Directions (Q. 1-5): In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer if:
1)If X>Y
2)If X<Y
3)If X≥ Y
4)If X≤ Y
5)If X=Y or cannot be established
1. I. 3X2 +23X + 44 = 0
II. 3Y2 + 20Y +33 = 0
2. I. 2X2 – X – 10 = 0
II. 2Y2 – Y – 21 = 0
3. I. X2 + 3X + 2 = 0
II. Y2 + 5Y +6 = 0
4. I. 2X2 – X – 21 = 0
II.3Y2 + 14Y + 15 = 0
5. I. 2X2 – 5X – 12 = 0
II. 2Y2 + 11Y + 15 = 0
6. A mixture of 15 ltrs contains two liquids A and B in the ratio 2:1. 5 ltrs is drawn and replaced with 5 ltrs of B, if the same process is repeated again, then find the amount of A at the end of it ?
A. 10
B. 12
C. 15
D. 16
E. None of these
7. Ramesh donates 20% of his salary to charity. On the donation day he changed is his mind and donated Rs 15,000 which is 125% of his previous amount. What is his salary ?
A. Rs 60,000
B. Rs 50,000
C. Rs 40,000
D. Rs 30,000
E. None of these
8. In a batch of 50 students and 8 teachers, gifts were distributed such that each student got 25% of the total teachers and each teacher got 10% of the total students. How many gifts were there ?
A. 150
B. 145
C. 140
D. 135
E. None of these
9. A train makes four stops each 15 min long to cover a distance of 500 km in 3hrs. If the train is 300m long then find the time it takes to cross a pole ?
A. 4.56 seconds
B. 3.24 seconds
C. 4.32 seconds
D. 3.42 seconds
E. None of these
10. A is 2 years older than B while B is 3 year younger than C. The ratio of age of A, 6 years hence and B, 2 years ago is 5:3. What was age of C, 6 years ago?
A.12 years
B.19 years
C.15 years
D.14 years
E.21 years
ANSWERS
1. 4
3x(x+4)+11(x+4)
X = -4, -11/3
3y(y+3)+11(y+3)
Y = -3, -11/3
2. 5
X(2x-5) + 2(2x-5) = 0
X = -2,5/2
Y(2y-7)+3(2y-7)= 0
Y= -3,7/2
3. 3
(x+1)(x+2) = 0
X= -1,-2(Y+2)(y+3) = 0
Y = -2,-3
4. 5
2x(x+3) – 7(x+3) = 0
X = -3,7/2
3y(y+3) + 5(y+3) = 0
Y = -3,-5/3
X = -3,7/2
3y(y+3) + 5(y+3) = 0
Y = -3,-5/3
5. 1
2x(x-4) + 3(x-4) = 0
X = 4,-3/2
2y(y+3) + 5(y+3) = 0
Y = -3,-5/2
Amount of A left after 2 withdrawls,
= 10*[(10-5)/5]^2
= 10 ltrs
7. Lets assume the salary is 'x'.
Previous charity donation = 20% of x = 0.2x
New donation = 125% of 0.2x = 0.25x
Now this is equal to Rs 15,000
0.25x = 15000
x = Rs 60,000
8. Number of gifts each student gets = 25% of 8 = 2
Total gifts to students = 2*50 = 100
Number of gifts to each teacher = 10% of 50 = 5
Total gifts to teachers = 5*8 = 40
Thus total gifts = (100+40) = 140
9. Lets assume time taken to be 't' seconds
Then speed of the train will be = (300/t) m/sec
Now its also given that the train takes 3hrs to cover a distance of 500 km with the stoppage time being = (15*4) = 60 min = 1 hr
Thus the speed of the train will be,
=500/(3-1) = 250km/hr = (250/3.6)m/sec
Now equating the two,
250/3.6 = 300/t
t = 4.32 seconds
Thus it takes 4.32 seconds to cross a pole.
10. Lets assume C is 'x' yrs
Then B will be (x-3) yrs
And A will be (x-3+2) = (x-1) yrs
Age of A 6yrs hence = x-1+6 = (x+5) yrs
Age of B 2 yrs ago = x-3-2 = (x-5) yrs
Now, ratio of these two is 5:3, so,
5/3 = (x+5)/(x-5)
x = 20 yrs
Age of C 6 yrs ago = x-6 = 14 yrs.
X = 4,-3/2
2y(y+3) + 5(y+3) = 0
Y = -3,-5/2
6. Initial amount of A = (2/3)*15 = 10
Initial amount of B = (1/3)*15 = 5Amount of A left after 2 withdrawls,
= 10*[(10-5)/5]^2
= 10 ltrs
7. Lets assume the salary is 'x'.
Previous charity donation = 20% of x = 0.2x
New donation = 125% of 0.2x = 0.25x
Now this is equal to Rs 15,000
0.25x = 15000
x = Rs 60,000
8. Number of gifts each student gets = 25% of 8 = 2
Total gifts to students = 2*50 = 100
Number of gifts to each teacher = 10% of 50 = 5
Total gifts to teachers = 5*8 = 40
Thus total gifts = (100+40) = 140
9. Lets assume time taken to be 't' seconds
Then speed of the train will be = (300/t) m/sec
Now its also given that the train takes 3hrs to cover a distance of 500 km with the stoppage time being = (15*4) = 60 min = 1 hr
Thus the speed of the train will be,
=500/(3-1) = 250km/hr = (250/3.6)m/sec
Now equating the two,
250/3.6 = 300/t
t = 4.32 seconds
Thus it takes 4.32 seconds to cross a pole.
10. Lets assume C is 'x' yrs
Then B will be (x-3) yrs
And A will be (x-3+2) = (x-1) yrs
Age of A 6yrs hence = x-1+6 = (x+5) yrs
Age of B 2 yrs ago = x-3-2 = (x-5) yrs
Now, ratio of these two is 5:3, so,
5/3 = (x+5)/(x-5)
x = 20 yrs
Age of C 6 yrs ago = x-6 = 14 yrs.
For more Updates & Notifications for bank exams like SBI PO, SBI CLERK, IBPS PO, IBPS RRB, IBPS CLERK, IBPS SO, NIACL, SSC CHSL, SSC CGL etc. like our facebook page at :
0 comments:
Post a Comment