of the conical portion is twice the diameter of its base, the diameter of the ice cream cone is : A.   8 cm B.  5 cm C.  7 cm D.  6 cm Solution : 4) A, B, C together earn Rs. 1450 and spend 60%, 65% and 70% of their salaries respectively. If their savings           are 14 : 21 : 15, the salary of B is: A.    Rs. 500 B. Rs. 600 C. Rs. 450 D. Rs. 750 Sol. 5) Ramesh travelled 300 km by train and 200 km by taxi. It took him 5 hours and 30 minutes. However, if he travels 260 km by train and 240 km by taxi, he takes 6 minutes more. The speed of the train is: A.    100 km/h B. 120 km/h C. 80 km/h D. 110 km/h Sol. 6) Rs. 9000 was divided equally among a certain number of persons. Had there been 20 more persons, each  would have got Rs. 160 less. The original number of persons was:  A.    30  B. 45  C. 25  D. 55 Sol. 7) The autorickshaw fare consists of a fixed charge together with the charge for the distance covered. For a journey of 10 km, the charge paid is Rs. 85 and for a journey of 15 km, the charge paid is Rs. 120. The fare for a journey of 25 km will be:  A.    Rs. 175 B. Rs. 190 C. Rs. 180 D. Rs. 225 Sol. Let fixed charges = F and Variable Charges = V F +10V = 85 + F +15V = 120⇒ F + 25V = 190/ 8) A train is scheduled to cover the distance between two stations 46 km apart in one hour. If it travels 25 km at a speed of 40 km/h, find the speed for the remaining journey to complete it in scheduled time:   A.  66 km/h   B. 56 km/h   C. 46 km/h   D. 36 km/h Sol.

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Complete solution of IBPS PO Prelims Paper 2016 - 22nd October Shift (Based on memory)

Directions (1-5): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer

(1) if x > y
(2) if x >=y
(3) if x < y
(4) if x <=y
(5) if x = y or relationship between x and y cannot be established.

1. 1) 8x^2 -10x +3 = 0
    2) 7y^2 -17y +6 = 0

Sol. For 1st eqn values are,
    x = 0.5, 0.75
     For 2nd equation values are,
    y = 2, 3/7

Thus, no relation between the two.

2. 1) 4x^2 -13x +3 = 0 
    2) 2y^2 -13y +21 = 0

Sol. For 1st eqn values are,
    x = 3, 1/4
     For 2nd equation values are,
    y = 3, 7/2

Thus, y >= x.

3. 1) 5x^2 -32x +12 = 0
    2) y^2 -15y +56 = 0

Sol. For 1st eqn values are,
    x = 6, 2/5
     For 2nd equation values are,
    y = 8, 7

Thus, y > x.

4. 1) 2x^2 +9x +10 = 0
    2) 5y^2 +19y +18 = 0

Sol. For 1st eqn values are,
    x = -2, -5/2
     For 2nd equation values are,
    y = -2, -9/5

Thus, y >= x.

5. 1) x^2 +11x +28 = 0
    2) y^2 +16y +64 = 0

Sol. For 1st eqn values are,
    x = -7, -4
     For 2nd equation values are,
    y = -8

Thus, x > y.

6. An item sold at 10% discount gives 17% profit, what would be the percentage profit if discount increased to 15% ?        

A. 12%
B. 11%
C. 10%
D. 10.5%
E. None of these

Sol. Lets assume C.P. to be 100
Then S.P. will be 117 (as profit 17%)

Now, 117 = (90/100)*M.P.   (As discount is 10%)
     M.P.= 130

When discount 15%, S.P. = (85/100)*130 = 110.5
Thus, profit % = 10.5 %.

7. What is the area of the square whose side is equal to the side of an equilateral triangle with area 9*(3)^0.5 ?

A. 16
B. 36
C. 18
D. 24
E. None of these

Sol. Lets say the side of the square  = side of the equilateral triangle be 'a'.
Now, area of the triangle is given 9*(3)^0.5,thus,
[a*a*(3)^0.5]/2 = 9*(3)^0.5
a = 6

Thus area of the square,
= a^2
= (6)^2
= 36

8. 6 yrs ago, ratio of age of Annu and Nalini was 7:4. The age of Annu 4 yrs hence is equal to age of Nalini 10 yrs hence. Then find the sum of ages of both 2 yrs from now ?

A. 38
B. 36
C. 34
D. 32
E. None of these

Sol. Lets assume Annu's age to be 'x'
     And Nalini's age to be 'y'

The 1st eqn. will be,,
(x-6)/(y-6) = 7/4
The 2nd eqn. will be,
x + 4 = y + 10

Solving both, we get,

x = 20
y = 14

Thus, 20 + 14 + 4 = 38.

9. 15 women can complete 10% of the work in 7 days, 25 women worked for 31.5 days then what fraction of the work is remaining ?

A. 1/5
B. 1/6
C. 1/4
D. 1/3
E. None of these

Sol. 25 women complete the work in = (15*70)/25 = 42 days

25 women per day work = 1/42
25 women 31.5 day work = 31.5/42

Remaining work = (1 - 31.5/42) = 1/4.

10. There are 32 cards in a bag numbered from 1 to 32. 2 cards are drawn one by one without replacement. Find the probability that both are even numbered cards.

A. 1/16
B. 15/62
C. 16/62
D. 15/31
E. None of these

Sol. Required Probability = (16/32)*(15/31) = 15/62

11. A and B enetered into a partnership with the investments of 25500 and 15000. At the end of 1 year B invested 9000 rs more. The total profit earned at the end of 2 yrs is 45,000 then find the difference between the shares of A and B.

A. 5000 RS
B. 6000 RS
C. 7000 RS
D. 8000 RS
E. None of these

Sol. (25500*2):(15000 + 24000)
= 17:13
Required Difference = (4/30)*45000 = Rs 6000.

12. A certain amount of money is invested in a scheme offering 12% simple per annum. After 2 yrs the total amount obtained from this scheme is invested for 5 yrs in another scheme offering 20% simple per annum. If the total amount obtained is 29,760. Then find the sum of money invested initially.

A. 10000
B. 12000
C. 13000
D. 15000
E. None of these

Sol. Let initial sum = 100
100*(124/100)*[(20*5)+100]/100 = 248 rs
For 248 rs total amount = Rs 29760
Thus, for 100 rs total amount will be = 12000 rs.

13. Two trains of length 200m each running in the same direction cross each other in 80 sec. If the speed of faster traiin is 72 km/hr, then find the speed of the slower train.

A. 36 km/hr
B. 45 km/hr
C. 54 km/hr
D. 57 km/hr
E. None of these

Sol. Relative speed = 400/9 = 5m/s
     Speed of faster train = 72*(5/18) = 20m/s
     Speed of slower train = 20 - 5 = 15m/s
     or 15*(18/5) = 54 km/h.

14. Out of three numbers, the first is twice the second and is half of the third. If the avg. of 3 numbers is 56, the three numbers in order are:

A. 48,96,24
B. 48,24,96
C. 96,24,48
D. 96,48,24
E. None of these

Sol. Sum of three numbers = 56*3 = 168
     Let 2nd no. = x
     1st no. = 2x
     3rd no. = 4x
 x + 2x + 4x = 168
The no.s are 48 , 24, 96.

15. A sells a horse to B for Rs 4860, thereby losing 19%, B sells it to C at a price which would have given A 17% profit. Find B's gain.

A. Rs 2160
B. Rs 2610
C. Rs 1260
D. Rs 2260
E. None of these

Sol. C.P. for A = 4860*[100/(100-19)] = 6000
     S.P. with 17% profit for A = 6000*[(100+17)/100] = 7020

     B's gain = 7020 - 4860 = 2160.

Directions(16-20):Find the missing numbers in the given series

16. 11, 14, 23, 50, _

A. 130
B. 132
C. 131
D. 133
E. None of these

Sol. 11 + 3 = 14
     14 + 3^2=23
     23 + 3^3=50

Thus, 50 + 3^4 = 131 

17. 19, 25, 42, 71, 113, _

A. 149
B. 156
C. 169
D. 175
E. None of these

Sol. The difference of the difference is in the A.P.
 = 113 + 56
 = 169.

18. 35, 30, 44, 39, _

A. 60
B. 55
C. 54
D. 53
E. None of these

Sol. 21 + 14 = 35
     35 - 5  = 30
     30 + 14 = 44
     44 - 5  = 39

Thus, 39 + 14 = 53    

19. 23, 39, 32, 48, 41, _

A. 56
B. 57
C. 55
D. 54
E. 52

Sol. 23 + 16 = 39
     39 - 7  = 32
     32 + 16 = 48
     48 - 7  = 41

Thus, 41 + 16 = 57.

20. 13, 17, 33, 97, _

A. 243
B. 341
C. 353
D. 281
E. None of these

Sol. 13 + 4 = 17
     17 + 4^2=33
     33 + 4^3=97



Thus,  97 + 4^4 = 353.  

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