Sunday, 23 October 2016




1) Two men undertake to do a piece of work for Rs. 600. One alone could do it in 6 days and the other in 8 days. With the assistance of a boy they finished it in 3 days. Boy's share should be
  B.
  C.
  D.
  
Sol. 1st man ‘A’ can do in 6 days
2nd man ‘B’ can do in 8 days
A, B  & Boy can do it is 3 days
Let there be 24 units of work (LCM of 6, 8 and 3)
⇒ A does 4 units/day
     B does 3 units/day
     Boy does 1 units/day
     Money is divided in the ratio of 4 : 3 : 1 .... That implies Boy gets Rs. 75/-

2) A wire of length 60 m is used to enclose a field which is in the shape of a right-angled triangle. The area of the field is 150 m2. Then the largest side of the field has a length of :

B.
C.
D.

Sol. Perpendicular = x
        Base = y
        Hypotenuse = z
 
x + y + z = 60
Also, x^2 + y^2 = z^2
(1/2)*x*y = 150

Solving, x=15m ,   y=20m  ,     z=25m
Longest side = 25 m.

3) A cylindrical container is filled with ice cream. Its diameter is 12 cm and height is 15 cm. The whole ice cream is distributed among 10 children in equal cones having hemispherical tops. If the height of the conical portion is twice the diameter of its base, the diameter of the ice cream cone is :


B.
C.
D.

Solution :



4) A, B, C together earn Rs. 1450 and spend 60%, 65% and 70% of their salaries respectively. If their savings           are 14 : 21 : 15, the salary of B is:
B.
C.
D.

Sol.



5) Ramesh travelled 300 km by train and 200 km by taxi. It took him 5 hours and 30 minutes. However, if he travels 260 km by train and 240 km by taxi, he takes 6 minutes more. The speed of the train is:
B.
C.
D.

Sol.



6) Rs. 9000 was divided equally among a certain number of persons. Had there been 20 more persons, each  would have got Rs. 160 less. The original number of persons was:
 B.
 C.
 D.

Sol.



7) The autorickshaw fare consists of a fixed charge together with the charge for the distance covered. For a journey of 10 km, the charge paid is Rs. 85 and for a journey of 15 km, the charge paid is Rs. 120. The fare for a journey of 25 km will be:
B.
C.
D.

Sol.

Let fixed charges = F and Variable Charges = V
F +10V = 85 + F +15V = 120⇒ F + 25V = 190/

8) A train is scheduled to cover the distance between two stations 46 km apart in one hour. If it travels 25 km at a speed of 40 km/h, find the speed for the remaining journey to complete it in scheduled time:

  B.
  C.
  D.
Sol.

 

 
















 


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