Dear Aspirants,
We have introduced "the 12 days study plan to crack IBPS SO Exam 2017". This plan is specifically dedicated to Quantitative Aptitude & English Language and cover all types of questions asked in Bank SO exams. This will help you to prepare in a more efficient and systematic way. So, follow this post to keep updated with the plan.
Q1. A swimmer covers a distance of 28 Km against the current and 40 Km in the direction of the current. If in each case he takes 4 hours, then the speed of the current is:
(a) 3.5 Km/h
(b) 1.5 Km/h
(c) 2.5 Km/h
(d) 4.5 Km/h
(e) None of these
Q2. If a man’s rate with the current is 12 Km/h and the rate of the current is 1 (1/2) Km/h, then his rate against the current is:
(a) 13 Km/h
(b) 7 Km/h
(c) 9 Km/h
(d) 10 Km/h
(e) None of these
Q3. A boatman can row 2 Km against the stream in 20 minutes and return in 18 minutes. Find the rate of current.
(a) 1/2 Km/h
(b) 2/3 Km/h
(c) 1/3 Km/h
(d) 1/4 Km/h
(e) None of these
Q4. A boat travels 2 Km upstream in a stream flowing at 3 Km/h and, then returns downstream to the starting point in 30 minutes. The speed of the boat in still water is:
(a) 17 Km/h
(b) 9 Km/h
(c) 13 Km/h
(d) 15 Km/h
(e) None of these
Q5. Twice the speed downstream is equal to the thrice the speed upstream, the ratio of speed in still water to the speed of the current is:
(a) 1 : 5
(b) 5 : 1
(c) 1 : 3
(d) 2 : 3
(e) None of these
Q6. A boatman goes 2 Km against the current of the stream in 1 h and goes 1 Km along the current in 10 min. How long will he take to go 5 Km in stationary water?
(a) 1 hour
(b) 1 hour 15 minutes
(c) 1 1/2 hours
(d) 40 minutes
(e) None of these
Q7. P, Q, R are three towns on a river which flows uniformly. Q is equidistant from P and R. A man rows from P to Q and returns in 10 h. He can row from P to R in 4 h. The ratio of speed of the man in still water to the speed of the current is :
(a) 5 : 3
(b) 3 : 5
(c) 2 : 5
(d) 1 : 2
(e) None of these
Q8. A man can row 30 Km upstream and 44 Km downstream in 10 hours. Also, he can row 40 Km upstream and 55 Km downstream in 13 hours. Find the rate of the current and the speed of the man in still water.
(a) 3 Km/h, 8 Km/h
(b) 3.5 Km/h, 7.5 Km/h
(c) 4.5 Km/h, 6.5 Km/h
(d) 4.5 Km/h, 6.5 Km/h
(e) None of these
Q9. A boat takes 6 hours to travel from place M to N downstream and back from N to M upstream. If the speed of the boat in still water is 4 Km/h, what is the distance between the two places?
(a) 8 Km
(b) 12 Km
(c) 6 Km
(d) Date inadequate
(e) None of these
Q10. A person can swim at 7 (1/2) Km/h in stagnant water. In a river with 1.5 Km/h current, the person swims to a certain distance and comes back within 50 min. What is the distance between the two points?
(a) 3 Km
(b) 4 Km
(c) 1 Km
(d) 2 Km
(e) None of these
Q11. A motor car does a journey in 10 hours, the first half at 21 km per hour, and the rest at 24 km per hour. Find the distance.
(a) 224 km
(b) 234 km
(c) 236 km
(d) 240 km
(e) None of these
Q12. A person going from Pondicherry to Ootacamond travels 120 km by steamer, 450 km by rail and 60 km by horse transit. The journey occupies 13 hours 30 minutes, and the rate of the train is three times that of the horse transit and 1 1/2 times that of the steamer. Find the rate of the train.
(a) 30 km/hr
(b) 60 km/hr
(c) 80 km/hr
(d) 90 km/hr
(e) None of these
Q13. How many seconds will a train 60 m in length, travelling at the rate of 42 km an hour, rate to pass another train 84 m long, proceeding in the same direction at the rate of 30 km an hour?
(a) 42
(b) 43.2
(c) 45
(d) 50
(e) None of these
Q14. A train 75 metres long overtook a person who was walking at the rate of 6 km an hour, and passed him in 7(1/2) seconds. Subsequently it overtook a second person, and passed him in 6 (3/4) seconds. At what rate was the second person travelling?
(a) 2 km/h
(b) 3 km/h
(c) 5 km/h
(d) 6 km/h
(e) None of these
Q15. A train takes 5 seconds to pass an electric pole. If the length of the train is 120 metres, the time taken by it to cross a railway platform 180 metres long is _______ seconds.
(a) 12.5
(b) 13.5
(c) 14.5
(d) 15.5
(e) None of these
Q16. The ratio between the speed of a train and a car is 16 : 15 respectively. Also, a bus covered a distance of 480 km in 8 h. The speed of the bus is three-fourth the speed of the train. How much distance will the car cover in 6 h?
(a) 450 km
(b) 480 km
(c) 360 km
(d) Cannot be determined
(e) None of these
Q17. Car A runs at the speed of 65 km/h and reaches its destination in 8h. Car B runs at the speed of 70 km/h and reaches its destination in 4h. What is the respective ratio of distances covered by Car A and Car B?
(a) 11 : 7
(b) 7 : 13
(c) 13 : 7
(d) 7 : 11
(e) None of these
Q18. A bus started its journey from Ramgarh and reached Devgarh in 44 min with its average speed of 50 km/hr. If the average speed of the bus is increased by 5 km/hr, how much time will it take to cover the same distance?
(a) 40 min
(b) 38 min
(c) 36 min
(d) 31 min
(e) 49 min
Q19. The wheel of an engine 4 (2/7) metres in circumference makes seven revolutions in 4 seconds. Find the speed of the train in km per hour.
(a) 27
(b) 30
(c) 33
(d) 36
(e) None of these
Q20. A man takes 6 hrs 30 min in walking to a certain place and riding back. He would have gained 2 hrs 10 min by riding both ways. How long would he take to walk both ways?
(a) 8 hr 30 min
(b) 8 hr 40 min
(c) 8 hr 50 min
(d) 9 hr
(e) None of these
ANSWERS :
S15. Ans(a)
Sol. Speed of the train = 120/5 = 24 m/s
time taken by the train to pass the platform
=(120+180)/24=12.5 seconds
S16. Ans.(a)
Sol. Speed of bus = 480/8 = 60km/ h
Speed of train = (60*4)/3=80 km / h
Speed of train : Speed of car = 16 : 15
Speed of car =80/16 * 15 = 75 km/ h
Distance covered by car in 6 hr = 75 × 6 = 450 km
S17. Ans.(c)
Sol. Distance travelled by Car A = 65 × 8 = 520 km
Distance travelled by Car B = 70 × 4 = 280 km
Ratio = 520/280 = 13 : 7
S18. Ans.(a)
Sol. Distance between Ramgarh and Devgarh =(50*44)/60=110/3
Average speed of the bus is increased by 5 km/hr then the
speed of the bus = 55 km/hr
Required time = 110/3*60/55 = 40 min
S19. Ans(a)
Sol. Distance covered in 4 seconds =30/7*7 metres
Speed in m/s = 30/4
Speed in km/hr = 30/4*18/5= 27 km/hr
S20. Ans.(b)
Sol. Walking + Riding = 6 hrs 30 min ……(1)
2 Riding = 6 hrs 30 min – 2 hrs 10 min
= 4 hrs 20 min ……(2)
Solving the above two relations (equations);
2 × (1) – (2) gives
2 walking = 13 hrs – 4 hrs 20 min = 8 hrs 40 minutes
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