RBI Assistant Prelims 2016-17 (Important Questions-2)

RBI Assistant Prelims 2016-17 (Important Questions-2)

Directions (1 -5): What will come in place of (_) in the following number series ?

1. 55, 111, 221, _, 885, 1771

A. 441
B. 443
C. 442
D. 444
E. None of these

Sol. 55 + (55+1) = 111
    111 + (111-1)= 221
    221 + (221+1)= 443
    443 + (443-1)= 885
    885 + (885+1)= 1771.

2. -17, -5, 27, 99, 251, _

A. 533
B. 563
C. 555
D. 540
E. None of these

Sol. -5 -(-17) = 12
     27 -(-5) = 32
     99 - 27 = 72
    251 - 99 = 152
    563 - 251= 312

     32 - 12 = 20
     72 - 32 = 40
    152 - 72 = 80
    312 - 152= 160.

3. 16807, _, 686, 294, 168, 120

A. 2400
B. 2401
C. 2404
D. 2403
E. None of these

Sol. 16807*(1/7) = 2401
      2401*(2/7) = 686
       686*(3/7) = 294
       294*(4/7) = 168
       168*(5/7) = 120.

4. 4296, 4234, _, 4050, 3928, 3786

A. 4165
B. 4152
C. 4142
D. 4184
E. None of these

Sol. 4296 - 4234 = 62
     4234 - 4152 = 82
     4152 - 4050 = 102
     4050 - 3928 = 122
     3928 - 3786 = 142.

5. 156, 151, _, 126, 106

A. 138
B. 135
C. 132
D. 141
E. None of these

Sol. 156 - 151 = 5
     151 - 141 = 10
     141 - 126 = 15
     126 - 106 = 20.
     
6. A piece of wire 72 cm long is bent successively in the shape of an equilateral triangle and a square. What is the difference between the areas of both ?

A. 235.3
B. 74.58
C. 326.6
D. 65.58
E. None of these

Sol. Length of wire = Perimeter of equilateral triangle = side*3 = 72
Side of equilateral triangle = 72/3 = 24 cm.

Length of wire = Perimeter of square = side*4 = 72
Side of square = 72/4 = 18 cm.

Area of equilateral triangle = [(24^2)*(3)^0.5]/4 = 249.42
Area of square = (18)^2 = 324
Required difference = 324 - 249.4 = 74.58.

7. There are 4 numbers. Average of first 3 numbers is 17 and of last 3 is 20. If the last number is 21, find the first number ?

A. 16
B. 15
C. 17
D. 18
E. 12

Sol. Lets assume th numbers to be a, b, c and 21.
According to the question,

(a+b+c)/3 = 17
a+b+c = 51

(b+c+21)/3 = 20
b+c = 39.

Thus, a + 39 = 51
a = 51 - 39 = 12.

8. The sum of a 2-digit is 13. When 27 is added to the number , the digits of the number are reversed. What is the actual number ?  

A. 57
B. 58
C. 98
D. 60
E. None of these

Sol. Lets assume ten's digit be 'x' and unit's digit be (13 - x)
Then number = 10x + (13-x) = 9x + 13
Digit with reversed digits = 10(13-x) + x = 130 - 9x

According to the question,
9x + 13 + 27 = 130 - 9x
x = 5.
Therefore, the required number = 9*5 + 13 = 58.

9. The breadth of the rectangular park is 3/4th of its length. If the area of the park is 1200 sq.m. then the difference between its length and breadth is ?

A. 3
B. 10
C. 5
D. 15
E. 20

Sol. Let the length be 'l'
Then breadth will be '3l/4'

According to the question, 
l*3l/4 = 1200
Thus, l = 40.
Length = 40
Breadth = 3*40/4 = 30

Therefore, required difference = 40 - 30 = 10.

10. The population of a town 2 years ago was 245000. It increased by 15% in first year and increased 20% in second year. What is the current population of the town ?

A. 338100
B. 274400
C. 351560
D. 294400
E. None of these

Sol. Population after 1st year = 115*245000/100 = 281750

Population after 2nd year = 120*281750/100 = 338100.  

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IBPS Clerk Mains 2016-17 (Important Questions-2)

IBPS Clerk Mains 2016-17 (Important Questions-2)

Directions (1-5): Find out the wrong number in the given series:

1. 23, 30, 50, 153, 616, 3085

A. 30
B. 50
C. 153
D. 616
E. None of these

Sol. 30
*1 + 1, *2 + 2, *3 + 3,

2. 5, 9, 19, 37, 75, 150, 299

A. 9
B. 75
C. 150
D. 299
E. None of these

Sol. 150
*2 – 1, *2 + 1, *2 – 1, *2 + 1,

3. 6, 11, 18, 32, 42, 61

A. 6
B. 11
C. 32
D. 61
E. None of these

Sol. 32
Difference of difference series

4. 152, 310, 912, 3648, 18240

A. 152
B. 310
C. 912
D. 3648
E. None of these

Sol. 310
*2, *3, *4, *5,

5. 101, 122, 148, 170, 197, 226, 257

A. 122
B. 148
C. 197
D. 226
E. None of these

Sol. 148
10^2 + 1, 11^2 + 1, 12^2 + 1, 13^2 + 1,

6. If a company sells a car with a marked price of Rs. 2,72,000 and gives a discount of 4% on Rs. 2,00,000 and 2.5% on the remaining amount of Rs. 72,000, then the actual price charged by the company for the car is:

A. Rs. 2,50,000 
B. Rs. 2,55,000
C. Rs. 2,60,100
D. Rs. 2,62,200
E. None of these

Sol. M.P. = Rs. 272000.
Discount = Rs. [(4% of 200000) + (2.5% of 72000)] = Rs. (8000 + 1800) = Rs. 9800.
Actual price = Rs. (272000 – 9800) = Rs. 262200.

7. The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?

A. 4 years
B. 8 years
C. 10 years
D. 6 years
E. None of these

Sol. Let the ages of the children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.

8. An amount of Rs. 2430 is divided among A, B and C such that if their shares be reduced by Rs. 5, Rs. 10 and Rs. 15 respectively, the remainders shall be in the ratio of 3 : 4 : 5. Then, B’s share was:

A. Rs. 605
B. Rs. 790
C. Rs. 800
D. Rs. 810
E. None of these

Sol. Remainder = Rs [2430 - (5+10+15)] = Rs 2400.
B's share = Rs[(2400*4/12) + 10] = Rs 810.

9. If inflation increases at a rate of 8% p.a., what will a Rs. 20 article cost at the end of two years?

A. Between Rs. 20 and Rs. 21
B. Between Rs. 21 and Rs. 22
C. Between Rs. 22 and Rs. 23
D. Between Rs. 23 and Rs. 24
E. None of these

Sol. Cost after 2 years = Rs[20*(1 + 8/100)^2]
= Rs(20*27*27)/(25*25) = Rs 23.33

10. A man travels 600 km by train at 80 km/hr, 800 km by ship at 40 km/hr, 500 km by aeroplane at 400 km/hr and 100 km by car at 50 km/hr. What is the average speed for the entire distance?

A. 60 km/hr
B. 605/123 km/hr
C. 62 km/hr
D. 655/123 km/hr
E. None of these

Sol. Total distance travelled = (600+800+500+100) = 2000 km.
Total time taken = (600/80 + 800/40 + 500/400 + 100/50) = 123/4 hrs.
Average speed = (2000*4/123) = 8000/123 km/hr.

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IBPS RRB Mains 2016-17 (Important Questions-2)

IBPS RRB Mains 2016-17 (Important Questions-2)

1. The area of a rectangle is 336 square centimeter. Breadth of the rectangle is four times the radius of a circle. If the perimeter of the rectangle is 80 cm, then the radius of the circle is ?

A. 5 cm
B. 4 cm
C. 3 cm
D. 2 cm
E. None of these

Sol. Lets assume the length to be 'l'
And breadth to be 'b'.

According to the question,

l*b = 336

and

2(l+b) = 80

Solving , b = 12 cm

Thus, radius of the circle = b/4 = 12/4 = 3cm.

2. Three dices are rolled simultaneously then find the probability that none of them have all same numbers ?

A. 35/36
B. 1/36
C. 5/36
D. 1/216
E. None of these

Sol. Total number of cases = 6*6*6 = 216
No. of cases where all have same numbers = 6
Number of favorable cases = (216 - 6) = 210

Thus, required probability = 210/216 = 35/36.

3. A can do a piece of work in 10 days and B can do the same work in 15 days. They work together for 3 days then B left. Find in how many days A finish the remaining work ?

A. 4 
B. 3
C. 5
D. 6
E. None of these

Sol. In 1 day working together they finish, 1/10 + 1/15 = 1/6th work.
In 3 days they will finish, = 1*3/6 = 1/2th work
Work remaining, to be done by A alone is  = 1/2th work

A finihes the whole work in = 10 days
Thus, A will finish 1/2th work in = 10/2 = 5 days.

4. An item was sold for Rss 2750. But if it was sold for 10% less, it would still made 10% profit. What is the cost price of the item ?

A. 2250
B. 2350
C. 2450
D. 2150
E. None of these

Sol. 10% 0f 2750 = Rs 275
Selling Price = 2750 - 275 = Rs 2475

Cost price = (2475*100)/(100+10) = Rs 2250.

5. In an exam, 10% boys and 10% girls passed. Number of boys is 100 and number of girls is 90. What is the percentage of candidates passed ?

A. 90
B. 80
C. 10
D. 20
E. None of these

Sol. No. of boys = 10% of 100 = 10
No. of girls = 10% of 90 = 9

Total candidates passed = 10 + 9 = 19

Percentage Failed = (1 - 19/190)*100 = 90%.

Directions (6-10): What will come in place of (_) in the following number series ?

6. 11, 13, 17, 19, 23, 29, _

A. 31
B. 37
C. 33
D. 34
E. None of these

Sol. All are prime numbers. Next prime is 31.

7. 3, 7, 15, 31, 63, _

A. 125
B. 123
C. 127
D. 129
E. None of these

Sol. 3*2 + 1 = 7
     7*2 + 1 = 15
    15*2 + 1 = 31
    31*2 + 1 = 63
    63*2 + 1 = 127.

8. 12, 36, 18, 54, 27, _

A. 81
B. 80
C. 87
D. 82
E. None of these

Sol. 12*3 = 36
     36/2 = 18
     18*3 = 54
     54/2 = 27
     27*3 = 81.

9. 9, 28, 65, 126, 217, _

A. 344
B. 354
C. 364
D. 374
E. None of these

Sol. 2^3 + 1 = 9
     3^3 + 1 = 28
     4^3 + 1 = 65
     5^3 + 1 = 126
     6^3 + 1 = 217
     7^3 + 1 = 344

10. 6, 18, 72, 360, 2160, _

A. 15120
B. 14250
C. 16540
D. 18750
E. None of these

Sol. 3*2 = 6
     6*3 = 18
    18*4 = 72
    72*5 = 360
   360*6 = 2160
  2160*7 = 15120. 

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RBI Assistant Prelims 2016-17 (Important Questions)

RBI Assistant Prelims 2016-17 (Important Questions)

Directions (1-5): What will come in place of (_) in the following number series ?

1. 5, 8, 17, 32, 53, _

A. 80
B. 76
C. 75
D. 85
E. None of these

Sol. 5 + 3 = 8
     8 + 9 = 17
    17 + 15= 32
    32 + 21= 53
    53 + 27= 80

2. 7, 8, 12, 21, 37, _

A. 62
B. 64
C. 65
D. 68
E. None of these

Sol. 7 + 1^2 = 8
     8 + 2^2 = 12
    12 + 3^2 = 21
    21 + 4^2 = 37
    37 + 5^2 = 62

3. 10, 12, 15, 19, 24, _

A. 30
B. 32
C. 35
D. 36
E. None of these

Sol. 10 + 2 = 12
     12 + 3 = 15
     15 + 4 = 19
     19 + 5 = 24
     24 + 6 = 30

4. 18, 16, 22, 10, 30, _

A. 8
B. 4
C. 3
D. 0
E. None of these

Sol. 18 - 1*2 = 16
     16 + 2*3 = 22
     22 - 3*4 = 10
     10 + 4*5 = 30
     30 - 5*6 = 0.

5. 82, 42, 22, 12, 7, _

A. 3
B. 3.5
C. 4
D. 4.5
E. None of these

Sol. 82/2 + 1 = 42
     42/2 + 1 = 22
     22/2 + 1 = 12
     12/2 + 1 = 7
      7/2 + 1 = 4.5

Directions (6-10): What will come in place of question mark(?) in the following number series ?

6. (9 ÷ 2 * 27 ÷ 9)/(18 ÷ 7.5 * 5 ÷ 4) = ?

A. 3.5
B. 4.5
C. 5.5
D. 6.5
E. None of these 

Sol. (9 ÷ 2 * 27 ÷ 9)/(18 ÷ 7.5 * 5 ÷ 4)
4.5 * 3 = 13.5
2.4*1.25 = 3
13.5/3 = 4.5

7. (986/34) ÷ (65/845) * (675/225) = ? 

A. 1121
B. 1131
C. 1141
D. 1151
E. None of these

Sol. 29 * 13 * 3 = 1131.

8. 634.696 + 71.472 – 396.708 = ? + 28.271

A. 281.189
B. 342.246
C. 323.578
D. 287.426
E. None of these

Sol. = 634.696 + 71.472 – 396.708 – 28.271
= 281.189.

9. (30% of 260) + (60% of 510) – 103 = ?

A. 211
B. 238
C. 281
D. 278
E. None of these

Sol. = 30% of 260 + 60% of 510 – 103
= 384 – 103
= 281.

10. (6438 – 3874 – 664) ÷ (769 – 506 – 63) = ?

A. 8.5
B. 7.5
C. 9.5
D. 4.5
E. None of these


Sol. 6438 – 3874 – 664 = 1900 ; 769 – 506 – 63 = 200; 1900 ÷ 200 = 9.5 

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IBPS Clerk Mains 2016-17 (Important Questions)

IBPS Clerk Mains 2016-17 (Important Questions)

1. Two trains start at the same time from A and B and proceed towards each other at 80 km/hr and 95 km/hr respectively, when the trains meet, it is found that one has travelled 180 km more than the other. Find the distance between A and B.

A. 210 km
B. 2100 km 
C. 2000 km 
D. 2010 km 
E. None of the above

Sol. The difference between the distance travelled by A and B after 1 hour = 95 – 80 = 15 km.
 Time taken by the trains to meet each other =180/15 = 12 hr.
 Total distance travelled by both trains in 1 hour = 80 + 95 = 175 km.
 Total distance between A and B = 175 × 12 = 2100 km.

2.  If Sohali walks from his home to office at 16 km/hr he is late by 5 min. If he walks at 20 km/hr, he reaches 10 min before the office time. Find the distance of his office from his house.

A. 22 km
B. 20 km 
C. 18 km 
D. 16 km 
E. None of the above

Sol. S1 = 16 km/hr
 S2 = 20 km/hr
 S_1/S_2 = 4/5
 T_1/T_2 = 5/4
 Time difference = 15 min
 T_1= 5×15 = 75 min
 T_2 = 4×15 = 60 min
Distance = 1 × 20 = 20 km.

3. A is twice as fast as B and B is thrice as fast as C. The journey covered by C in 42 minutes will be covered by A in

A. 7 minutes
B. 14 minutes
C. 28 minutes
D. 63 minutes
E. None of these

Sol. Let C’s speed by x metres/min
Then, B’s speed = 3x metres/min and A’s speed = 6x metres/min.
Ratio of speeds of A and C = Ratio of times taken by C and A.
6x : x = 42 : y min
 6x/x=42/y
 y = 42/6 min = 7 min.

4. A train leaves a station A at 7 am and reaches another station B at 11 am. Another train leaves B at 8 am and reaches A at 11.30. The two trains cross one another at

A. 8.36 am
B  8.56 am
C. 9.00 am
D. 9.24 am  
E. None of these

Sol. Let both trains meet after t hours since 7 a.m.
Distance between stations A and B = x km
x/4 × t + 2x/7 × (t – 1) = x  (speed=Distance/Time)
t/4+(2(t-1))/7=1
(7t+8t-8)/28=1 15t – 8 = 28
 15t = 28 + 8 = 36
 t = 36/15=12/5 hours
 2 hours 24 minutes
 Required time = 9:24 a.m.

5. In a box, there are 7 red, 8 blue and 6 green balls. One ball is picket up randomly. What is the probability that it neither red nor green?  

A. 2/3
B. 3/4
C. 7/19
D. 8/21
E. 9/21

Sol. Total number of balls = (8 + 7 + 6) = 21
Let E = event that the ball drawn is neither red nor green = event that the ball drawn is blue.
 n(E) = 8
 P(E) = 8/21.

6. There are 4 blue balls, 3 red, and 2 green balls. 2 balls are drawn at random. What is the probability of all red or all green balls ?

A. 1/9
B. 4/9
C. 3/36
D. 1/36
E. None of these

Sol. Probability of all red = 3c2/9c2 = 3/36
     Probability of all green = 2c2/9c2 = 1/36

Required Probability = (3 + 1)/36 = 1/9.

7. On a certain sum of money, simple interest obtained is Rs 200 after 2 years at 10% per annum. What will be the compound interest obtained at the same rate and for the same time ?

A. Rs 220
B. Rs 210
C. Rs 230
D. Rs 200
E. None of these

Sol. Lets assume the sum invested to be 'P'.

According to the question,

200 = (P*10*2)/100
P = Rs 1000.

C.I. = 1000[{1 + (10/100)}^2 - 1] = Rs 210.

8. Deepak borrows Rs.5000 at simple Interest from a lender. At the end of 3 years, she again borrows Rs.2000 and settled that amount after paying Rs.5000 as interest after 8 years from the time she made the first borrowing. What is the rate of interest ?

A. 8%
B. 9%
C. 7%
D. 10%
E. None of these

Sol. SI for Rs.5000 for 8 years= (5000*r*8)/100
Again borrowed=2000
SI = (2000*r*5)/100
Total interest= [(5000*r*8)/100] + [(2000*r*5)/100] = 5000
400r + 100r = 5000
r = 10%.

9. 40 boys and 62 girls form a group for social work. During their membership drive, an equal number of boys and girls also join the group. How many members does the group have now, if the ratio of boys to girls is 2:3 ?

A. 112
B. 110
C. 106
D. 140
E. None of these

Sol. [40 + x / 62 + x ] = 2/3
x = 4
40 + 62 + 4 + 4 = 110.

10. If 8 examiners can examine a certain number of answer books in 12 days by working 5 hours a day, for how many hours a day would 4 examiners have to work in order to examine twice the number of answer books in 20 days ?

A. 16
B. 10
C. 14
D. 12
E. None of these

Sol. x – number of answer books
y – hours
[8 * 12 * 5] / x = [4 * 20 * y] /2x
y = 12. 

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IBPS RRB Mains 2016-17 (Important Questions)

IBPS RRB Mains 2016-17 (Important Questions)

                                                                                                                                                                                                                                                                                                                                                                                                                                                                              

Directions (1-5): What will come in place of (_) in the following number series :

1. 7, 20, 46, 85, _, 202

A. 136

B. 135

C. 137

D. 138

E. 141

Sol. 20 - 7 = 13

       46 - 20 = 26

       85 - 46 = 39

     

   Thus, 85 + 52 = 137.

2. 4, 13, 40, 121, _, 1093

A. 365

B. 364

C. 366

D. 368

E. None of these

Sol. 13 - 4 = 9

     40 - 13= 27

    121 - 40= 81

  

Thus, 121 + 243 = 364.

3. 17, 18, 14, 23, 7, _

A. 30

B. 32

C. 33

D. 36

E. 39

Sol. 18 - 17 = 1

     14 - 18 =-4

     23 - 14 = 9

      7 - 23 =-16

Thus, 7 + 25 = 32.

4. 2180, 2179, 2152, 2027, _

A. 1780

B. 1684

C. 1500

D. 1980

E. None of these

Sol. 2179 - 2180 =-1

     2152 - 2179 =-27

     2027 - 2152 =-125

Thus, 2027 - 343 = 1684.

5. 6, 10, 19, 32, 48, _

A. 64

B. 65

C. 66

D. 67

E. 68

Sol. 10 - 6 = 4

     19 - 10= 9

     32 - 19= 13

     48 - 32= 16

     9 - 4 = 5

    13 - 9 = 4

    16 - 13= 3

Thus, 16 + 2 = 18

Therefore, 48 + 18 = 66.

6. 5 years ago the age of A was one-third the age of B, and sum of their present ages is 70. Then find the age of A, 5 years after ?

A. 15

B. 20

C. 25

D. 30

E. None of these

Sol. Lets assume B's age 5 years ago be 'x'

Then A's age 5 years ago was x/3

According to the question, 

x + 5 + x/3 + 5 = 70

Solving, x = 45

Thus, A's present age = 45/3 + 5 = 20

A's age 5 years after = 20 + 5 = 25 years. 

7. If 40% of X is added to Y, the resultant is one-fifth more than Y. Calculate ratio X:Y ?

A. 2:3

B. 1:2

C. 3:4

D. 1:4

E. 1:5

Sol. According to the question, 

0.4X + Y = Y + Y/5

Solving, X/Y = 1/2

Thus, X:Y = 1:2.

8. Shiya's income is 25% more than Aman, and if each save 1/3 of their incomes, and total of their savings is Rs 11000. What is the difference in their incomes ?

A. 3500

B. 3666.67

C. 4666.67

D. 4500

E. None of these

Sol. Lets assume Aman's income be 'x'

Then, Shiya's income is 1.25x

According to the question,

1.25x/3 + x/3 = 11000

Solving, x = 14666.67

Difference in incomes = 0.25*14666.67 = Rs 3666.67 

9. In a lab, two chemical solutions Sulphuric Acid with 94% purity and Hydrochloric Acid with 96% purity are mixed resulting in 24 litres of mixture of 95% purity. How much is the quantity of the Sulphuric Acid in the resulting mixture ?

A. 12

B. 21

C. 20

D. 16

E. 18

Sol. 94x + (24 – x)* 96 = 24 * 95

2x = 24

x = 12.

10. A basket contains 5 red 4 blue 3 green balls. If three balls picked up random, What is the probability that at least one ball is blue ?

A. 41/55

B. 53/55

C. 47/55

D. 49/55

E. 31/55

Sol. Total Balls = 12

Other than blue = 8c3/12c3 = 14/55

Probability = 1-14/55 = 41/55.

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IBPS Clerk Prelims 2016-17 (Important Questions - 5)

As some shifts have already completed of IBPS Clerk Prelims 2016-17.  We now have a better understanding of the questions asked in IBPS Clerk Prelims exam. 

So, for our students we have prepared a set of questions containing some of the asked questions in  IBPS Clerk Prelims 2016-17 and some based on their types.
Solving this will get you a better understanding of the questions asked in IBPS Clerk Prelims, if you still have not given your IBPS Clerk Prelims paper. 

These sets will be posted daily for all those students who have yet to give their IBPS Clerk Prelims exam, and get them ready to face the exam with confidence.

Directions (1-5): What will come in place of question mark (?) in the following number series ?

1. 3, 8, 21, 88, ?, 2616

A. 440

B. 435

C. 445

D. 450

E. None of these

Sol. 3*2 + 2 = 8

     8*3 - 3 = 21

    21*4 + 4 = 88

    88*5 - 5 = 435

   435*6 + 6 = 2616

2. 48, 28, 30, 61, 244.5, ?

A. 1956.25

B. 2000

C. 1885.25

D. 1756.5

E. None of these

Sol. 48*0.5 + 4 = 28

     28*1.0 + 2 = 30

     30*2.0 + 1 = 61

     61*4.0 + 0.5=244.5

  244.5*8.0 +0.25=1956.25

3. 16, 20, 4, 40, ?, 76

A. 8

B. 0

C. 4

D. 2

E. None of these

Sol. 16 + 2^2 = 20

     20 - 4^2 = 4

      4 + 6^2 = 40

     40 - 8^2 =-24

    -24 + 10^2= 76

4. 6, 10, 17, 30, 52, ?

A. 112

B. 86

C. 99

D. 124

E. None of these

Sol. Difference of difference.

5. 1, 3, 10, 38, 168, ?

A. 872

B. 802

C. 868

D. 854

E. None of these

Sol. 1*1 + 2 = 3

     3*2 + 4 = 10

    10*3 + 8 = 38

    38*4 + 16= 168

   168*5 + 32= 872

Directions (6-10) : What should come in place of question mark (?) in the following questions ?

6. 56% of 225 + 20% of 150 = ? – 109 

A. 49

B. 103

C. 53

D. 47

E. None of these

Sol. Sol. ? = 126 + 30 + 109 = 265

7. 12% of 1885 = ? ÷ 6

A. 1248.4

B. 1292.2

C. 1312.6

D. 1357.2

E. None of these

Sol. Sol. ? = 226.2 × 6 = 1357.2

8. (854×854×854−276×276×276)/(854×854+854×276+276×276) = ?

A. 1130

B. 578

C. 565

D. 1156

E. None of these

Sol. ? = [(854)^3− (276)^3]/[(854)^2 + (854×276) + (276)^2]

= 854 – 276

= 578.

9. 7(1/17) × 3485 + 9(1/18) × 2430 = ?

A. 23354

B. 53345

C. 46605

D. 43345

E. None of these

Sol. 120/17(3485) + 163/18(2430)

     24600+22005 = 46605

10. 44.01-323.66 + 2450.50 = ? + 170.85

A. 2000

B. 1240

C. 1670

D. 2460

E. None of these

Sol. 2494.51-323.66 = 2170.85

11. Twenty-four men can complete a work in 18 days and twenty women can complete the same work in 16 days. Thirty-six men started the work and left after 3 days. Now ten women started the work and left after 4 days. What amount of left is completed by now ?

A. 5/8

B. 2/7

C. 3/8

D. 1/4

E. None of these

Sol. 24m in 18 days, so 36 in 24*18/36 = 12 days

In 3 days, they did 1/12 * 3 = 1/4 work

20w in 16 days, so 10 in 20*16/10 = 32 days

In 4 days, they did 1/32 * 4 = 1/8 work

So completed work = 1/4 + 1/8 = 3/8.

12. A box contains 150 tickets (numbered 1 to 150). Find the probability of drawing a ticket containing a multiple of 3 or 6.

A. 1/3

B. 2/3

C. 43/150

D. 31/150

E. None of these

Sol. Required Probability = 50/150 = 1/3.

13. An article is marked 25% above the cost price and it gets a 10% discount also. Find the profit percent if the seller cheats while selling by using 10% less weight ?

A. 23%

B. 22%

C. 20%

D. 25%

E. None of these

Sol. Let CP = 100

So MP = 125

So SP after discount = 90/100 * 125 = 112.5

Now seller selling 10% less in weight so CP = Rs 90

Now CP = 90, SP = 112.5

So profit % = 22.5/90 * 100 = 25%.

14. X and Y started a business with investments Rs 1800 and Rs 2400 respectively. After 6 months, Z also joined them with investment of Rs 4000. If after a year a total of Rs 42,000 is earned as profit, what is the share of Z ?

A. 25,500

B. 23,000

C. 20,000

D. 28,000

E. None of these

Sol. X : Y : Z

1800*12 : 2400*12 : 4000*6

9 : 12 : 10

10/(9+12+10) * 42,000 = 13548.

15. A rectangular box has length, breadth and height in the ratio 7 : 2 : 7. These are respectively increased by 20%, 5% and 50%. What is the percentage increase in volume of rectangular box ?

A. 89%

B. 85%

C. 90%

D. 96%

E. None of these

Sol. 7x, 2x and 7x, so volume = 98.

Now when increase is done, ratio is

(120/100)*7x , (105/100)*2x , (150/100)*7x

New volume = 185.22

% increase = (185.22-98)/98 * 100 = 89%.

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IBPS Clerk Prelims 2016-17 (Important Questions - 4)

As some shifts have already completed of IBPS Clerk Prelims 2016-17.  We now have a better understanding of the questions asked in IBPS Clerk Prelims exam. 

So, for our students we have prepared a set of questions containing some of the asked questions in  IBPS Clerk Prelims 2016-17 and some based on their types.
Solving this will get you a better understanding of the questions asked in IBPS Clerk Prelims, if you still have not given your IBPS Clerk Prelims paper. 

These sets will be posted daily for all those students who have yet to give their IBPS Clerk Prelims exam, and get them ready to face the exam with confidence.

1. X’s present age is 1/3 of Y’s and Y’s present age is 9/13 of Z’s present age. The sum of their present ages is 125 years. What is the sum of ages of Y and X ?

A. 45
B. 40
C. 50
D. 60
E. None of these

Sol. Y = 9Z/13 and X = 1/3(9Z/13) = 3Z/13
So 3Z/13 + 9Z/13 + Z = 125
Solve, Z = 65,
so X = 3*65/13 = 15
Y is then 9*65/13 = 45
So X+Y = 15+45 = 60

2. Two varieties of wheat at Rs 42 per kg and Rs 50 per kg respectively are mixed in the ratio 5 : 3. The mixture is then sold at Rs 36 per kg. What is the loss % ?

A. 33%
B. 25%
C. 20%
D. 16%
E. None of these

Sol. Let CP of mixture is x
By method of allegation:
A……………….B
42………………50
. …………x
(50-x) (x-42)
Then, (50-x)/(x-42) = 5/3
Solve, x = 45 = CP
SP = 36
So loss% = [(45-36)/45] * 100

3. X can complete 4/5th of a piece of work in 12 days and Y can complete 1/3rd of the same work in 9 days. If both X and Y work together, they can do 7/15th of that work in how many days ?

A. 4.5
B. 5
C. 9
D. 8
E. None of these

Sol. X can do 4/5th of the work in 12 days, so whole work in 5/4 * 12 = 15 days.
Y can do 1/3th of the work in 9 days, so whole work in 3/1 * 9 = 27 days.
X and Y together can complete whole work in 15*27/(15+27) = 15*9/14 days.
So 7/15th work in 7/15 * (15*9/14) = 9/2 days.

4. Rs 310 are to be divided among X, Y and Z in the ratio 1/2 : 1/3 : 1/5, but by mistake it was divided in the ratio of 2 : 3 : 5 among them respectively. How much did X lost in this transaction ?

A. 85
B. 75
C. 20
D. 62
E. 88

Sol. Ratio in which divided = 2 : 3 : 5
Actual ratio = 1/2 : 1/3 : 1/5 or 15 : 10 : 6
Both ratios show that X and Y have lost and Z has gained the most.
X got = 2/(2+3+5) * 310 = 62
Actually X would have got = 15/(15+10+6) * 310 = 150
So X lost 150 – 62 = 88. 

5. The train goes from station X to Y and back to station X in 32 hours where total distance covered by train is 1800 km. The train halted for two hours after reaching station Y. If the average speed of train from X to Y is 20% more than that from B to A, what is the speed of train from X to Y station ?

A. 72 km/hr
B. 75 km/hr
C. 66 km/hr
D. 60 km/hr
E. None of these

Sol. Total distance is 1800
So 900 from X to Y and then 900 from Y to X
Let speed in return journey is a, then in X to Y is (120/100)*a = 6a/5
So 900/a + 900/(6a/5) = 30
Solve, a = 55
So from X to Y is 6*55/5 = 66 km/hr.

Directions (6-10) : What should come in place of question mark (?) in the following questions ?

6. 3251+ 587 + 369 – ? = 3007

A. 1250
B. 1300
C. 1375
D. 1400
E. None of these

Sol. ? = 4207 – 3007 = 1200.

7. (9261)^1/3 × (62742241)^1/2 = ? +89

A. 166254
B. 166259
C. 166253
D. 166252
E. None of these

Sol. ? = 21 × 7921 – 89 = 166252.

8. 18.6 × 3 + 7.2 – 16.5 = ? + 21.7

A. 35.7
B. 21.6
C. 24.8
D. 27.6
E. None of these

Sol. ? = 55.8 + 7.2 – 38.2 = 24.8

9. 5.35 + 4.43 + 0.45 + 45.34 + 534 = ?

A. 597.27
B. 589.57
C. 596.87
D. 596.67
E. None of these

Sol.? = 589.57

10. 0.5% of 674 of 0.8% of 225 = ?

A. 7.066
B. 9.12
C. 6.066
D. 5.17
E. None of these

Sol. ? = (0.5/100)×674×(0.8/100)×225 = 6.066


Directions (11-15):What will come in the place of the question mark (_) in the following number series ?

11. 3, 5, 10, 20, _, 63

A. 37
B. 36
C. 35
D. 34
E. None of these

Sol. 5 - 3 = 2
    10 - 5 = 5
    20 - 10= 10
    37 - 20= 17
    63 - 37= 26

     5 - 2 = 3
    10 - 5 = 5
    17 - 10= 7
    26 - 17= 9

12. 7, 8, 18, 57, 232, _

A. 1160
B. 1162
C. 1165
D. 1169
E. None of these

Sol. 7*1 + 1 = 8
     8*2 + 2 = 18
    18*3 + 3 = 57
    57*4 + 4 = 232
   232*5 + 5 = 1165

13. 43, 46, 54, 67, 85, _

A. 106
B. 107
C. 108
D. 109
E. None of these

Sol. 46 - 43 = 3
     54 - 46 = 8
     67 - 54 = 13
     85 - 67 = 18
     
Thus, 85 + 23 = 108

14. 8, 4, 4, 8, 32, _

A. 256
B. 144
C. 196
D. 244
E. None of these

Sol. 8*0.5 = 4
     4*1.0 = 4
     4*2.0 = 8
     8*4.0 = 32
    32*8.0 = 256

15. 13, 16, 22, 34, _, 106

A. 56
B. 48
C. 58
D. 62
E. None of these

Sol. 16 - 13 = 3
     22 - 16 = 6
     34 - 22 = 12
     58 - 34 = 24

    106 - 58 = 48   

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