Ratio & Proportion Quiz For All Bank Exams

1. If A : B = 3/4, B : C = 4/5, C : D = 5/6, then A : D will be: 

(a) 2 : 3
(b) 4 : 3
(c) 1 : 2
(d) 2 : 1
(e) None of these  

Sol. A : B = 3 : 4, B : C = 4 : 5, C : D = 5 : 6
∴A∶B∶C∶D= 3 : 4 : 5 : 6.
Thus, A : D = 3 : 6 or, 1 : 2.

2. The ratio of present ages of Suresh and Mahesh is 7 : 5. If after 6 years their ages will be in the ratio of 4 : 3, the present age of Mahesh is:  

(a) 32 years 
(b) 36 years 
(c) 30 years 
(d) 35 years
(e) None of these 

Sol. (7x+6)/(5x+6) = 4/3
Solving, x = 6
Present age of mahesh = 5x = 30 yrs.

3. In a mixture of 60 litres, the ratio of milk and water is 2 : 1. What amount of water must be added to make the ratio of milk and water as 1 : 2?

(a) 75 litres 
(b) 55 litres 
(c) 60 litres 
(d) 65 litres 
(e) None of these 

Sol. Here, milk = 40, water = 20
Let x litres of water is added
(20+x)/(60+x) = 2/3
x = 60 litres 

4. even men, five women and eight children were given as assignment of distributing 2000 books to students in a school over a period of three days. All of them distributed books on the first day. One of the second day two women and three children remained absent and on the third day three men and five children remained absent. If the ratio of the number of books distributed in a day by a man, a woman and a child was 5 : 4 : 2 respectively, a total of approximately how many books were distributed on the second day?  

(a) 1000
(b) 800
(c) 650
(d) 900
(e) Cannot be determined 

Sol. Let the books distributed by man, a woman and a child be 5x, 4x and 2x respectively. 
No. of books distributed in 1st day 
= 7×5x+5×4x+8×2x=71x 
No. of books distributed in 1Ind day 
= 7×5x+3×4x+5×2x=57x  
And no. of books distributed in IIIrd day 
= 4×5x+5×4x+3×2x=46x 
71x + 57x + 46x = 2000, x = 2000/174 
57x=2000/174×57=650 (Approx.) 

5. A sum of money is divided among A, B, C and D in the ratio 3 : 5 : 8 : 9 respectively. If the share of D Rs. 1,872 more than the share of A, then what is the total amount of money of B & C together? 

(a) Rs. 4,156 
(b) Rs. 4,165
(c) Rs.4,056 
(d) Rs. 4,065
(e) None of these 

Sol. Share of B+C = 1872*(5+8)/(9-3) = Rs 4056.

6. A bag contains one rupee, 50 paise and 25 paise coins in the ratio 2 : 3 : 5. Their total value is Rs. 144. The value of 50-paise coins is:   

(a) Rs. 24
(b) Rs. 36
(c) Rs. 48
(d) Rs. 72 
(e) None of these 

 Sol. Let the number of one-rupee coins, 50-paise coins and 25-paise coins be 2k, 3k and 5k, respectively. 
 2k × 1 + 3k × 0.50 + 5k × 0.25 = 114 
 2k + 1.50k + 1.25k = 114 
 4.75k = 114
 k = 24. 
50 paise value = 1.5x = 1.5*24 = 36.

7. Determine the ratio of the number of people having characteristic X to the number of people having characteristic Y in a population of 100 subjects from the following table: 
Having X and Y - 10
Having X but not Y - 30
Having Y but not X - 20
Having neither X nor Y - 40 

(a) 4 : 3  
(b) 3 : 2
(c) 1 : 2
(d) 2 : 3 
(e) None of these 


Sol. Number of people having characteristic X
= 10 + 30 = 40
Number of people having characteristic Y 
= 10 + 20 = 30 
Required ratio = 40 : 30 = 4 : 3  

8. The students in three classes are in the ratio 4 : 6 : 9. If 12 students are increased in each class, the ratio changes to 7 : 9 : 12. Then the total number of students in the three classes before the increase is:  

(a) 95
(b) 76
(c) 100
(d) 114 
(e) None of these 

Sol. Let the original number of students be 4x, 6x and 9x. 
Now, according to the question, 
(4x + 12)/(6x + 12)=7/9 
42x + 84 = 36x + 108 
42x – 36x = 108 – 84 
6x = 24 
x = 4 
Required number of students = 4x + 6x + 9x = 19x = 19 × 4 = 76   

9. When X is subtracted from the numbers 9, 15 and 27, then remainders are in the continued proportion. What is the value of X?

(a) 8
(b) 6
(c) 4
(d) 5
(e) None of these

Sol. Let x be subtracted from the numbers 9, 15 and 27 we get continue proportion.
Now, (9 – x) : (15 – x) : (27– x) 
b^2=ac 
⇒ (15-x)^2=(9-x)(27-x) 
Or, 225 – 30x +x^2=243+x^2-36x 
Or 6x = 243 – 225 = 18 
x = 3 
Hence, number become 9 – x = 9 – 3 = 6 
15 – x = 15 – 3 = 12 
And, 27 – x = 27 – 3 = 24 
6 : 12 : 24 = 1 : 2 : 4 

10. A certain amount was to be distributed among A, B and C in the ratio 2 : 3 : 4, but was erroneously distributed in the ratio 7 : 2 : 5. As a result of this, B received Rs. 40 less. What is the actual amount? 

(a) Rs. 210
(b) Rs. 270
(c) Rs. 230
(d) Rs. 280
(e) None of these 

Sol. Let amount be x.
B's share = 3x/9
After error B's share = 2x/14
thus, 3x/9 - 2x/14 = 40
Solving, x = Rs 210.

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