IBPS Clerk Mains 2016-17 (Important Questions-5)

IBPS Clerk Mains 2016-17 (Important Questions-5)

1. In how many ways "PROBATIONARY" can be written such that the vowels are always together ?

A. 2 * 7!*5!
B. 8!
C. 2 * 8!*5!
D. 8! / 2!
E. 7!

Sol. Vowels in the word PROBATIONARY are O, A, I, O, A
     Now keeping them together and treating them as one word.
     No.  of ways of writting that will be = 8!
     Now the vowel group its self can be written in = (5!/2!*2!) 

Thus, total ways of writing PROBATIONARY is = (8!*5!)/(2!*2!) = 2*7!*5!

2. A can complete a piece of work in 4 days. B takes double the time taken by A, C takes double that of B, and D takes double that of C to complete the same task. They are paired in groups of two each. One pair takes two-thirds the time needed by the second pair to complete the work. Which is the first pair?

A. A and B
B. A and C
C. B and C
D. A and D
E. C and D

Sol. Work done in one day by A, B and C are 1/4,1/8,1/16 and 1/32 respectively.
Using answer choices, we note that the pair of B and C does 3/16 of work in one day; the pair of A and D does 1/4+1/32=9/32 of work in one day
Hence, A and D take 32/9 days
B and C take 16/3=32/6 days
Hence, the first pair must comprise of A and D.

3. X and Y can do a piece of work in 20 days and 30 days. Both starts the work together for some time, but Y leaves the job 5 days before the work is completed. Find the time in which work is completed ?

A. 7 days
B. 12 days
C. 14 days
D. 16 days
E. None of these

Sol. Together they can finish the job in,
= 1/(1/20 + 1/30)
= 12 days

X works alone for 5 days, thus completes, = 5/20 = 1/4th work
Work to be completed by both working togeher = 1- 1/4 = 3/4th

Time taken for that = 12*(3/4) = 9 days.
Thus, total time take to complete the work is = (9 + 5) = 14 days.

4. A sum of Rs.3,50,500 is to be paid back in 2 equal annual instalments. How much is each instalment, if the rate of interest charged 4% per annum compound annually ?

A.Rs.1,90,450
B.Rs.1,65,876
C.Rs.1,76,545
D.Rs.1,85,834
E.None of these

Sol. Total value of all the 3 instalments
[X*100/104] + [X*100*100/104]  = 3,50,500
X*25/26 + x*625/676 = 3,50,500
X*25/26[1+25/26] = 3,50,500
X*25/26[51/26] = 3,50,500
X = 35500*676/25*51 = 185833.72 = 185834. 

5. The difference between the total simple interest and the total compound interest compounded annually at the same rate of interest on a sum of money at the end of two years is Rs. 350. What is definitely the rate of interest per cent per annum?

A.9,300
B.7600
C.12000
D.Data inadequate
E.None of these

Sol. Difference = Pr2/(100)2
= (350×100×100)/(P×r2)
P is not given. Thus data inadequate. 


Directions(6-10): Find the missing number in the given series:

6. 11, 15, 29, 59, 111, _

A. 191
B. 193
C. 192
D. 198
E. 196

Sol. 15 - 11 = 4
    29 - 15 = 14
    59 - 29 = 30
    111 - 59 = 52  
    Now finding the difference of the difference,
    14 - 4 = 10
    30 - 14 = 16
    52 - 30 = 22
    Further calculating the difference
    16 - 10 = 6
     22 - 16 = 6

7. 40, 53, 78, 119, 180, _

A. 275
B. 265
C. 215
D. 280
E. 195

Sol. 
    40 + 2^2 + 3^2 = 53
    53 + 3^2 + 4^2 = 78
    78 + 4^2 + 5^2 = 119
   119 + 5^2 + 6^2 = 180
   180 + 6^2 + 7^2 = 265.

8. 527, 523, 514, 498, 473, _

A. 436
B. 437
C. 486
D. 487
E. 453

Sol. 527 - 2^2 = 523
     523 - 3^2 = 514
     514 - 4^2 = 498
     498 - 5^2 = 473
     473 - 6^2 = 437

9.  13, 18, 32, 56, 91, _

A. 136
B. 135
C. 144
D. 156
E. 138

Sol. E

     18 – 13 = 5
     32 – 18 = 14
     56 – 32 = 24; 14 – 5 = 9; 24 – 14 = 10.

10. 6, 5, 8, 20, 72, _

A. 344
B. 244
C. 324
D. 224
E. 124

Sol. 
    6*1 - 1 = 5
    5*2 - 2 = 8
    8*3 - 4 = 20
   20*4 - 8 = 72

   72*5 - 16= 344. 

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