1. The ratio of the number of boys and girls in a school is 2:3. If 30% of the boys and 40% of the girls are scholarship holders, the percentage of the students who are not scholarship holders is ?
A. 64%
B. 58%
C. 46%
D. 74%
E. None of these
Sol. Consider Total no of students = 100
Ratio is 2:3 i.e Boys=40 and Girls=60
30% of boys who get scholarship = 40*30/100=12%
40% of girls who get scholarship = 60*40/100 =24%
Therefore % of students who do not get scholarship =100-(12+24) = 64%.
2. Prachi lends Rs 40,000 of two of her friends. She gives Rs 20,000 to the first at 5% p.a. simple interest. She wants to make a profit of 10% on the whole. The simple interest rate at which she should lend the remaining sum of money to the second friend is ?
A. 16%
B. 15%
C. 14%
D. 13%
E. None of these
Sol. S.I. on Rs 20000
=(20000×5×1)/100 = Rs. 1000
Profit to made on Rs 40000
= 40000×10/100=Rs 4000
S.I.on Rs.20000 = 4000-1000 = Rs.3000
Rate=(S.I.* 100)/(P * T)=(3000×100)/20000
=15% per annum.
3. Two places are A and B are 150 kms from each other. A train leaves from A for B at the same time another train leaves B for A. The two trains meet at the end of 5 hours. If the train travelling from A to B travels 10km/hr faster than the other. Find the speed of the faster train ?
A. 20
B. 28
C. 25
D. 15
E. None of these
Sol. Let Speed of trains = S and S + 10 km/hr.
At some X distance from A both train will meet.
So, 5 = X/(S +10) ; 5 = (150 – P)/s
Solve both equation, we get S = 10 so faster train speed is 20 km/hr.
4. The cost price of goods with a bankrupt is Rs. 25500 and if the goods had realised in their full value, his creditiors would have received 85 paise in the rupee. But 2/5 of the goods were sold at 17% and the remainder at 22% below their cost price. How many paise in a rupee was received by the creditors?
A. 72 paise
B. 68 paise
C. 55 paise
D. 52 paise
E. None of these
Sol. Total debt = 25500 × 100/85 = Rs.30000
Money received by selling the goods = 25500(2/5 × 83/100 + 3/5 × 78/100)
= 25500/500 (166 + 234)
= 51×400 = Rs.20400
Therefore, money received by the creditors for a rupee = Rs.(20400/30000)=Rs.0.68=68 paise
Hence, the creditor received 68 paise in a rupee.
5. Arjun can complete a work in 60 days. Also if Arjun and Bibek work together, they complete the same work in 20 days. If both start work but Bibek works for only half a day, in how many days will both complete the work ?
A. 25
B. 30
C. 35
D. 20
E. None of these
Sol. Bibek’s 1 day’s work = 1/20 – 1/60 = 1/30
Now in 1day Bibek completes 1/30 of the work, so in half day he will complete 1/2 * 1/30 = 1/60 of the work
Now Arjun’s 1 day’s work is 1/60 and B’s 1/60
So their total 1 day’s work = 1/60 + 1/60 = 1/30
Directions(6-10): What should come in place of the question mark(?) in the following number series:
6. 7, 16, 34, 61, 97, ?
A. 142
B. 154
C. 148
D. 164
E. None of these
Sol. 7 + 9*1, 16 + 9*2, 34 + 9*3, 61 + 9*4, ..
7. 8, 2, 2, 4.5, 18, ?
A. 112.5
B. 122.5
C. 134.2
D. 142.5
E. None of these
Sol. A) 112.5
* (0.5^2), * (1^2), * (1.5^2), * (2^2), * (2.5^2)
8. 7, 9, 23, 121, 839, _
A. 7650
B. 7561
C. 7542
D. 7560
E. 7652
Sol. 7*1 + 2 = 9
9*3 - 4 = 23
23*5 + 6 = 121
121*7 - 8 = 839
839*9 + 10 =7561
9. 6, 8, 16, 34, 66, _
A. 120
B. 122
C. 115
D. 116
E. 124
Sol. 6 + 2*1^2 = 8
8 + 2*2^2 = 16
16 + 2*3^2 = 34
34 + 2*4^2 = 66
66 + 2*5^2 = 116
10. 90, 89, 58, 53, 34, _
A. 22
B. 24
C. 25
D. 26
E. 21
Sol. 10^2 - 10 = 90
9^2 + 8 = 89
8^2 - 6 = 58
7^2 + 4 = 53
6^2 - 2 = 34
5^2 + 0 = 25
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