Directions(1-5): Find the missing numbers in the given series:
1. 41, 42, 45, 54, 81, _
A. 158
B. 160
C. 162
D. 164
E. None of these
Sol. 41 + 3^0 = 42
42 + 3^1 = 45
45 + 3^2 = 54
54 + 3^3 = 81
81 + 3^4 = 162
2. 5, 4, 7, 20, 79, _
A. 390
B. 398
C. 394
D. 395
E. None of these
Sol. 5*1 - 1 = 4
4*2 - 1 = 7
7*3 - 1 = 20
20*4 - 1 = 79
79*5 - 1 = 394
3. 12, _, 6, 9, 18, 45
A. 12
B. 6
C. 8
D. 15
E. None of these
Sol. 12*0.5 = 6
6*1 = 6
6*1.5 = 9
9*2 = 18
18*2.5 = 45
4. 164, 84, 44, 24, 14, _
A. 12
B. 9
C. 8
D. 15
E. None of these
Sol. 164 - 80 = 84
84 - 40 = 44
44 - 20 = 24
24 - 10 = 14
14 - 5 = 9
5. 350, 334, 366, 318, _, 302
A. 376
B. 382
C. 386
D. 390
E. None of these
Sol. 350 - 16 = 334
334 + 32 = 366
366 - 48 = 318
318 + 64 = 382
382 - 80 = 302
6. Six years from now, average of mannu's age and ninnu's age will be 29 yrs. Five years ago, ratio of ahe of mannu to ageo ninnu is 11:7. What is the age of ninnu ?
A. 19
B. 20
C. 22
D. 18
E. None of these
Sol. Lets assume age of mannu to be 'x'
And age of ninnu to be 'y'
Six years from now, mannu's age = x+6 and ninnu's age = y+6
Thus, according to the question,
(x+6+y+6)/2 = 29
x + y = 46
Five years ago, mannu's age = x-5 and ninnu's age = y-5
Thus, according to the question,
(x-5)/(y-5) = 11/7
11y - 7x = 20
Now solving these equations we get,
y = 19 years.
7. There are seven positive numbers. Average of first 4 numbers is 11 and the average of last 4 numbers is 9. What is the 4th number ?
A. 16
B. 15
C. 13
D. 12
E. None of these
Sol. Sum of 1st four no.s = 11*4 = 44
Sum of last four no.s = 8*4 = 32
Also, Sum of all seven no.s = 9*8 = 72
Thus, Fourth number = (44 + 32) - 72 = 13.
8. Two trains travel in opposite direction from the same starting point. Speeds of the 1st train is 22m/s and speed of 2nd train is 8m/s. How long will tey take to be 378 km apart ?
A. 3hours 30min
B. 3hours 45min
C. 4hours 15min
D. 3hours 35min
E. None of these.
Sol. Relative speed = 22 + 8 = 30m/s = 30*18/5 = 108 km/hr
Relative distance = 378 km
Thus time taken will be = 378/108 = 3hours 30minutes.
9. 2/7th of a number is two less than 1/2 of another number . If the sum of the two numbers is 15, what is their product ?
A. 14
B. 54
C. 56
D. 36
E. None of these
Sol. Lets assume the numbers are x and y.
Then, according to the question,
2x/7 = y/2 - 2
and
x + y = 15
Solving these we get,
x = 7
y = 8
Thus the product = 8*7 = 56.
10. Sum of the two positive numbers is 630. If 75% of 1st number is equal to 60% of 2nd number, then what is the larger number among the two ?
A. 280
B. 350
C. 290
D. 340
E. None of these
Sol. Lets assume the 1st number be 'x'
And the 2nd number be 'y'
According to the question,
x + y = 630
and
75x/100 = 60y/100
Solving these two we get,
x = 350
y = 280
Thus the larger number is 350.
For more Updates & Notifications for bank exams like SBI PO, SBI CLERK, IBPS PO, IBPS RRB, IBPS CLERK, IBPS SO, NIACL, SSC CHSL, SSC CGL etc. like our facebook page at :
0 comments:
Post a Comment