IBPS Clerk Mains 2016-17 (Important Questions-7)

IBPS Clerk Mains 2016-17 (Important Questions-7)

Directions(1-5): What should come in place of the question mark (?) in the following questions:

1. 69.69 – 51.54 + 73.65 = ? + 32.42

A. 47.44
B. 53.88
C. 53.38
D. 44.34
E. None of these

Sol.Ans.E 59.38

2. 25% of 48 + 50% of 120 = ?% of 1200

A. 4
B. 5
C. 6
D. 8
E. 16

Sol. Ans. C 6


3. 323.232 + 32.3232 + 3.23232 = ?

A. 678.324652
B. 6687665.2
C. 358.78752
D. 368.76752
E. None of these

Sol. Ans. C 358.78752

4. (5.8 × 12 × 6) + (8.6 × 18 × 10) = ?

A. 1695.6
B. 1965.6
C. 1596.6
D. 1695.6
E. None of these

Sol. 417.6 + 1548 = 1965.6

5. 63.603 + 153.755 + 94.753 – 48.32 – 122.204 = ?

A. 145
B. 141.587
C. 140.587
D. 139.587
E. None of these

Sol. Ans. B 141.587

6. Ramesh won a competition and got some prize money. He gave Rs. 2000 less than the half of prize money to Suresh and Rs. 1000 more than the two third of the remaining to his Mahesh. If both of them got the same amount, what is the prize money Ramesh got ?

A. 20000  
B. 25000
C. 26000  
D. 24000
E. None of these

Sol. Assume Ramesh got x rupees.
     He gave x/2 - 2000 to Suresh.
     And (2/3)*( x/2 + 2000 ) + 1000 to Mahesh.
     x/2 - 2000 = x/3 + 7000/3
     x = 26000.

7. The cost price of goods with a bankrupt is Rs. 25500 and if the goods had realised in their full value, his creditiors would have received 85 paise in the rupee. But 2/5 of the goods were sold at 17% and the remainder at 22% below their cost price. How many paise in a rupee was received by the creditors? 

A. 72 paise 
B. 68 paise  
C. 55 paise 
D. 52 paise  
E. None of these

Sol. Total debt = 25500 × 100/85 = Rs.30000
Money received by selling the goods = 25500(2/5 × 83/100 + 3/5 × 78/100)
= 25500/500 (166 + 234)
= 51×400 = Rs.20400
Therefore, money received by the creditors for a rupee = Rs.(20400/30000)=Rs.0.68=68 paise
Hence, the creditor received 68 paise in a rupee.

8. Two trains start at the same time from A and B and proceed towards each other at 80 km/hr and 95 km/hr respectively, when the trains meet, it is found that one has travelled 180 km more than the other. Find the distance between A and B.

A. 210 km
B. 2100 km 
C. 2000 km 
D. 2010 km 
E. None of the above.

Sol. The difference between the distance travelled by A and B after 1 hour = 95 – 80 = 15 km.
 Time taken by the trains to meet each other =180/15 = 12 hr.
 Total distance travelled by both trains in 1 hour = 80 + 95 = 175 km.
 Total distance between A and B = 175 × 12 = 2100 km

9. A train travels at the rate of 50 km/hr without stoppages and it travels at 40 km/hr with stoppages. How many minutes does the train stop on an average per hour?

A. 6 min
B. 12 min 
C. 18 min 
D. 14 min 
E. None of the above

Sol. Train stop for a time which is equal to time taken to travel a distance of 10 km with a speed of  50 km/hr.
because in an hour train travels 10 km less.
Time =10/50×60 = 12 min.

10. If Sohali walks from his home to office at 16 km/hr he is late by 5 min. If he walks at 20 km/hr, he reaches 10 min before the office time. Find the distance of his office from his house.

A. 22 km
B. 20 km 
C. 18 km 
D. 16 km 
E. None of the above

Sol. S1 = 16 km/hr
 S2 = 20 km/hr
 S_1/S_2 =4/5
 T_1/T_2 =5/4
 Time difference = 15 min
 T_1=5×15=75 min
 T_2=4×15=60 min
 Distance = 1 × 20 = 20 km.

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