Just a few days are left for SBI PO and NIACL Assistant Examination. It is time to pace up your preparation for SBI PO Prelims and NIACL Assistant Mains 2017. These Reasoning questions will also help you in preparing for BOB PO and NICL AO 2017 recruitment examination.
Directions (1-5): Study the given information and answer the questions:
A word and number arrangement machine when given an input line of words and numbers rearranges them following a particular rule in each step. The following is an illustration of an input and rearrangement.
Input: getting 26 their 35 due 48 share 17 resources 64 within 56
Step I: due getting 26 their 35 48 share resources 64 within 56 17
Step II:getting due their 26 35 48 share resources 64 within 17 56
Step III:their getting due 26 35 48 share resources within 17 56 64
Step IV:their 64 getting due 26 35 share resources 17 56 within 48
Step V:getting 56 their 64 due 26 resources 17 within 48 share 35
Step VI: due 17 getting 56 their 64 within 48 share 35 resources 26
And Step VI is the last step of the rearrangement of the above input.
As per the rules followed in the above steps, find out in each of the following questions the appropriate step for the given input.
Input: fly 15 butter 28 in 45 the 64 sky 32 blue 57
Q1. Which of the following would be the step 3rd after arrangement?
(a)in fly butter 15 28 45 the sky 32 blue 57 64
(b) in fly butter 15 28 45 the sky blue 57 64 32
(c)in fly butter 15 28 45 the sky blue 32 64 57
(d) in fly butter 15 28 45 the sky blue 32 57 64
(e) None of these
Q2. In step V, which of the following words would be at 6th position from the left end?
(a) in
(b)64
(c) butter
(d) 15
(e) None of these
Q3.In step IV, which of the following words would be at 3rd position to the left of 8th from the left end?
(a) fly
(b) 15
(c)28
(d) butter
(e)None of these
Q4. In step II,‘15’ is related to ‘in’ and ‘the’ is related to ‘sky’. In the same way ‘64’ is related to?
(a)32
(b) sky
(c)57
(d)butter
(e) blue
Q5. In which step the elements ’15 blue 32’ found in the same order?
(a)StepI
(b)StepII
(c)StepIII
(d)StepV
(e)None of these
Solution (1-5):
Students let us understand the Logic behind this Question and let’s understand how to solve it. When we see the each step, then we can find that there is both number and words are arranged in each step.
1) In this arrangement input series is divided into two equal parts.. “fly 15 butter 28 in 45” and “the 64 sky 32 blue 57”
Now from first part all words are arranged alphabetically in every step upto arrangement of all words, and it is shifted to one position right in next step.
2) In second part , all numbers are arranged in increasing order and arranged number are shifted to one position left in next step.
3) After completion of arrangement of all words and numbers in both equal parts, now its turn of arrangement of that part which is not arranged yet.
4) Now from Step IV- One highest word according to English dictionary and one highest number both of arranged part will arranged to left end and it will shift one position to right in next step.
One highest word according to English dictionary and one highest number both of unarranged part will be arranged to right end and it will shift one position to left in next step.
5)And the above process will continue till the last step.
Input: fly 15 butter 28 in 45 the 64 sky 32 blue 57
Step I: butter fly 15 28 in 45 the 64 sky blue 57 32
Step II: fly butter 15 28 in 45 the 64 sky blue 32 57
Step III: in fly butter 15 28 45 the sky blue 32 57 64
Step IV: in 64 fly butter 15 28 sky blue 32 57 the 45
Step V: fly 57 in 64 butter 15 blue 32 the 45 sky 28
Step VI: butter 32 fly 57 in 64 the 45 sky 28 blue 15
S1. Ans.(d)
Sol.This is the step III- in fly butter 15 28 45 the sky blue 32 57 64
S2. Ans.(d)
Sol. This is the Step V:fly 57 in 64 butter 15 blue 32 the 45 sky 28
15 is the 6th from the left.
S3. Ans.(b)
Sol. In step IV, ‘15’ would be at 3rd position to the left of 8th from the left end.
This is the Step IV: in 64 fly butter 15 28 sky blue 32 57 the 45
3rd position to the left of 8th from the left= 5th from left=15
S4. Ans.(e)
Sol.
S5. Ans.(d)
Sol.
Solution (1-5):
Students let us understand the Logic behind this Question and let’s understand how to solve it. When we see the each step, then we can find that there is both number and words are arranged in each step.
1) In this arrangement input series is divided into two equal parts.. “fly 15 butter 28 in 45” and “the 64 sky 32 blue 57”
Now from first part all words are arranged alphabetically in every step upto arrangement of all words, and it is shifted to one position right in next step.
2) In second part , all numbers are arranged in increasing order and arranged number are shifted to one position left in next step.
3) After completion of arrangement of all words and numbers in both equal parts, now its turn of arrangement of that part which is not arranged yet.
4) Now from Step IV- One highest word according to English dictionary and one highest number both of arranged part will arranged to left end and it will shift one position to right in next step.
One highest word according to English dictionary and one highest number both of unarranged part will be arranged to right end and it will shift one position to left in next step.
5)And the above process will continue till the last step.
Input: fly 15 butter 28 in 45 the 64 sky 32 blue 57
Step I: butter fly 15 28 in 45 the 64 sky blue 57 32
Step II: fly butter 15 28 in 45 the 64 sky blue 32 57
Step III: in fly butter 15 28 45 the sky blue 32 57 64
Step IV: in 64 fly butter 15 28 sky blue 32 57 the 45
Step V: fly 57 in 64 butter 15 blue 32 the 45 sky 28
Step VI: butter 32 fly 57 in 64 the 45 sky 28 blue 15
S1. Ans.(d)
Sol.This is the step III- in fly butter 15 28 45 the sky blue 32 57 64
S2. Ans.(d)
Sol. This is the Step V:fly 57 in 64 butter 15 blue 32 the 45 sky 28
15 is the 6th from the left.
S3. Ans.(b)
Sol. In step IV, ‘15’ would be at 3rd position to the left of 8th from the left end.
This is the Step IV: in 64 fly butter 15 28 sky blue 32 57 the 45
3rd position to the left of 8th from the left= 5th from left=15
S4. Ans.(e)
Sol.
S5. Ans.(d)
Sol.
Directions (6-10): Study the following information carefully and answer the question given below:
Eight friends Q, R, S, T, W, X, Y and Z attended the seminar in the months of January and March but not necessarily in the same order. In each month, the seminar was conducted on dates 8th, 11th, 15thand 19th of the month. Only one person attended the seminar on these given dates.
Q attended the seminar on either 15th January or 15th March. There was only one person attended the seminar between Q and T. There are two persons attended the seminar between the T and R. There are one person attended the seminar between the R and S. S attended the seminar on 11th of any month either March or January. Only one person attended the seminar between S and W. There are as many as person attended the seminar between W and Y as between Y and Z. X did not attend the seminar on 8th of January.
Q6.Who among following attended the seminar on 15th January?
(a) Z
(b) Q
(c) R
(d) Y
(e) S
Q7. How many persons attended the seminar between R and W?
(a) One
(b) Two
(c) Three
(d) More than three
(e) None of these
Q8. Who among following attended the seminar on 19th March?
(a) R
(b) Y
(c) S
(d) X
(e) W
Q9. If T is related to Q and R is related to S, in the same way Y is related to ?
(a) X
(b) T
(c) Z
(d) Q
(e) R
Q10. X attended the seminar on which of the following dates ?
(a) 11th January
(b) 19th March
(c)15th January
(d) 19th January
(e) None of these
Solution (6-10):
S6. Ans.(b)
Sol.
S7. Ans.(c)
Sol.
S8. Ans.(e)
Sol.
S9. Ans.(a)
Sol.
S10. Ans.(e)
Sol.
Q11. Prakash starts from a point A and travels 3 m eastwards to B and then turns left and travels thrice that distance to reach C. He again turns left and travels five times the distance he covered between A and B and reaches his destination D. The shortest distance between the starting point and the destination is .
(a) 12m
(b) 15m
(c) 16m
(d) 18m
(e) None of these
S11. Ans.(b)
Sol. The distance between A and D(starting point and destination is)=
Q12. Neha walks 20 m North. Then she turns right and walks 35 m. Then she turns left and walks 15 m. Then she again turns left and walks 15 m. In which direction is she from her original position?
S11. Ans.(b)
Sol. The distance between A and D(starting point and destination is)=
Q12. Neha walks 20 m North. Then she turns right and walks 35 m. Then she turns left and walks 15 m. Then she again turns left and walks 15 m. In which direction is she from her original position?
(a) North
(b) North-west
(c) North-east
(d) South-east
(e) None of these
S12. Ans.(c)
Sol. Neha is in north-east of from her starting position.
Q13. Shivam is the son of Madan’s father’s sister. Romil is the son of Shikha who is the mother of Sonu and grandmother of Madan. Pawan is the father of Kalika and maternal grandfather of Shivam. How is Sonu’s brother related to Kalika?
(a) Niece
(b) Sister-in-law
(c) Sister
(d) Mother
(e) Brother
S13. Ans.(e)
Sol.Brother
Q14. Shubham, Sonam, Ishant, Neha, and Nimisha work in the same company. Nimisha joined company before Ishant but after Sonam. Shubham started working in the company before Sonam but after Neha. Who is the senior-most among them?
(a) Shubham
(b) Neha
(c) Nimisha
(d) Sonam
(e) None of these
S14. Ans.(b)
Sol.Neha is senior most among all the of the employee.
Neha > Shubham > Sonam > Nimisha > Ishant
Q15. Jay is taller than Vinod who is shorter than pramod. Usha is taller than Priyanka but shorter than Vinod. Pramod is shorter than Jay. Who is the tallest?
(a) Priyanka
(b) Vinod
(c) Pramod
(d) Jay
(e) None of these
S15. Ans.(d)
Sol.Jay > Pramod > Vinod > Usha > Priyanka
S15. Ans.(d)
Sol.Jay > Pramod > Vinod > Usha > Priyanka
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